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# ![@diwa810 Avatar](https://lunarcrush.com/gi/w:26/cr:twitter::1911028026323738624.png) @diwa810 Diwakar Upadhyay

Diwakar Upadhyay posts on X about  the most. They currently have XX followers and XX posts still getting attention that total X engagements in the last XX hours.

### Engagements: X [#](/creator/twitter::1911028026323738624/interactions)
![Engagements Line Chart](https://lunarcrush.com/gi/w:600/cr:twitter::1911028026323738624/c:line/m:interactions.svg)

- X Week XXX +61%
- X Month XXX +1,380%

### Mentions: X [#](/creator/twitter::1911028026323738624/posts_active)
![Mentions Line Chart](https://lunarcrush.com/gi/w:600/cr:twitter::1911028026323738624/c:line/m:posts_active.svg)

- X Week X +100%
- X Month XX +333%

### Followers: XX [#](/creator/twitter::1911028026323738624/followers)
![Followers Line Chart](https://lunarcrush.com/gi/w:600/cr:twitter::1911028026323738624/c:line/m:followers.svg)

- X Week XX +23%
- X Month XX +233%

### CreatorRank: undefined [#](/creator/twitter::1911028026323738624/influencer_rank)
![CreatorRank Line Chart](https://lunarcrush.com/gi/w:600/cr:twitter::1911028026323738624/c:line/m:influencer_rank.svg)

### Social Influence [#](/creator/twitter::1911028026323738624/influence)
---
### Top Social Posts [#](/creator/twitter::1911028026323738624/posts)
---
Top posts by engagements in the last XX hours

"@PythagoraAI Yes bro DFS is more optimized here since it's a BST if the current node value is smaller than L we dont need to traverse its left subtree and similarly if its greater than r we can skip the right subtree"  
[X Link](https://x.com/diwa810/status/1978916643695686032) [@diwa810](/creator/x/diwa810) 2025-10-16T20:11Z XX followers, XX engagements


"Day XX of #100DaysOfCodeSolved the POTD on #GFG Remove BST keys outside given range Approach Used #DFS traversal in postorder (left right root) For each node checked if its value lies within the range based on that returned the appropriate left or right child #DSA #LeetCode"  
[X Link](https://x.com/diwa810/status/1978918198570295480) [@diwa810](/creator/x/diwa810) 2025-10-16T20:17Z XX followers, XX engagements


"Day XX of #100DaysOfCode Solvde potd on #gfg Median of BST & #LeetCode 3397 X first calculate no of nodes and run the inorder traverse for (total+1)/2 and return that node X sort the array and use the last no i can create from the prev no and acc to that inc the cnt #Coding #DSA"  
[X Link](https://x.com/diwa810/status/1979653976577704186) [@diwa810](/creator/x/diwa810) 2025-10-18T21:01Z XX followers, XX engagements

[GUEST ACCESS MODE: Data is scrambled or limited to provide examples. Make requests using your API key to unlock full data. Check https://lunarcrush.ai/auth for authentication information.]

@diwa810 Avatar @diwa810 Diwakar Upadhyay

Diwakar Upadhyay posts on X about the most. They currently have XX followers and XX posts still getting attention that total X engagements in the last XX hours.

Engagements: X #

Engagements Line Chart

  • X Week XXX +61%
  • X Month XXX +1,380%

Mentions: X #

Mentions Line Chart

  • X Week X +100%
  • X Month XX +333%

Followers: XX #

Followers Line Chart

  • X Week XX +23%
  • X Month XX +233%

CreatorRank: undefined #

CreatorRank Line Chart

Social Influence #


Top Social Posts #


Top posts by engagements in the last XX hours

"@PythagoraAI Yes bro DFS is more optimized here since it's a BST if the current node value is smaller than L we dont need to traverse its left subtree and similarly if its greater than r we can skip the right subtree"
X Link @diwa810 2025-10-16T20:11Z XX followers, XX engagements

"Day XX of #100DaysOfCodeSolved the POTD on #GFG Remove BST keys outside given range Approach Used #DFS traversal in postorder (left right root) For each node checked if its value lies within the range based on that returned the appropriate left or right child #DSA #LeetCode"
X Link @diwa810 2025-10-16T20:17Z XX followers, XX engagements

"Day XX of #100DaysOfCode Solvde potd on #gfg Median of BST & #LeetCode 3397 X first calculate no of nodes and run the inorder traverse for (total+1)/2 and return that node X sort the array and use the last no i can create from the prev no and acc to that inc the cnt #Coding #DSA"
X Link @diwa810 2025-10-18T21:01Z XX followers, XX engagements

creator/x::diwa810
/creator/x::diwa810