#  @abhigargclasses Abhi Garg Classes Abhi Garg Classes posts on YouTube about sector, math, solve, how to the most. They currently have [---] followers and [---] posts still getting attention that total [-----] engagements in the last [--] hours. ### Engagements: [-----] [#](/creator/youtube::UCpb0DUwHL2jtnU7xWGV3xhw/interactions)  - [--] Week [---] +286% - [--] Month [---] -81% - [--] Months [-----] +1,851% ### Mentions: [--] [#](/creator/youtube::UCpb0DUwHL2jtnU7xWGV3xhw/posts_active)  ### Followers: [---] [#](/creator/youtube::UCpb0DUwHL2jtnU7xWGV3xhw/followers)  - [--] Week [---] +1.90% - [--] Month [---] +13% - [--] Months [---] +71% ### CreatorRank: [---------] [#](/creator/youtube::UCpb0DUwHL2jtnU7xWGV3xhw/influencer_rank)  ### Social Influence **Social topic influence** [sector](/topic/sector) #1543, [math](/topic/math), [solve](/topic/solve), [how to](/topic/how-to), [hook](/topic/hook), [complex](/topic/complex) #1430, [this is](/topic/this-is), [tutorial](/topic/tutorial), [the most](/topic/the-most), [can you](/topic/can-you) ### Top Social Posts Top posts by engagements in the last [--] hours "Master AP Sum Trick: Sum of Integers Between [---] and [---] Divisible by [--] Class [--] Maths 🤯 Don't let Arithmetic Progression sums confuse you This classic problem requires two simple steps and we show you exactly how to tackle it. Question: Find the sum of the integers between [---] and [---] that are (i) divisible by [--]. (ii) not divisible by [--]. Concept Explained: We use the AP sum formula S = (n/2)(a + l) and the concept of exclusion (Total Sum - Sum Divisible = Sum Not Divisible) to solve this problem efficiently. Join the best coaching institute Abhi Garg Classes is located in Sector 20" [YouTube Link](https://youtube.com/watch?v=J3KKtlKb25c) 2026-02-15T07:05Z [---] followers, [--] engagements "Viral Geometry Trick: Find Difference in Areas of Overlapping Sectors (R=6 R=8) Cancellation Meth 🔥 Geometry Hack Alert This seemingly complex problem involving overlapping sectors has a surprising simplification trick. Question: Find the difference in the areas of regions I and III given two overlapping sectors with radii [--] cm and [--] cm (assuming they are quadrants). Concept Explanation: We demonstrate the powerful cancellation technique. By setting up simultaneous equations for the areas we show that the common overlapping area (Region II) completely cancels out allowing us to find the" [YouTube Link](https://youtube.com/watch?v=3Y51BYsRxK0) 2026-02-16T05:08Z [---] followers, [--] engagements "Area Related to Circles: Finding Perimeter of Shaded Region with Four Semi-Circles Class [--] Maths 🔥 Don't let complex figures fool you This seemingly tricky geometry problem is a straightforward application of circle perimeter. Question: In the given figure APB and CQD are semi-circles with a diameter of [--] cm each. ARC and BSD are semi-circles with a diameter of [--] cm each. Find the perimeter of the shaded region. Concept Focus: The perimeter of a composite region formed by arcs is the sum of the lengths of the bounding arcs. Remember arc length for a semi-circle is r. Join Abhi Garg Classes" [YouTube Link](https://youtube.com/watch?v=BK7BAkmsV08) 2026-02-14T02:52Z [---] followers, [--] engagements "TRIGONOMETRY PROOF TRICK: Prove (cosec - sec) / (cosec + sec) = 3/4 Class [--] Maths 🔥 Don't let complex trigonometric proofs scare you This is one of the most frequently asked proof questions in CBSE Class [--] Boards. Question: Prove that (cosec - sec) / (cosec + sec) = 3/4 if tan = [--] / [--]. Concept: The key to solving this proof quickly is recognizing the relationship between cosec sec and tan. By dividing the numerator and denominator by cosec we reduce the entire expression to a simple function of tan making substitution straightforward and fast. 📍 Join Abhi Garg Classes for comprehensive" [YouTube Link](https://youtube.com/watch?v=ObmSAP5s950) 2026-02-16T07:50Z [---] followers, [---] engagements "Area of Shaded Region: Square and Two Semicircles NCERT Class [--] Geometry Abhi Garg Classes Stop confusing composite shapes This is one of the most frequently asked questions on Area of Shaded Regions in Class [--] boards. ❓ The Question: Find the area of the shaded region if ABCD is a square of side [--] cm and APD and BPC are semicircles. 💡 Concept Explained: We use the fundamental principle: Area of Shaded Region = Area of Square - Area of Two Semicircles. Pay close attention to calculating the radius from the side length This is perfect practice for Class [--] Boards geometry. 📍 For focused" [YouTube Link](https://youtube.com/watch?v=et1ul3d5om8) 2026-02-15T15:22Z [---] followers, [--] engagements "Area of Shaded Region Class [--] Equilateral Triangle & Major Sector Combo Explained Simply CBSE Hook: Stop confusing composite figures Learn the fastest method to solve this challenging Class [--] Area of Shaded Region problem. Question: Find the area of the shaded region where a circular arc of radius [--] cm has been drawn with vertex O of an equilateral triangle OAB of side [--] cm as the centre. Concept: We break down the figure into two parts: the Area of the Equilateral Triangle (363) and the Area of the Major Sector (30). The key is accurately identifying the [--] angle of the triangle and" [YouTube Link](https://youtube.com/watch?v=VKLpPx3nQO0) 2026-02-15T06:08Z [---] followers, [--] engagements "NCERT Class [--] Area of Shaded Region Problem (7 cm [--] cm) Geometry Simplified 🔥 Geometry Hack Alert This is a super important question from Area Related to Circles that frequently appears in CBSE Class [--] Board Exams. ❓ The Question: Find the area of the shaded region if PQ = [--] cm PR = [--] cm and O is the centre of the circle. 💡 Concept: The key is recognizing that the angle subtended by the diameter (QR) at the circumference is [--]. This immediately allows us to use the Pythagorean theorem to find the diameter and then calculate the required area by subtracting the area of the triangle from" [YouTube Link](https://youtube.com/watch?v=fipaxBu8OKs) 2026-02-15T05:17Z [---] followers, [--] engagements "Area of Shaded Region Concentric Circles (R=14 r=7 =40) Class [--] Maths Chapter [--] 🔥 Quickest way to solve Area Related to Circles problems We tackle the challenge of finding the area of the shaded region between two concentric circles. Question: Find the area of the shaded region if the radii of the two concentric circles are [--] cm and [--] cm and the central angle is [--]. Concept: The solution relies on finding the difference between the areas of the two large and small sectors. A simple factorisation of the sector formula makes the calculation lightning fast: Area = (/360) (R - r). Need" [YouTube Link](https://youtube.com/watch?v=laNXcjC_ddM) 2026-02-15T05:30Z [---] followers, [--] engagements "Area to Distance HACK How Many Revolutions Does a Wheel Make Class [--] Circles Problem Tired of confusing word problems in Circles This short tutorial breaks down the classic 'Number of Revolutions' calculation easily We show you how to link Area Circumference and Total Distance. Question: Find the number of revolutions made by a circular wheel of area [----] m rolling a distance of [---] m. Concept Explanation: This problem requires two steps: first finding the radius (r) from the given Area (A = r) and second using the Circumference (C = 2r) to find the number of revolutions (N = Distance / C)." [YouTube Link](https://youtube.com/watch?v=-YjC91zD7lc) 2026-01-27T04:53Z [---] followers, [--] engagements "Area of Three Sectors Shortcut Class [--] Maths Chapter [--] The Central Angle Trick Explained Don't waste time calculating the area of three sectors separately Watch this shortcut where we solve this common CBSE Class [--] geometry problem in a single step. Question: Three sectors of a circle of radius [--] cm making angles [--] [--] and [--] at the center are shaded. Find the area of the shaded region. Use = 22/7 Concept Explained: Learn how combining the central angles simplifies complex area calculations in circles. By recognizing that the total shaded angle creates a single larger sector we" [YouTube Link](https://youtube.com/watch?v=23dOJb7-MS8) 2026-02-11T07:17Z [---] followers, [--] engagements "Area of Segment Class [--] Maths Circles FULL SOLUTION in [--] Minutes (NCERT Example) Don't skip this Geometry essential Finding the Area of a Segment is one of the most tested topics in the Class [--] syllabus. QUESTION: A circle has a radius (r) of [--] cm and a central angle () of [--]. Find the area of the minor segment. (Use = 22/7). CONCEPT: The area of the minor segment is calculated by subtracting the area of the corresponding triangle from the area of the sector. The key formulas used are: Area of Sector = ( / 360) * * r and Area of Triangle = (1/2) * r * sin(). Mastery of this ensures full" [YouTube Link](https://youtube.com/watch?v=8-mVFXi7mzw) 2026-02-06T05:07Z [---] followers, [--] engagements "Area of Segment TRICK Chord Subtending [--] Class [--] Circles Most Important Question 🔥 Don't let area of segments problems confuse you This concept is crucial for your board exams. 🔥 Question: Find the difference of the areas of two segments of a circle formed by a chord of length [--] cm subtending an angle of [--] at the centre. We tackle a crucial application of the area of sectors and triangles within a circle. When the angle is [--] we use Pythagoras theorem to find the radius and then proceed step-by-step to calculate the area difference. Mastering these formulas is key to securing top marks." [YouTube Link](https://youtube.com/watch?v=9PbFQbp6uck) 2026-01-28T03:30Z [---] followers, [--] engagements "Area of Three Sectors in a Triangle Explained Class [--] Math Circles Abhi Garg Classes Don't let side lengths trick you This classic geometry problem relies on a fundamental concept you already know: the Angle Sum Property of a triangle. 🔥 Question: Given a triangle ABC arcs are drawn from vertices A B and C as centers each with a radius of r = [--] cm. If the side lengths are AB = [--] cm BC = [--] cm and CA = [--] cm find the total area of the three sectors. (Use = 3.14). Concept Explanation: This problem beautifully combines the area of a sector formula with the fact that the sum of angles in any" [YouTube Link](https://youtube.com/watch?v=A1f_KzER8Ww) 2026-01-29T04:41Z [---] followers, [--] engagements "Area Ratio: Circle vs Square when Perimeter is Equal Class [--] CBSE Geometry Problem Explained 🔥 Catchy Hook: Can two shapes with the same perimeter have drastically different areas Find out the crucial ratio for this classic exam question 📚 Question: If the perimeter of a circle is equal to that of a square then the ratio of their areas is what 💡 Concept Explanation: We equate the perimeter formulas (2r = 4a) to find the relationship between radius (r) and side (a). By substituting this relationship into the area ratio (A_c / A_s) we derive the simple fraction 4/ which simplifies to 14:11." [YouTube Link](https://youtube.com/watch?v=CIAcY5qs8Uc) 2026-02-05T05:11Z [---] followers, [--] engagements "Viral Geometry Trick: Find the Area of a Square Inscribed in a Circle (R = [---] cm) [--]. Hook: Stop confusing diameter and diagonal This simple concept is key to cracking high-level geometry questions quickly. [--]. The Question: The area of the square inscribed in a circle of radius [---] cm is calculated by equating the diameter of the circle to the diagonal of the square. [--]. Concept Explanation: The most efficient way to solve this is using the formula Area = (1/2) (Diagonal) where Diagonal = [--] Radius. This saves time and avoids finding the side length first. Result is [----] cm. [--]. Location: Join" [YouTube Link](https://youtube.com/watch?v=DFToWCPCCIw) 2026-02-03T04:53Z [---] followers, [--] engagements "Area of Shaded Region: Trapezium and Sector Cutout CBSE Class [--] Maths Geometry Problem 🔥 Don't let composite figures confuse you This problem tests your knowledge of two fundamental geometry formulas: Area of a Trapezium and Area of a Sector. Question: A trapezium ABCD with AB parallel to DC has parallel sides AB = [--] cm and DC = [--] cm and the height is [--] cm. A sector of a circle with radius r = [--] cm and central angle [--] is cut out from corner D. Find the area of the shaded region in terms of . 🎯 Concept Explained: The key is to break down the complex figure into simpler parts. Area of" [YouTube Link](https://youtube.com/watch?v=DK9bFA33PlA) 2026-02-12T05:21Z [---] followers, [--] engagements "Perimeter of a Sector SOLVED Class [--] Maths Area Related to Circles Full Explanation (CBSE) 🔥 HOOK: Don't lose marks on this easy Perimeter of Sector question It comes up almost every year in the Class [--] CBSE Board Exams. ❓ QUESTION: The shape of the top of a table is that of a sector of a circle with centre O and angle AOB = [--]. If AO = OB = [--] cm find the perimeter of the top of the table. 💡 CONCEPT: Remember that the perimeter of a sector includes not just the curved arc length but also the two straight radii. We use the formula: Perimeter = (/360) * 2r + 2r. Mastering this formula is" [YouTube Link](https://youtube.com/watch?v=Eupyn-8fiLw) 2026-02-12T05:13Z [---] followers, [--] engagements "Areas Related to Circles: ALL Formulas Explained in [--] Minutes Class [--] Maths Formula Sheet Are you tired of mixing up circumference and area This video gives you a crystal-clear breakdown of the [--] essential formulas needed for 'Areas Related to Circles' (Class 10/9 Maths). Formulas Covered: [--]. Area of Circle (r) [--]. Circumference (2r) [--]. Area of Sector [--]. Length of Arc [--]. Area of Segment Mastering these concepts is non-negotiable for scoring high in your CBSE Board Exams. We explain what each variable (r and ) represents and how to apply the formula correctly. Ready to achieve guaranteed" [YouTube Link](https://youtube.com/watch?v=HMkJjC7vOuU) 2026-02-10T04:59Z [---] followers, [--] engagements "Area of Uncovered Floor with Circular Tiles Tiling Problem Mensuration Class [--] & [--] 🎯 Quick Math Challenge: Area of Uncovered Floor **Question:** Floor of a room has dimensions [--] m [--] m. It is covered with circular tiles of diameter [--] cm each. Find the area of the floor that remains uncovered by the tiles. (Use = 3.14) This problem requires careful unit conversion (cm to m) and understanding how the area of a circle (r) relates to a rectangular floor space. We calculate the total area the area covered by all the tiles and subtract to find the remaining area. A crucial concept for Class [--] and" [YouTube Link](https://youtube.com/watch?v=IwZU6vmFiEw) 2026-01-30T05:12Z [---] followers, [--] engagements "Bicycle Wheel Problem [----] Revolutions in [--] km Find the Diameter (Circles Class 10/9) Is your geometry strong enough to measure a bicycle wheel 🚴♂ Let's tackle this classic problem involving Distance Revolutions and Circumference Question: A bicycle wheel makes [----] revolutions in moving [--] km. Find the diameter of the wheel. This concept is vital for understanding the relationship between linear distance traveled and angular rotation (Distance = N Circumference) a key topic in the 'Areas Related to Circles' chapter for CBSE/ICSE Class [--] and [--]. Join Abhi Garg Classes for top-tier coaching" [YouTube Link](https://youtube.com/watch?v=MmY8ZgCmBrM) 2026-02-07T06:20Z [---] followers, [--] engagements "Area of Sector Class [--] Clock Hand Problem (5 a.m. to [--] a.m.) Geometry and Circles Concept 🎯 Hook: Stop panicking when you see clock problems in circles Today we solve one of the most frequently asked Class [--] Sector questions in less than [--] seconds. Question: The length of the hour hand of a clock is [--] cm. Find the area of the minor sector swept by the hour hand of the clock between [--] a.m. to [--] a.m. Also find the area of the major sector. Concept Explained: The key is understanding that the hour hand moves [--] every hour (360 / [--] hours). Once the angle ( = 90) is found we use the formula" [YouTube Link](https://youtube.com/watch?v=NgLk78JZ5Tg) 2026-02-11T05:36Z [---] followers, [--] engagements "Major Segment Area Calculation Class [--] Circles Full Solution [--] Chord Problem 🔥 Don't let Major Segment problems scare you This is a frequently asked question (FAQ) for CBSE Class [--] Boards. Question: A chord of a circle of radius [--] cm subtends an angle of [--] at the centre. Find the area of the corresponding major segment of the circle. (Use = 3.14). Concept Explained: Finding the major segment involves calculating the total circle area and subtracting the minor segment (sector area - triangle area). Pay close attention to the right angle simplification Join Abhi Garg Classes for" [YouTube Link](https://youtube.com/watch?v=NiMKL6EZDkc) 2026-02-12T10:07Z [---] followers, [--] engagements "OLYMPIC RINGS MATH CHALLENGE Radius Sector & Segment Area in [--] Minutes Class [--] Circles 🔥 Geometry Hot Question 🔥 Unlock the secrets hidden within the Olympic Rings symbol This video breaks down a crucial application-based problem involving Circumference Area of Sectors and Area of Segments (Class [--] Maths). **The Question:** Students used 44m of rope per ring. If AOB is equilateral find the Radius (r) and the Area of the shaded Rangoli region (R). We show you exactly how to use the Circumference formula to find the radius and then calculate the segment area using = 22/7. Conceptual Clarity" [YouTube Link](https://youtube.com/watch?v=OFlgZzdQ9Zs) 2026-02-08T12:23Z [---] followers, [--] engagements "Area Related to Circles: Semi-Circle Farm House Case Study CBSE Class [--] Maths Abhi Garg Classes 🔥 Ultimate Geometry Challenge Can you solve this complex semi-circle case study involving perimeter and area Question: A farm house is shaped like a semi-circle (D=70 m). Point P is on the circumference such that PAB = [--]. Find (i) POA (ii) Total perimeter and (iii) Area of Sector AOP. This video breaks down how to use radius properties (Isosceles Triangles) and area formulas (Area of Sector) efficiently. Perfect revision for your Class [--] Board Exams 📍 Learn with the best at Abhi Garg Classes" [YouTube Link](https://youtube.com/watch?v=Ptn4T9k2EEs) 2026-02-09T05:15Z [---] followers, [--] engagements "Perimeter of a Sector of a Circle Class [--] Maths Chapter [--] Areas Related to Circles Solved Prob 🔥 Learn the easiest way to calculate the perimeter of a sector in seconds Question: The perimeter of the sector of a circle of radius [--] cm which subtends an angle of [--] at the centre of circle is: Concept Simplified: The perimeter of a sector combines the arc length (calculated using the central angle) and the length of the two radii. This concept is fundamental to the 'Areas Related to Circles' chapter for CBSE Class [--]. For personalized tutoring in Mathematics and Science (8th to 12th) visit" [YouTube Link](https://youtube.com/watch?v=YWXL48qKdRc) 2026-02-04T06:05Z [---] followers, [--] engagements "Arc Length Ratio Solved in Seconds [--] Central Angle Circles Class [--] Maths CBSE/ICSE Unlock the secrets of circles This ratio problem involving arc length and circumference is a guaranteed question type for your board exams. Question: If an arc subtends an angle of [--] at the center of a circle what is the ratio of its length to the circumference of the circle Concept Explained: The ratio of the arc length to the total circumference is directly proportional to the ratio of the central angle subtended by the arc () to the total angle (360). It's simpler than you think Master this and many more" [YouTube Link](https://youtube.com/watch?v=YfboouBCEBY) 2026-02-01T05:02Z [---] followers, [--] engagements "Equilateral Triangle & Inscribed Circle: Find the Shaded Area Class [--] Math Geometry Solution 🎯 Master the relationship between heights and radii in geometry This video solves a critical Class [--] problem involving an inscribed circle within an equilateral triangle. Question: A circle is inscribed in an equilateral triangle ABC of side [--] cm. Find the radius of the inscribed circle and the area of the shaded region. (Use = [----] and [--] = 1.73) We break down how to calculate the height of the triangle using the altitude formula and how that height determines the inradius (r=h/3). Then we" [YouTube Link](https://youtube.com/watch?v=cOiYO84acyU) 2026-02-13T06:34Z [---] followers, [--] engagements "Area of Sectors: Finding the Difference (120 Angle) Class [--] CBSE Chapter [--] Full Solution Get ready to ace your Class [--] Geometry chapter This video breaks down a highly requested board exam question: finding the difference between the areas of the Major and Minor sectors of a circle. Question: Find the difference of the areas of a sector of angle [---] and its corresponding major sector of a circle of radius [--] cm. We utilize the fundamental formula A = ( / 360) * * r and show a clean effective method to calculate the difference. Understanding the relationship between the minor and major" [YouTube Link](https://youtube.com/watch?v=cbSV72J4Gu0) 2026-01-31T05:40Z [---] followers, [--] engagements "🔥 Perimeter of Shaded Region Explained Circles Class [--] Maths Area Related to Circles CBSE Sol 🎯 Catchy Hook: Stop struggling with complex geometry figures This seemingly difficult shaded region problem is actually a simple application of the semi-circle perimeter formula. 🧠 The Question: PQRS is a diameter of a circle of radius [--] cm. PQ = QR = RS. Find the perimeter of the shaded region formed by semi-circles on diameters PQ QS and PS. 💡 Concept Explanation: The key is recognizing that the perimeter calculation requires only adding the lengths of the bounding arcs ( radius). Since the" [YouTube Link](https://youtube.com/watch?v=gAkNTb97qn4) 2026-02-12T15:13Z [---] followers, [---] engagements "Area of Remaining Cardboard Two Maximum Circles Cut from Rectangle Class [--] Maths Geometry Prob 🔥 How much cardboard area is left after cutting two big circles This is a classic geometry question that requires you to identify the maximum constraints Question: Two circular pieces of equal radii and maximum area touching each other are cut out from a rectangular card board of dimensions [--] cm x [--] cm. Find the area of the remaining card board. Use = 22/7 Concept Explanation: The key to solving this lies in recognizing that the diameter of the maximum possible equal circles must be equal to the" [YouTube Link](https://youtube.com/watch?v=h5w0_6fmH3Y) 2026-02-13T10:28Z [---] followers, [--] engagements "Perimeter of Shaded Region involving Semicircles Class [--] Mensuration Solved Abhi Garg Classes Unlock the secrets of Mensuration 🔓 Can you calculate the perimeter of this complex shaded region involving multiple semi-circles This is a guaranteed high-score question for CBSE/ICSE Class [--] Board Exams. The Question: In the figure a semi-circle is drawn with O as the center and AB as the diameter. Two smaller semi-circles are drawn using AO and OB as diameters. If AB = [--] m find the perimeter of the shaded region. (Use = 22/7). Concept Explained: The key here is recognizing that the perimeter" [YouTube Link](https://youtube.com/watch?v=m8OlJfBcc6c) 2026-02-14T07:27Z [---] followers, [--] engagements "SUM OF AREAS of Two Circular Parks Radius of the New Circle Class [--] Areas Related to Circles Stop guessing the answer This Class [--] Areas Related to Circles problem is crucial for your board exams preparation. We solve it step-by-step. 🤔 THE QUESTION: It is proposed to build a new circular park equal in area to the sum of areas of two circular parks of diameters [--] m and [--] m in a locality. Find the radius of the new park. 💡 CONCEPT EXPLAINED: We use the fundamental area formula A = r and the crucial relationship that the radius (r) is half the diameter (d). The entire problem hinges on" [YouTube Link](https://youtube.com/watch?v=mGfRjjp4jIU) 2026-02-02T05:10Z [---] followers, [--] engagements "Olympic Rings Area Calculation (Advanced Geometry) CBSE Class 10/12 Abhi Garg Classes 🤯 How the Olympic Rings are a hidden geometry puzzle Question: Given the Olympic rings of radius [--] cm where the common chord length is [--] cm. Find the total area of the four intersecting (dotted) regions. This video breaks down a tricky area calculation question. We use the property that equal radius and equal chord length create a [--] (Equilateral Triangle) sector. Mastering segment area calculation is key to solving CBSE and competitive exam problems. 📍 Visit us: Abhi Garg Classes Sector [--] Chandigarh. 🔔" [YouTube Link](https://youtube.com/watch?v=p63ROnqlfXY) 2026-02-07T14:12Z [---] followers, [--] engagements "CBSE Class [--] Solve the Viral Square & Circles Shaded Area Problem in [--] Steps Areas Related to C 🔥 Master the trickiest geometry problems effortlessly 🔥 Question: ABCD is a square of side [--] cm. Four circles are drawn with centres A B C and D such that each circle touches two adjacent circles externally. Find the area of the shaded region. Concept: This is a classic problem involving Areas Related to Circles. We calculate the area of the large square and subtract the area of the four identical quarter-circle sectors. A must-know concept for Class [--] CBSE boards (Area of Square - Area of 1" [YouTube Link](https://youtube.com/watch?v=s7PjzBOY8EQ) 2026-02-13T05:02Z [---] followers, [--] engagements "NCERT MASTER: Area of Square Lawn & Circular Flower Beds Class [--] Maths Chapter [--] [----] m 🎯 Master the tricky concepts of Areas Related to Circles with Abhi Garg Classes Question: In the given figure two circular flower beds have been shown on two sides of a square lawn ABCD of side [--] m. If the center of each circular flower bed is the point of intersection O of the diagonals of the square lawn find the sum of the areas of the lawn and the flower beds. 💡 Concept Explanation: This problem requires combining the area of a square with the area of two circular segments. We must first find the" [YouTube Link](https://youtube.com/watch?v=sJ3mwrDl7tg) 2026-02-10T05:12Z [---] followers, [--] engagements "Bus Wheel Revolutions: How to Calculate RPM from Speed Class [--] Circles Application Problem Catchy Hook: Stop guessing Learn the precise mathematical relationship between linear speed and the rotation of a wheel in just a few steps. Question: The diameter of the wheels of a bus is [---] cm. How many revolutions per minute must a wheel make in order to move at a speed of [--] km per hour Concept Explanation: This concept requires using the circumference (2r) to find the distance covered in one rotation. Crucially you must perform accurate unit conversions moving from kilometers per hour to" [YouTube Link](https://youtube.com/watch?v=vPj_YSWam5I) 2026-02-08T05:55Z [---] followers, [--] engagements "Quick Proof: (cot cosec ) = (1 cos )/(1 + cos ) #Maths Problem: Prove (cot cosec ) = (1 cos )/(1 + cos ). Solution summary: [--]. cot cosec = (cos 1)/sin = (1 cos )/sin . [--]. Square and use sin = [--] cos = (1 cos )(1 + cos ). [--]. Cancel (1 cos ) to get (1 cos )/(1 + cos ). Domain: sin [--] so cot and cosec are defined. #Trigonometry #Class10Maths #MathsProof #AbhiGargClasses" [YouTube Link](https://youtube.com/watch?v=1J53DuX5CY8) 2025-10-07T05:33Z [---] followers, [--] engagements "Trig Proof: (1+sec)/sec = sin/(1cos) Problem: Prove (1 + sec A)/sec A = sinA/(1 cos A). Short solution: LHS = (1+secA)/secA = 1/secA + [--] = cosA + [--]. RHS = sinA/(1cosA) = (1cosA)/(1cosA) = 1+cosA (after cancellation). Thus both sides equal [--] + cosA where defined. Domain: require cosA [--] and [--] cosA [--] for direct cancellation; equality's simplified form 1+cosA holds when expressions are defined. (Abhi Garg Classes)" [YouTube Link](https://youtube.com/watch?v=1JGPvwx04PU) 2025-10-10T04:54Z [---] followers, [---] engagements "Sum of 11-term AP when middle term = [--] #AP #MathsTrick Arithmetic Progression quick method: sum of odd-numbered AP = n (middle term). Learn why S = n middle term and apply it fast for exams. #WhatIsTheSum #HowToFind Question (rewritten): Find the sum of all the [--] terms of an AP whose middle most term is [--]. Short Explanation: For any AP with odd number of terms n the middle term equals the average of the sequence and the sum of all terms = n (middle term). Here n = [--] and middle term = [--] so total sum S = [--] [--] = [---]. Perfect quick trick for Class [--] / CBSE / NCERT exam prep saves time in" [YouTube Link](https://youtube.com/watch?v=1O8_0ByIGfc) 2025-09-05T05:54Z [---] followers, [---] engagements "Find the 3-digit AP number Sum=15 Reverse is [---] less #AP #Maths Class [--] Maths Arithmetic Progression Important AP Word Problem 👉 Question: The digits of a three-digit positive integer are in AP. Their sum is [--]. The number obtained by reversing the digits is [---] less than the original number. Find the number. 🔎 Key Concepts: - Digits in AP middle digit = average of first and last. - Sum of digits = [--]. - Reversed number = Original number [---]. - Equation solving with AP logic. 📘 Solution Highlights: Let digits be (a d) a (a + d). Sum = (a d) + a + (a + d) = 3a = [--] a = [--]. Digits: (5 d) 5" [YouTube Link](https://youtube.com/watch?v=2daOuUSzhyw) 2025-09-07T13:28Z [---] followers, [---] engagements "#FindNumberOfTerms in AP: [----] [--]. ➤ Sum = [---] #HowManyTerms #WhatIsN Solved In this video we solve this Arithmetic Progression problem: "How many terms of the AP [----] [--]. must be taken so that their sum is 636" Perfect for CBSE Class [--] students and those preparing for competitive exams. #FindNumberOfTerms #HowManyTerms #WhatIsN #APSolved #ArithmeticProgression #NCERTQuestion #CBSEMaths #Class10Maths #MathHelp #APFormula #MathShorts" [YouTube Link](https://youtube.com/watch?v=3a9w-CWEPb0) 2025-07-31T05:53Z [---] followers, [--] engagements "When Are Two A.P. Terms Equal Class [--] CBSE AP Trick 🎯 Two arithmetic progressions. One question: 👉 When will their nth terms become equal AP 1: [--] [--] [--]. AP 2: [--] [--] [--]. Learn how to equate AP terms step-by-step. Great revision for CBSE Class [--] students 🧮 Perfect question for board preparation. 📌 Like Comment your answer and Subscribe for more class [--] math tricks. #MathChallenge #ArithmeticProgression #CBSEClass10 #BoardExam2025 #StudyShorts #FastMaths #nthterm #MathsWithAbhiSir" [YouTube Link](https://youtube.com/watch?v=49PdoyfxSXQ) 2025-07-20T08:13Z [---] followers, [--] engagements "🤯 Number Riddle with Digits Class [--] Quadratic Equation Statement Ques. #mathematics #quadratic 🎓 Quadratic Equation Word Problem Number Based Puzzle Class [--] Maths 📌 Question Covered: A two-digit number is four times the sum of its digits. It is also equal to three times the product of its digits. 👉 Find the number. 📘 In this video: Step-by-step explanation Building and solving the quadratic equation Tips to identify number-based word problems in Class [--] Board Exams 🧑🏫 Presented by Abhi Sir Mathematics and Science 🎯 Ideal for: ✔ Class [--] CBSE students ✔ Quadratic equation word" [YouTube Link](https://youtube.com/watch?v=5Sb-SIna9pQ) 2025-06-18T10:37Z [---] followers, [--] engagements "Find the Missing Terms in APs Class [--] Arithmetic Progression #AP #question3 📘 Topic: Fill in the missing terms in the given Arithmetic Progressions (APs) using the formula: 👉 an = a + (n 1)d In this video we solve [--] different APs where some terms are missing. Learn how to find them step-by-step 🔥 Must-watch for Class [--] CBSE students preparing for board exams 📌 Like comment and subscribe for more concept-wise short videos #ArithmeticProgression #MissingTermsInAP #Class10Maths #CBSEBoard2025 #MathsWithAbhiSir #FillTheBlanksAP #APChapterClass10 #MathConcepts #BoardExamPrep" [YouTube Link](https://youtube.com/watch?v=5mGSHSv0-o4) 2025-07-08T11:21Z [---] followers, [--] engagements "#AP Sum Formula Proof Show that S = (a+c)(b+c-2a)/2(b-a) #Class10Maths #NCERT 📘 In this video we solve an important NCERT/CBSE Class [--] Maths question on Arithmetic Progressions (AP). We are asked to **show that the sum of an AP with first term a second term b and last term c is equal to (a+c)(b+c-2a) / 2(b-a).** 👉 This proof is a frequently asked question in exams and is very important for Class [--] board preparation. 👉 We carefully break it down step by step for better understanding. ✨ Keywords: Arithmetic Progression sum proof Class [--] Maths AP proof NCERT AP sum formula CBSE AP" [YouTube Link](https://youtube.com/watch?v=61PnnIE62RY) 2025-09-03T06:49Z [---] followers, [--] engagements "#AP #Class10 If n-2 4n-1 5n+2 are in AP Find n Answer = [--] Arithmetic Progression Class [--] question: Solve for n if n-2 4n-1 5n+2 are in AP. SEO: AP condition how to check numbers in AP find n in AP NCERT CBSE maths solutions. Question (rewritten): If the numbers n - [--] 4n - [--] and 5n + [--] are in AP find the value of n. Fast solution: For AP: 2nd 1st = 3rd 2nd (4n - 1) - (n - 2) = (5n + 2) - (4n - 1) 3n + [--] = n + [--] 3n - n = [--] - [--] 2n = [--] n = [--] ✅ Answer: n = [--] #ArithmeticProgression #Class10Maths #NCERT #CBSE #APFormula #ExamPrep #WhatIsTheAnswer #MathTrick" [YouTube Link](https://youtube.com/watch?v=6kM3BuXtwMU) 2025-08-30T05:13Z [---] followers, [--] engagements "When Are Two A.P. Terms Equal Class [--] CBSE AP Trick 🎯 Two arithmetic progressions. One question: 👉 When will their nth terms become equal AP 1: [--] [--] [--]. AP 2: [--] [--] [--]. Learn how to equate AP terms step-by-step. Great revision for CBSE Class [--] students 🧮 Perfect question for board preparation. 📌 Like Comment your answer and Subscribe for more class [--] math tricks. #MathChallenge #ArithmeticProgression #CBSEClass10 #BoardExam2025 #StudyShorts #FastMaths #nthterm #MathsWithAbhiSir" [YouTube Link](https://youtube.com/watch?v=7VwrmO6P8bI) 2025-07-20T08:13Z [---] followers, [---] engagements "AP Tricks: Find 'a' and 'd' in Seconds Class [--] Maths #maths #AP 📘 Topic: Find the first term and common difference of given Arithmetic Progressions (APs). We solve the following APs: [--] [--] [--] [--] [--] [--] [--] [--] [--] [--] [--] [--] [---] [---] [---] [---] 🧠 Concept: First term = first number in the AP Common difference = second term first term Perfect for Class [--] CBSE students learning AP basics #Class10Maths #ArithmeticProgression #FindCommonDifference #CBSE2025 #APFirstTerm #MathsWithAbhiSir #BoardMathsPrep #MathBasics #NumberPatterns #StudyShorts" [YouTube Link](https://youtube.com/watch?v=7j5tz3-LcJg) 2025-06-30T14:14Z [---] followers, [---] engagements "AM = tanB=3/4 tanC=5/12 BC=56 AM = [--] cm #TrigTrick Geometry + Trigonometry: Find the altitude AM when BC = [--] cm and tan B = 3/4 tan C = 5/12. Short exam-ready solution below. SEO: altitude of triangle tanB and tanC given find AM Class [--] trig NCERT geometry problem. Question (rewritten): In ABC AM is perpendicular to BC. If tan B = 3/4 tan C = 5/12 and BC = [--] cm find the length of AM. Solution (step-by-step): 1) Drop altitude AM to BC at M. In right triangles ABM and ACM: tan B = AM / BM BM = AM / tan B tan C = AM / CM CM = AM / tan C 2) BC = BM + CM = AM(1/tan B + 1/tan C). 3) Therefore" [YouTube Link](https://youtube.com/watch?v=9n7GO3xhabg) 2025-09-15T05:36Z [---] followers, [--] engagements "AP [--] [--] [--] [--] : First negative term #ArithmeticProgression Class [--] AP Decreasing AP to first negative term using nth term formula. SEO: AP first negative term AP decreasing series Class [--] NCERT AP questions. Rewritten Question: Which term of the AP [--] [--] [--] [--] is the first negative term Quick Solution: a=65 d=4. a = [--] + (n1)(4) = [--] 4n For first negative: [--] 4n [--] n [-----] n = [--]. Check: a = [--] [--] = [--] (negative) a = [--] (positive). ✅ Answer: 18th term. #ArithmeticProgression #WhichTerm #APQuestion #NCERT #CBSE #BoardExamPrep #APFormula #MathsShorts" [YouTube Link](https://youtube.com/watch?v=ANWTz9lla9g) 2025-08-23T05:01Z [---] followers, [--] engagements "Class [--] Maths [--] Number System Explained Real Rational Irrational Integers & More 📚 Class [--] Maths Number System Full Concept Explained In this video we cover all types of numbers in detail: Natural Numbers Whole Numbers Integers Rational & Irrational Numbers Real Numbers With simple examples and clear explanation. 🎯 Perfect for CBSE ICSE and State Boards. 🔔 Dont forget to Subscribe for more Maths & Science lessons 📥 Share with friends and support the channel #class9maths #numbersystem #mathslecture #cbsemaths #rationalnumbers #irrationalnumbers #abhigargclasses" [YouTube Link](https://youtube.com/watch?v=BbI5pR8O3b4) 2025-05-22T15:11Z [---] followers, [--] engagements "Sum of LAST [--] terms: AP [--] [--] [--] [---] Answer = [----] #AP #Class10 #NCERT AP last ten terms sum sum of last [--] terms AP Class [--] Arithmetic Progression NCERT solution. SEO: how to find sum of last [--] terms AP sum formula NCERT Class [--] AP CBSE maths tricks. Rewritten Question: Find the sum of the last ten terms of the AP: [--] [--] [--] [---]. Fast Solution (one glance): a = [--] d = [--] last term l = [---] Find total terms: [---] = [--] + (n1)2 n = [--] Last [--] terms are T51 to T60: first of this block = T51 = [--] + [---] = [---] Sum of last [--] = (10/2) (first_of_block + last_term) = [--] (108 + 126) = [--] [---] = [----] ✅ Final" [YouTube Link](https://youtube.com/watch?v=ClODyNUHFJw) 2025-09-02T14:37Z [---] followers, [--] engagements "Quick Proof: (cosecsin)(seccos)=1/(tan+cot) Problem: Show that (cosec A sin A)(sec A cos A) = [--] / (tan A + cot A). Short solution summary: [--]. Convert to sines and cosines: cosecsin = cos/sin and seccos = sin/cos. [--]. Multiply to get sinAcosA. [--]. RHS simplifies to 1/( (sin+cos)/(sincos) ) = sinAcosA. Thus both sides equal sinAcosA; identity proved. Domain: require sinA [--] and cosA [--] so expressions are defined. #Trigonometry #Class10Maths #MathsProof #AbhiGargClasses" [YouTube Link](https://youtube.com/watch?v=Cn5WDF4zH_U) 2025-09-30T06:15Z [---] followers, [--] engagements "Find altitude AM when tan B=3/4 tan C=5/12 and BC=56 cm Quick Trig Trick #Geometry #Trigonometry Geometry + Trigonometry: Find the altitude AM when BC = [--] cm and tan B = 3/4 tan C = 5/12. Short exam-ready solution below. SEO: altitude of triangle tanB and tanC given find AM Class [--] trig NCERT geometry problem. Question (rewritten): In ABC AM is perpendicular to BC. If tan B = 3/4 tan C = 5/12 and BC = [--] cm find the length of AM. Solution (step-by-step): 1) Drop altitude AM to BC at M. In right triangles ABM and ACM: tan B = AM / BM BM = AM / tan B tan C = AM / CM CM = AM / tan C 2) BC = BM" [YouTube Link](https://youtube.com/watch?v=CnsSeI77Yb4) 2025-09-15T05:33Z [---] followers, [--] engagements "AP Trick: Sum of last [--] terms in [--------] = [----] ✅ AP last ten terms sum sum of last [--] terms AP Class [--] Arithmetic Progression NCERT solution. SEO: how to find sum of last [--] terms AP sum formula NCERT Class [--] AP CBSE maths tricks. Rewritten Question: Find the sum of the last ten terms of the AP: [--] [--] [--] [---]. Fast Solution (one glance): a = [--] d = [--] last term l = [---] Find total terms: [---] = [--] + (n1)2 n = [--] Last [--] terms are T51 to T60: first of this block = T51 = [--] + [---] = [---] Sum of last [--] = (10/2) (first_of_block + last_term) = [--] (108 + 126) = [--] [---] = [----] ✅ Final Answer: 1170" [YouTube Link](https://youtube.com/watch?v=N_FHMIlJsbY) 2025-09-02T14:35Z [---] followers, [--] engagements "AP Trick: If a:a=2:3 find S:S (Answer 6:17) #ArithmeticProgression #Class10 AP ratio problem nth term to sum conversion Class [--] NCERTquick proof + final answer (6:17). SEO: Arithmetic Progression ratio a11:a18=2:3 find S5:S10 AP nth term AP sum formula Class [--] CBSE NCERT solutions. Question (rewritten): If the ratio of the 11th term of an AP to its 18th term is 2:3 find the ratio of the sum of the first five terms to the sum of its first ten terms. Fast solution: Let a be the first term and d the common difference. a = a + (n1)d Given a : a = (a+10d) : (a+17d) = [--] : [--] 3(a+10d) = 2(a+17d) 3a" [YouTube Link](https://youtube.com/watch?v=OF8N2zvIcv8) 2025-08-28T05:11Z [---] followers, [--] engagements "Prove [--] + (cot)/(1 + cosec ) = cosec #Maths Problem: Prove that [--] + (cot) / (1 + cosec ) = cosec . Solution (step-by-step): [--]. Start with the LHS: [--] + (cot) / (1 + cosec ) = (1 + cosec ) + cot / (1 + cosec ) (write [--] as (1 + cosec )/(1 + cosec )) [--]. Use identity: [--] + cot = cosec Numerator = cosec + cosec = cosec (cosec + 1) [--]. So LHS = cosec (cosec + 1) / (1 + cosec ) = cosec . Hence proved: [--] + (cot) / (1 + cosec ) = cosec . #Trigonometry #MathsProof #Class10Maths #TrigIdentities (For more such proofs follow Abhi Garg Classes.)" [YouTube Link](https://youtube.com/watch?v=OgfKtge4d6k) 2025-09-24T05:47Z [---] followers, [--] engagements "Trig Identity:Q8 part V) (cossin+1)/(cos+sin1) = cosec + cot #Maths Problem: Prove (cos A sin A + 1)/(cos A + sin A 1) = cosec A + cot A. Solution summary: RHS = (1 + cos A)/sin A. Cross-multiply and expand both sides. Use sinA + cosA = [--] to show both sides match. Domain: sin A [--] and cos A + sin A [--] [--]. For more quick trig proofs follow Abhi Garg Classes" [YouTube Link](https://youtube.com/watch?v=RaJNF0D--uE) 2025-10-01T05:44Z [---] followers, [--] engagements "Trig Identity:Q8 part V) (cossin+1)/(cos+sin1) = cosec + cot #Maths Problem: Prove (cos A sin A + 1)/(cos A + sin A 1) = cosec A + cot A. Solution summary: RHS = (1 + cos A)/sin A. Cross-multiply and expand both sides. Use sinA + cosA = [--] to show both sides match. Domain: sin A [--] and cos A + sin A [--] [--]. For more quick trig proofs follow Abhi Garg Classes" [YouTube Link](https://youtube.com/watch?v=Sm-Rw1g1f4M) 2025-10-01T05:45Z [---] followers, [--] engagements "🤔 Can you solve this in [--] secondsMath isnt tough you just need the right strategy Question: If two positive integers a and b are as a = x3y2 and b = xy3 where x y are prime numbers then the result obtained by dividing the product of the positive integers by the LCM (a b) is 🤔 Can you solve this in [--] seconds Math isnt tough you just need the right strategy Try this smart LCM trick from exponents 💡 🎓 Topic: Real Number Class [--] 🔔 Follow for more CBSE math tricks #class10maths #mathtricks #numberSystem #cbse2025 #abhigargclasses #shorts #reels" [YouTube Link](https://youtube.com/watch?v=SuUnDhN_Nbg) 2025-06-01T07:57Z [---] followers, [---] engagements "How to Find First Term and Common Difference of APs Class [--] Arithmetic Progression 📘 Topic: Find the first term and common difference of given Arithmetic Progressions (APs). We solve the following APs: [--] [--] [--] [--] [--] [--] [--] [--] [--] [--] [--] [--] [---] [---] [---] [---] 🧠 Concept: First term = first number in the AP Common difference = second term first term Perfect for Class [--] CBSE students learning AP basics #Class10Maths #ArithmeticProgression #FindCommonDifference #CBSE2025 #APFirstTerm #MathsWithAbhiSir #BoardMathsPrep #MathBasics #NumberPatterns #StudyShorts" [YouTube Link](https://youtube.com/watch?v=TM3UiLylgTQ) 2025-06-30T14:16Z [---] followers, [--] engagements "#SumOfAP Find the Sum of These Tricky APs #WhatIsTheSum #Class10Maths #CBSE2025 📘 Lets solve [--] interesting AP sums These questions test your understanding of AP Sum Formula (Sn). Watch this step-by-step breakdown for: (i) [--] + [----] + [--] +. + [--] (ii) [--] + [--] + [--] +. + [--] (iii) [--] + (8) + (11) +. + (230) Perfect for Class [--] CBSE [----] prep 📚 👇 Comment your answers below #WhatIsTheSum #SumOfAP #Class10Maths #CBSE2025 #MathsQuiz #ArithmeticProgression #SnFormula #LearnWithAbhiSir #MathsReel #NTHTerm #FormulaBasedQuestion #BoardExamPrep" [YouTube Link](https://youtube.com/watch?v=Uxtw-Q5pUJM) 2025-07-27T07:06Z [---] followers, [--] engagements "Trig Proof: tan/(1cot) + cot/(1tan) = [--] + seccsc #Maths Problem: Prove fractantheta1-cottheta + fraccottheta1-tantheta = [--] + secthetacsctheta. Solution summary: Convert tan and cot to sin/cos and simplify. Combine terms factor sin3cos3 and cancel (sincos). Use sin2+cos2 = [--] to reach [--] + 1/(sincos) = [--] + seccsc. Perfect for Class [--] practice and quick exam revision. (Abhi Garg Classes)" [YouTube Link](https://youtube.com/watch?v=VzptZiYx5Ng) 2025-10-06T05:21Z [---] followers, [--] engagements "AP Sum Proof 🔥 (a+c)(b+c-2a)/2(b-a) #Maths #Class10 📘 In this video we solve an important NCERT/CBSE Class [--] Maths question on Arithmetic Progressions (AP). We are asked to **show that the sum of an AP with first term a second term b and last term c is equal to (a+c)(b+c-2a) / 2(b-a).** 👉 This proof is a frequently asked question in exams and is very important for Class [--] board preparation. 👉 We carefully break it down step by step for better understanding. ✨ Keywords: Arithmetic Progression sum proof Class [--] Maths AP proof NCERT AP sum formula CBSE AP questions. #Maths" [YouTube Link](https://youtube.com/watch?v=WafV9kJJQ1w) 2025-09-03T06:51Z [---] followers, [--] engagements "3-digit number in AP Digits sum [--] & reverse is [---] less Important Class [--] AP Question #Maths Class [--] Maths Arithmetic Progression Important AP Word Problem 👉 Question: The digits of a three-digit positive integer are in AP. Their sum is [--]. The number obtained by reversing the digits is [---] less than the original number. Find the number. 🔎 Key Concepts: - Digits in AP middle digit = average of first and last. - Sum of digits = [--]. - Reversed number = Original number [---]. - Equation solving with AP logic. 📘 Solution Highlights: Let digits be (a d) a (a + d). Sum = (a d) + a + (a + d) =" [YouTube Link](https://youtube.com/watch?v=Wh9mpSu1nts) 2025-09-07T13:23Z [---] followers, [--] engagements "Can You Fill the Missing AP Terms Class [--] CBSE #Ap #exercise5.2 #question3 📘 Topic: Fill in the missing terms in the given Arithmetic Progressions (APs) using the formula: 👉 an = a + (n 1)d In this video we solve [--] different APs where some terms are missing. Learn how to find them step-by-step 🔥 Must-watch for Class [--] CBSE students preparing for board exams 📌 Like comment and subscribe for more concept-wise short videos #ArithmeticProgression #MissingTermsInAP #Class10Maths #CBSEBoard2025 #MathsWithAbhiSir #FillTheBlanksAP #APChapterClass10 #MathConcepts #BoardExamPrep" [YouTube Link](https://youtube.com/watch?v=WoveNiwi3RQ) 2025-07-08T11:23Z [---] followers, [--] engagements "Find [--] AP numbers: Sum [--] & product ratio 7:15 Quick Solve #AP #WhatIs AP problem: find four consecutive AP terms when their sum is [--] and (firstlast) : (2nd3rd) = [--] : [--] Answer: [--] [--] [--] [--]. SEO keywords: Arithmetic Progression find numbers in AP AP product ratio sum of AP Class [--] NCERT problem. Question (rewritten): The sum of four consecutive numbers in an AP is [--] and the ratio of the product of the first and the last terms to the product of the two middle terms is [--] : [--]. Find the numbers. Short solution: Let the four consecutive AP terms be a a+d a+2d a+3d. Sum 4a + 6d = [--] 2a + 3d = 16" [YouTube Link](https://youtube.com/watch?v=a9-Lg0h3Xj8) 2025-09-01T05:09Z [---] followers, [---] engagements "🟰 Find Dimensions of Triangle Quadratic Equation Word Problem Class [--] Maths 📘 Quadratic Equation Word Problem Class [--] CBSE Maths 🔹 Question: The area of a right-angled triangle is [---] cm. If the base exceeds the height by [--] cm find the dimensions of the triangle. 🧠 In this short video: Learn to form and solve a quadratic equation from a geometry word problem Use the area formula ( base height) with smart substitution Solve it step-by-step in an easy way 🎓 Best for: ✔ CBSE Class [--] Students ✔ Word problem practice ✔ Concept strengthening & exam readiness 👨🏫 Explained by Abhi Sir" [YouTube Link](https://youtube.com/watch?v=aV6lwSAyjNM) 2025-06-15T13:27Z [---] followers, [---] engagements "#AP Question Sum of Two Middle Terms in AP: -4/3 [---] -2/3. [--] #Class10 #NCERT 📘 In this video we solve an **NCERT Class [--] Arithmetic Progression problem**: Find the sum of the two middle most terms of the AP: -4/3 [---] -2/3 [--]. 👉 We calculate the total number of terms identify the two middle terms and then find their sum step by step. 👉 This is an important CBSE exam-style question from the Arithmetic Progressions chapter. ✨ Keywords: Arithmetic Progression middle terms Class [--] Maths AP NCERT AP questions CBSE AP sums sum of middle terms in AP. #Maths #ArithmeticProgression #NCERT #CBSE" [YouTube Link](https://youtube.com/watch?v=bEhi8wa9skU) 2025-09-04T06:03Z [---] followers, [--] engagements "Trig Proof: tan/(1cot) + cot/(1tan) = [--] + seccsc #Maths Problem: Prove fractantheta1-cottheta + fraccottheta1-tantheta = [--] + secthetacsctheta. Solution summary: Convert tan and cot to sin/cos and simplify. Combine terms factor sin3cos3 and cancel (sincos). Use sin2+cos2 = [--] to reach [--] + 1/(sincos) = [--] + seccsc. Perfect for Class [--] practice and quick exam revision. (Abhi Garg Classes)" [YouTube Link](https://youtube.com/watch?v=cFaL660mHIQ) 2025-10-06T05:21Z [---] followers, [--] engagements "Quick Proof: (cot cosec ) = (1 cos )/(1 + cos ) #Maths Problem: Prove (cot cosec ) = (1 cos )/(1 + cos ). Solution summary: [--]. cot cosec = (cos 1)/sin = (1 cos )/sin . [--]. Square and use sin = [--] cos = (1 cos )(1 + cos ). [--]. Cancel (1 cos ) to get (1 cos )/(1 + cos ). Domain: sin [--] so cot and cosec are defined. #Trigonometry #Class10Maths #MathsProof #AbhiGargClasses" [YouTube Link](https://youtube.com/watch?v=eIeK-htB4-Q) 2025-10-07T05:34Z [---] followers, [--] engagements "Different way: If tan + cot = [--] ( acute) Find tan + cot Trig Quick Trick #Trigonometry Trigonometry trick: If tan + cot = [--] ( acute) find tan7 + cot7. Quick proof and result perfect for exam prep and short-form maths videos. Question (rewritten): If is an acute angle and tan + cot = [--] find tan7 + cot7 . Solution (short): Let t = tan. Then t + 1/t = [--] (t2 + 1)/t = [--] t2 2t + [--] = [--] (t 1)2 = [--] t = [--] (since is acute). So tan = [--] and cot = [--]. Hence tan7 + cot7 = [--] + [--] = [--]. ✅ Final Answer: [--] #Trigonometry #TrigTrick #tanpluscot #WhatIsTheAnswer #HowToSolve #MathsShorts #Class10Maths #NCERT #CBSE" [YouTube Link](https://youtube.com/watch?v=ecmegBGyrI4) 2025-09-14T13:41Z [---] followers, [--] engagements "Quick Proof: [--] + (cot)/(1 + cosec ) = cosec Problem: Prove that [--] + (cot) / (1 + cosec ) = cosec . Solution (step-by-step): [--]. Start with the LHS: [--] + (cot) / (1 + cosec ) = (1 + cosec ) + cot / (1 + cosec ) (write [--] as (1 + cosec )/(1 + cosec )) [--]. Use identity: [--] + cot = cosec Numerator = cosec + cosec = cosec (cosec + 1) [--]. So LHS = cosec (cosec + 1) / (1 + cosec ) = cosec . Hence proved: [--] + (cot) / (1 + cosec ) = cosec . #Trigonometry #MathsProof #Class10Maths #TrigIdentities (For more such proofs follow Abhi Garg Classes.)" [YouTube Link](https://youtube.com/watch?v=fB23YVJk02c) 2025-09-24T05:48Z [---] followers, [--] engagements "tan + cot = [--] tan + cot = Trig Trick #Maths Trigonometry trick: If tan + cot = [--] ( acute) find tan7 + cot7. Quick proof and result perfect for exam prep and short-form maths videos. Question (rewritten): If is an acute angle and tan + cot = [--] find tan7 + cot7 . Solution (short): Let t = tan. Then t + 1/t = [--] (t2 + 1)/t = [--] t2 2t + [--] = [--] (t 1)2 = [--] t = [--] (since is acute). So tan = [--] and cot = [--]. Hence tan7 + cot7 = [--] + [--] = [--]. ✅ Final Answer: [--] #Trigonometry #TrigTrick #tanpluscot #WhatIsTheAnswer #HowToSolve #MathsShorts #Class10Maths #NCERT #CBSE #ExamPrep" [YouTube Link](https://youtube.com/watch?v=jEKB2iyIvWc) 2025-09-13T05:50Z [---] followers, [---] engagements "#FindSn When S = [--] and S = [---] AP Sum Formula #ArithmeticProgression #Class10Maths In this video we solve: "If the sum of first [--] terms of an AP is [--] and that of [--] terms is [---] find the sum of first n terms." We use the formula: S = n/2 (2a + (n - 1)d) and simplify using given values to find a general expression for S. A perfect AP Sum problem from CBSE Class [--] Arithmetic Progression chapter. #FindSn #APSum #ArithmeticProgression #APFormula #CBSEMaths #NCERTSolution #Class10Maths #MathsQuestion #WhatIsSn #HowToFindSum" [YouTube Link](https://youtube.com/watch?v=ndM8vyT0W4E) 2025-08-01T05:05Z [---] followers, [--] engagements "First negative term in [------] #AP Class [--] AP Decreasing AP to first negative term using nth term formula. SEO: AP first negative term AP decreasing series Class [--] NCERT AP questions. Rewritten Question: Which term of the AP [--] [--] [--] [--] is the first negative term #ArithmeticProgression #WhichTerm #APQuestion #NCERT #CBSE #BoardExamPrep #APFormula #MathsShorts" [YouTube Link](https://youtube.com/watch?v=nzgxBeHC3bo) 2025-08-23T05:02Z [---] followers, [--] engagements "AP Problem: Sum = [--] & (1st4th):(2nd3rd)=7:15 Find the [--] numbers #What #How AP problem: find four consecutive AP terms when their sum is [--] and (firstlast) : (2nd3rd) = [--] : [--] Answer: [--] [--] [--] [--]. SEO keywords: Arithmetic Progression find numbers in AP AP product ratio sum of AP Class [--] NCERT problem. Question (rewritten): The sum of four consecutive numbers in an AP is [--] and the ratio of the product of the first and the last terms to the product of the two middle terms is [--] : [--]. Find the numbers. Short solution: Let the four consecutive AP terms be a a+d a+2d a+3d. Sum 4a + 6d = [--] 2a + 3d" [YouTube Link](https://youtube.com/watch?v=oRvyb2jeT58) 2025-09-01T05:07Z [---] followers, [--] engagements "14 Trigonometry tan7 a + cot7 a Trigonometry trick: If tan + cot = [--] ( acute) find tan7 + cot7. Quick proof and result perfect for exam prep and short-form maths videos. Question (rewritten): If is an acute angle and tan + cot = [--] find tan7 + cot7 . Solution (short): Let t = tan. Then t + 1/t = [--] (t2 + 1)/t = [--] t2 2t + [--] = [--] (t 1)2 = [--] t = [--] (since is acute). So tan = [--] and cot = [--]. Hence tan7 + cot7 = [--] + [--] = [--]. ✅ Final Answer: [--] #Trigonometry #TrigTrick #tanpluscot #WhatIsTheAnswer #HowToSolve #MathsShorts #Class10Maths #NCERT #CBSE #ExamPrep" [YouTube Link](https://youtube.com/watch?v=qD1kN6GbBI4) 2025-09-13T05:49Z [---] followers, [--] engagements "Diiferent Way: tan + cot = [--] tan + cot = Trig Trick #Maths Trigonometry trick: If tan + cot = [--] ( acute) find tan7 + cot7. Quick proof and result perfect for exam prep and short-form maths videos. Question (rewritten): If is an acute angle and tan + cot = [--] find tan7 + cot7 . Solution (short): Let t = tan. Then t + 1/t = [--] (t2 + 1)/t = [--] t2 2t + [--] = [--] (t 1)2 = [--] t = [--] (since is acute). So tan = [--] and cot = [--]. Hence tan7 + cot7 = [--] + [--] = [--]. ✅ Final Answer: [--] #Trigonometry #TrigTrick #tanpluscot #WhatIsTheAnswer #HowToSolve #MathsShorts #Class10Maths #NCERT #CBSE #ExamPrep" [YouTube Link](https://youtube.com/watch?v=rI8uiIm1ZEo) 2025-09-14T13:43Z [---] followers, [--] engagements "Trig Proof: (1+sec)/sec = sin/(1cos) Problem: Prove (1 + sec A)/sec A = sinA/(1 cos A). Short solution: LHS = (1+secA)/secA = 1/secA + [--] = cosA + [--]. RHS = sinA/(1cosA) = (1cosA)/(1cosA) = 1+cosA (after cancellation). Thus both sides equal [--] + cosA where defined. Domain: require cosA [--] and [--] cosA [--] for direct cancellation; equality's simplified form 1+cosA holds when expressions are defined. (Abhi Garg Classes)" [YouTube Link](https://youtube.com/watch?v=s0cT6zafPKM) 2025-10-10T04:54Z [---] followers, [--] engagements "Sum of integers divisible by [--] between [---] and [---] Class [--] Maths #AP In this video we solve an important Arithmetic Progression (AP) problem: ❓ Find the sum of integers between [---] and [---] that are (i) divisible by [--] (ii) not divisible by [--] This type of question is frequently asked in Class [--] Maths exams (AP Chapter NCERT/Exemplar) and is super useful for board exam preparation. Watch till the end to understand the step-by-step solution ✨ #Maths #AP #ArithmeticProgression #Class10 #NCERT #ExamPrep #MathsTricks #Algebra" [YouTube Link](https://youtube.com/watch?v=s73HyHaYXi0) 2025-09-02T04:41Z [---] followers, [--] engagements "How many terms needed to get [---] from AP [----] [--]. #WhatIsN #FindTerms #APSolved In this video we solve this Arithmetic Progression problem: "How many terms of the AP [----] [--]. must be taken so that their sum is 636" We use the AP sum formula: S = n/2 2a + (n - 1)d to find the number of terms (n). Perfect for CBSE Class [--] students and those preparing for competitive exams. #FindNumberOfTerms #HowManyTerms #WhatIsN #APSolved #ArithmeticProgression #NCERTQuestion #CBSEMaths #Class10Maths #MathHelp #APFormula #MathShorts" [YouTube Link](https://youtube.com/watch?v=wSDvE_DCgKA) 2025-07-31T05:56Z [---] followers, [---] engagements "NCERT Volume Check Spherical Vessel + Cylindrical Neck Class [--] Maths Chapter [--] Solution 🎯 Can you calculate the precise volume of this tricky spherical vessel Question: A spherical glass vessel has a cylindrical neck [--] cm long [--] cm in diameter; the diameter of the spherical part is [---] cm. By measuring the amount of water it holds a child finds its volume to be [---] cm. Check whether she is correct taking the above as the inside measurements and = [----]. Concept: This question requires calculating the volume of a composite solid by adding the volume of a cylinder (rH) and the volume of a" [YouTube Link](https://youtube.com/watch?v=-8cw0wxNOuI) 2025-12-12T05:02Z [---] followers, [--] engagements "Cylinder with Conical Cavity Total Surface Area (Answer: [--] cm) Class [--] Mensuration Problem: From a solid cylinder (height [---] cm diameter [---] cm) a cone of same height and diameter is removed. Find the total surface area of the remaining solid. Solution summary: r = [---] cm h = [---] cm cone slant l = [---] cm. Cylinder lateral = 2rh = [----]. Bottom face = r = [----]. Inner cone lateral = rl = [----]. Total = [---] [-----] cm **18 cm (nearest cm)**. #Mensuration #SurfaceArea #Class10Maths #Cylinder #Cone #Geometry #AbhiGargClasses" [YouTube Link](https://youtube.com/watch?v=-kBAkPHHQ-k) 2025-11-23T05:28Z [---] followers, [---] engagements "Find sum of first n terms when S = [--] & S = [---] #FindSn #APSum #Class10Maths In this video we solve: "If the sum of first [--] terms of an AP is [--] and that of [--] terms is [---] find the sum of first n terms." We use the formula: S = n/2 (2a + (n - 1)d) and simplify using given values to find a general expression for S. A perfect AP Sum problem from CBSE Class [--] Arithmetic Progression chapter. #FindSn #APSum #ArithmeticProgression #APFormula #CBSEMaths #NCERTSolution #Class10Maths #MathsQuestion #WhatIsSn #HowToFindSum" [YouTube Link](https://youtube.com/watch?v=08Pqxr6lpFk) 2025-08-01T05:06Z [---] followers, [---] engagements "CSA of Cone = CSA of Hemisphere Find the Height (h) in terms of Radius (r) Class [--] Mensuration 🔥 Don't let solid geometry formulas confuse you This is a classic CBSE/ICSE board exam question dealing with the relationship between a cone and a hemisphere. Question: A solid consists of a hemisphere at the bottom and a cone above it both having the same base radius r. If the curved surface areas (CSA) of the hemisphere and cone are equal then find the height (h) of the conical part. Concept Explained: We set the fundamental formulas for Curved Surface Area (CSA) of a hemisphere (2r) and a cone" [YouTube Link](https://youtube.com/watch?v=0MrNLKGbkAI) 2026-01-07T04:34Z [---] followers, [---] engagements "Area of Shaded Path TRICK Mensuration Geometry Problem Solved Step-by-Step (Class [--] & 10) 🔥 Quick and easy way to solve complex area problems This video breaks down a common Mensuration question often seen in Class [--] and Class [--] exams. ❓ The Question: Find the area of the shaded region in Fig. [----]. Outer rectangle: [--] m x [--] m. Inner gaps: [--] m (sides) [--] m (top/bottom). ✍ Concept Explained: To find the area of a uniform path or shaded border surrounding an inner figure simply find the difference between the area of the outer figure and the area of the inner figure. This 'area subtraction'" [YouTube Link](https://youtube.com/watch?v=0zXCN40IRxQ) 2026-01-22T04:52Z [---] followers, [--] engagements "Rocket Maths Solved 🚀 Find Surface Area & Volume of Cylinder and Cone Composite Solids (Class 10) Welcome to ABHI GARG CLASSES In this detailed session for Class [--] Mathematics students we tackle a crucial problem from the chapter on Surface Area and Volume of Composite Solids. This question is frequently asked in CBSE and ICSE board exams. ***The Question:*** A rocket is in the form of a right circular cylinder closed at the lower end and surmounted by a cone with the same radius as that of the cylinder. The diameter and height of the cylinder are [--] cm and [--] cm respectively. If the slant" [YouTube Link](https://youtube.com/watch?v=24Glw2S-JRI) 2025-12-03T06:26Z [---] followers, [---] engagements "Hour Hand Problem SOLVED Area Swept by Clock Hand in [--] Minutes Class [--] Maths 🔥 Catchy Hook: Stop guessing the angle Learn the precise formula for clock problems and master the application of the Area of a Sector formula (A = (/360) R). Question: The hour hand of a clock is [--] cm long. The area swept by it between 11:20 am and 11:55 am is calculated step-by-step. Concept: We utilize the fundamental angular speed of the hour hand (0.5 per minute) to find the angle () and then apply the sector area formula. This is an essential concept for Class [--] Board exams 📌 Location: Abhi Garg Classes" [YouTube Link](https://youtube.com/watch?v=2XOC0WwQ5AM) 2026-01-20T01:48Z [---] followers, [---] engagements "🔥 Cube Carving Problem Surface Area of Remaining Solid (Cube + Hemispherical Depression) Class [--] Welcome to Abhi Garg Classes 🔥 Are you struggling with surface area problems involving combined solids Question: A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter 'l' of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid. In this video we break down this tricky carving problem step-by-step. The key concept is understanding that the external surface area changes: we lose the area of the circular" [YouTube Link](https://youtube.com/watch?v=30u60F_OCFw) 2025-12-27T05:06Z [---] followers, [--] engagements "DOUBLE CONE Surface Area TRICK (r=8 h=15) Class [--] Maths CBSE Surface Area and Volume Question 🔥 Welcome to ABHI GARG CLASSES In this essential Class [--] Mathematics tutorial we tackle a critical problem from the Surface Area and Volume chapter involving composite solids. This is a common high-scoring question in CBSE/ICSE board exams. 📚 Question Covered: Two cones with the same base radius (r = [--] cm) and height (h = [--] cm) are joined together along their bases. Find the total surface area of the shape so formed. Key Concepts You Will Learn: [--]. Identifying the correct formula for the TSA of" [YouTube Link](https://youtube.com/watch?v=3bIO0222-Kc) 2025-11-29T05:40Z [---] followers, [--] engagements "CLASS [--] MATHS: Surface Area of Hemisphere Mounted by Cylinder Mensuration Full Solution CBSE 🔥 Mastering Mensuration: Solve the toughest Surface Area problems effortlessly This video breaks down a crucial Class [--] question involving a vessel formed by a hollow hemisphere and a hollow cylinder. Question: A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. The diameter of the hemisphere is [--] cm and the total height of the vessel is [--] cm. Find the inner surface area of the vessel. Concept Explained: Learn why we calculate the Curved Surface Area (CSA) and how to" [YouTube Link](https://youtube.com/watch?v=5-0ppqWcfec) 2025-12-31T05:14Z [---] followers, [--] engagements "How to Find the Volume of the LARGEST Cone Carved from a Cube (Side [--] cm) Class 9/10 Geometry 🔥 Geometry Visualisation Challenge 🔥 Question: The volume of the largest right circular cone that can be carved out from a solid cube of side length [--] cm is: This video explains the crucial relationship between the dimensions of the base object (the cube) and the derived object (the cone). For the largest possible fit the cone's height and diameter must equal the cube's side length. Perfect for quick revision of Surface Areas and Volumes Join us at Abhi Garg Classes Sector [--] Chandigarh for" [YouTube Link](https://youtube.com/watch?v=52fJ0v7YsTI) 2026-01-14T05:17Z [---] followers, [--] engagements "Hemispherical Bowl Volume Trick Find Volume of Steel Used Surface Area & Volume Class [--] 🎯 Quick Math Challenge Can you calculate the exact volume of steel used in this hemispherical bowl Question: A hemispherical bowl is made of steel of thickness [----] cm. The inner radius of the bowl is [--] cm. The volume of steel used (in cu cm) is: In this detailed video Abhi Garg explains the key concept for hollow solids: finding the volume of material by calculating V_outer - V_inner. This is an essential high-scoring topic for CBSE Class [--] and Class [--] geometry exams. Need expert guidance to ace your" [YouTube Link](https://youtube.com/watch?v=59L1R9AX3_E) 2026-01-11T14:37Z [---] followers, [--] engagements "TSA of Cone Mounted on Hemisphere Class [--] Maths Surface Area and Volume (NCERT ) Don't lose marks on composite solids Learn the simplest method to find the Total Surface Area (TSA) of a toy combining a cone and a hemisphere. Question: A toy is in the form of a cone of radius [---] cm mounted on a hemisphere of the same radius. The total height of the toy is [----] cm. Find the total surface area of the toy. Concept Explained: Remember for the total surface area of a composite solid you only add the exposed Curvature Surface Areas (CSA). Finding the slant height (l) using the Pythagorean theorem" [YouTube Link](https://youtube.com/watch?v=5R5yHuLWxt8) 2026-01-01T05:13Z [---] followers, [--] engagements "Angle [--] [--] after [--] m Find tree height & river width (Answer: [-----] m [--] m) #Trigonometry Question: From the bank angle of elevation to a tree on opposite bank = [--]. After moving [--] m away angle becomes [--]. Find the tree's height and the river width. Solution summary: Let river width = d. From tan60 = h/d h = d3. From tan30 = h/(d+40) h = (d+40)/3. Solving gives d = [--] m and h = [---] [-----] m. Final: Height = [-----] m Width = [-----] m. #Trigonometry #HeightAndDistance #Class10Maths #NCERT #MathsWithAbhi #QuickSolution" [YouTube Link](https://youtube.com/watch?v=5cPsz6HR2oE) 2025-11-21T05:29Z [---] followers, [--] engagements "NCERT Volume Check Spherical Vessel + Cylindrical Neck Class [--] Maths Chapter [--] Solution 🎯 Can you calculate the precise volume of this tricky spherical vessel Question: A spherical glass vessel has a cylindrical neck [--] cm long [--] cm in diameter; the diameter of the spherical part is [---] cm. By measuring the amount of water it holds a child finds its volume to be [---] cm. Check whether she is correct taking the above as the inside measurements and = [----]. Concept: This question requires calculating the volume of a composite solid by adding the volume of a cylinder (rH) and the volume of a" [YouTube Link](https://youtube.com/watch?v=5quoNUDrKwg) 2025-12-12T05:03Z [---] followers, [--] engagements "FIND THE HEIGHT Volume of Cylinder and Hemispherical Dome Problem Class [--] Mensuration CBSE 🔥 Geometry Alert Don't miss this classic volume problem crucial for your board exams Question: A building is in the form of a cylinder surmounted by a hemispherical dome. The base diameter (D) of the dome is equal to 2/3 of the total height (H) of the building. Find the height of the building if it contains [--] 1/21 m of air. Concept Explained: We simplify the complex relationship by expressing both the cylinder's height (h) and the radius (R) in terms of the Total Height (H). This reduces the entire" [YouTube Link](https://youtube.com/watch?v=6F1ubLxHYv0) 2025-12-14T05:04Z [---] followers, [---] engagements "🔥 Cube Carving Problem Surface Area of Remaining Solid (Cube + Hemispherical Depression) Class [--] Welcome to Abhi Garg Classes 🔥 Are you struggling with surface area problems involving combined solids Question: A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter 'l' of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid. In this video we break down this tricky carving problem step-by-step. The key concept is understanding that the external surface area changes: we lose the area of the circular" [YouTube Link](https://youtube.com/watch?v=6V_-KmnxIV0) 2025-12-27T05:08Z [---] followers, [---] engagements "Area of Shaded Region: Square Inscribed in a Quadrant Class [--] CBSE Geometry Mastery 🔥 Quick Geometry Challenge Can you find the area of the shaded region when a square is inscribed in a quarter circle Question: A square OABC is inscribed in a quadrant OPBQ. If the side OA = [--] cm find the area of the shaded region. (Use = 3.14). This video walks you through the crucial concept: realizing that the diagonal of the inscribed square serves as the radius of the quadrant. We use the Pythagorean theorem to find R easily simplifying the calculation of the quadrant's area. 📍 Visit Abhi Garg Classes" [YouTube Link](https://youtube.com/watch?v=6zEYwSqvRZE) 2026-01-21T07:15Z [---] followers, [--] engagements "💊 Surface Area of a Medicine Capsule Combined Solids Class [--] Maths NCERT Ex [----] Q3 Solution Stop scrolling Can you calculate how much material is needed to coat this standard medicine capsule Question: A medicine capsule is in the shape of a cylinder with two hemispheres stuck to each of its ends. The length of the entire capsule is [--] mm and the diameter of the capsule is [--] mm. Find its surface area. This problem involves finding the total surface area of a composite figure: a cylinder capped by two hemispheres. Remember you only calculate the curved surface area (CSA) of the individual" [YouTube Link](https://youtube.com/watch?v=7-2PQU3c31U) 2025-12-28T04:54Z [---] followers, [---] engagements "VOLUME OF WOOD Cuboid with Conical & Cubical Depressions Surface Areas and Volumes Class [--] Welcome to ABHI GARG CLASSES Master the tricky questions from Class [--] Mathematics. This video focuses on a crucial question from the Surface Areas and Volumes chapter often featured in CBSE and ICSE board exams. 🎯 The Question: A wooden pen stand is shaped like a cuboid (length = [--] cm width = [--] cm height = [--] cm). It has four identical conical depressions (radius r = [---] cm depth h = [---] cm) and one cubical depression (edge a = [--] cm) for holding pens and pins. Find the volume of the wood used in the" [YouTube Link](https://youtube.com/watch?v=7BZA_9LESc4) 2025-12-05T05:45Z [---] followers, [---] engagements "Hemisphere TSA Ratio Secret Surface Area & Volume Class [--] Maths Quick Trick Are you often confused about the difference between Curved Surface Area and Total Surface Area of a hemisphere This quick problem will cement the concept for you ❓ QUESTION: The ratio of total surface area of a solid hemisphere to the square of its radius is: CONCEPT EXPLAINED: The total surface area of a SOLID hemisphere is 3r because it includes both the curved part and the flat circular base. Setting up the ratio (3r / r) simplifies beautifully to [--] : [--]. Master Mathematics and Science from Class 8th to 12th. Join" [YouTube Link](https://youtube.com/watch?v=8RzH_99oylg) 2026-01-15T04:50Z [---] followers, [---] engagements "Industrial Shed Volume Calculation Cuboid & Half Cylinder Volume Class [--] Maths Application 🎯 Can you solve this real-world volume problem We calculate the total air capacity of an industrial shed shaped like a cuboid surmounted by a half cylinder and then subtract the space occupied by machinery and workers. QUESTION: Shanta runs an industry in a shed which is in the shape of a cuboid surmounted by a half cylinder. If the base of the shed is of dimension [--] m x [--] m and the height of the cuboidal portion is [--] m find the volume of air that the shed can hold. Further suppose the machinery in" [YouTube Link](https://youtube.com/watch?v=8W8EhUaZP7s) 2025-12-15T05:37Z [---] followers, [---] engagements "Sphere vs. [--] Hemispheres: Surface Area Ratio TRICK (4r vs 6r Explained) Class [--] Math 🚨 Stop guessing the surface area ratio When a solid sphere is cut into two hemispheres the total surface area changes drastically. This is a crucial concept for CBSE Class [--] and [--] board exams. ❓ The Question: A solid sphere is cut exactly into two hemispheres. What is the ratio of the surface area of the original sphere to the total combined surface area of the two resulting hemispheres 💡 Concept Insight: Remember that the total surface area of a hemisphere includes the curved area (2r) plus the new flat" [YouTube Link](https://youtube.com/watch?v=8pBWESOcWks) 2026-01-13T04:29Z [---] followers, [--] engagements "Volume of Solid (Cone on Hemisphere) Class [--] Maths Board Exam Question Quick Geometry Solution Can you solve this Class [--] geometry problem in [--] seconds Its simpler than you think Question: A solid is in the shape of a cone standing on a hemisphere with both their radii being equal to [--] cm and the height of the cone is equal to its radius. Find the volume of the solid in terms of pi. Concept: Mastering the volume of composite solids involves breaking down the structure into standard shapes (like cones and hemispheres) and applying their respective formulas. The key here is realizing that" [YouTube Link](https://youtube.com/watch?v=8xT7dKRMPoM) 2025-12-26T04:59Z [---] followers, [--] engagements "Prove V = (131 / 96) R Volume of Combined Solids Sphere & Cylinder Math Proof (Class 10) Stop struggling with complicated Mensuration proofs This question beautifully combines the volumes of a sphere and a cylinder requiring careful algebraic substitution. We break down the steps to prove that the total volume is (131 / 96) R. Question: A spherical glass vessel has a cylindrical neck whose radius (r) is R/8 and height (h) is 2R. Prove V = (131 / 96) R. This concept is crucial for scoring high marks in surface area and volume chapters. Mastering substitution and fractions is key 📍 Find expert" [YouTube Link](https://youtube.com/watch?v=9ZpeznaP0f0) 2026-01-11T05:10Z [---] followers, [--] engagements "Ladder slides from [--] to [--] Find foot distance (Answer: [--] m) #Trigonometry Problem: A ladder reaches [--] m on a wall at [--]. After pulling its foot out it makes [--] with the ground. Find the distance of the foot from the wall. Solution summary: Let ladder length = L. From sin60 = 5/L L = 10/3. At [--] horizontal distance = Lcos30 = (10/3)(3/2) = [--] m. Final answer: [--] m. #Trigonometry #HeightAndDistance #LadderProblem #Class10Maths #MathsShorts #AbhiGargClasses" [YouTube Link](https://youtube.com/watch?v=B5pYmBdjjm8) 2025-11-16T05:47Z [---] followers, [--] engagements "CLASS [--] MATHS: Surface Area of Hemisphere Mounted by Cylinder Mensuration Full Solution CBSE 🔥 Mastering Mensuration: Solve the toughest Surface Area problems effortlessly This video breaks down a crucial Class [--] question involving a vessel formed by a hollow hemisphere and a hollow cylinder. Question: A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. The diameter of the hemisphere is [--] cm and the total height of the vessel is [--] cm. Find the inner surface area of the vessel. Concept Explained: Learn why we calculate the Curved Surface Area (CSA) and how to" [YouTube Link](https://youtube.com/watch?v=CqZbWwltZAA) 2025-12-31T05:14Z [---] followers, [---] engagements "MASSIVE IRON POLE WEIGHT CALCULATION (892 kg) Class [--] Maths Surface Area & Volume Hook: Ready to calculate the weight of this massive industrial iron pole just using geometry Let's find out Question: A solid iron pole consists of a cylinder of height [---] cm and base diameter [--] cm which is surmounted by another cylinder of height [--] cm and radius [--] cm. Find the mass of the pole given that [--] cm of iron has approximately [--] g mass. (Use = 3.14). Concept: This problem requires finding the volume of two cylinders and adding them up (Volume of Combined Solids). We then use the given density (mass" [YouTube Link](https://youtube.com/watch?v=DBcr6fgiL20) 2025-12-20T07:32Z [---] followers, [--] engagements "Open Box Volume & Weight Problem Solved Critical Class 10/12 Mensuration Question 🎯 STOP losing marks on Mensuration The 'Open Box' problem has one subtle trick you MUST know regarding internal height. We solve this complete volume and weight question step-by-step. ❓ Question: How many cubic centimetres of iron is required to construct an open box whose external dimensions are [--] cm [--] cm and [----] cm provided the thickness of the iron is [---] cm. If one cubic cm of iron weighs [---] g find the weight of the box. 💡 Concept Focus: When calculating the internal dimensions of an open box with" [YouTube Link](https://youtube.com/watch?v=DOdUf2j6wUk) 2025-12-09T08:31Z [---] followers, [--] engagements "MELTED IRON BLOCK to [---] METER PIPE 🤯 Class [--] Maths Board Exam Question Volume & Recasting Welcome to ABHI GARG CLASSES In this essential Class [--] Mathematics video we solve a challenging Mensuration problem involving the concept of 'Recasting Solids'. When a solid is melted and recast the total volume remains constant. This question tests your ability to handle complex unit conversions and the formula for the volume of a hollow cylinder. FULL QUESTION: A solid iron cuboidal block of dimensions [---] m x [---] m x [--] m is recast into a hollow cylindrical pipe of internal radius [--] cm and" [YouTube Link](https://youtube.com/watch?v=EnrXLhd-An0) 2025-12-02T05:08Z [---] followers, [--] engagements "Stool Design: Find Leg Length & Step Lengths Practical Trigonometry #Maths Problem: A stool has a square top of side [---] m at height [---] m. Each leg is inclined at [--] to the ground. Find (1) the length of each leg and (2) lengths of two steps fixed at equal vertical intervals (heights [---] m and [---] m). Solution summary: [--]. Leg length L: vertical component = Lsin60 = [---] L = [---] / sin60 = [---] / (3/2) = [--] [-----] m. [--]. At a level y above ground horizontal distance between opposite legs = [---] + 2(1.5 y)/3. - For y = [---] m: step length = [---] + 2(1.0)/3 = [---] + 2/3 [------] m. - For y = [---] m: step" [YouTube Link](https://youtube.com/watch?v=F5T-ifa4OTA) 2025-11-02T05:04Z [---] followers, [--] engagements "MELTED IRON BLOCK to [---] METER PIPE 🤯 Class [--] Maths Board Exam Question Volume & Recasting Welcome to ABHI GARG CLASSES In this essential Class [--] Mathematics video we solve a challenging Mensuration problem involving the concept of 'Recasting Solids'. When a solid is melted and recast the total volume remains constant. This question tests your ability to handle complex unit conversions and the formula for the volume of a hollow cylinder. FULL QUESTION: A solid iron cuboidal block of dimensions [---] m x [---] m x [--] m is recast into a hollow cylindrical pipe of internal radius [--] cm and" [YouTube Link](https://youtube.com/watch?v=HYLgZkshwPE) 2025-12-02T05:09Z [---] followers, [--] engagements "Sphere Dropped in Cylinder: How to Calculate Water Level Rise (Surface area and Volume Class 10) 🎯 Catchy Hook: Can the size of the container really determine how much water rises Yes and the math behind it is simple geometry Question: A sphere of diameter [--] cm is dropped into a cylindrical vessel of diameter [--] cm partly filled with water. If the sphere is completely submerged what is the rise in the water level Concept: We use the fundamental principle of volume displacement: the volume of the sphere is equal to the volume of the cylindrical column of water that rises. This is a must-know" [YouTube Link](https://youtube.com/watch?v=JSLGFX5m2_A) 2026-01-18T06:01Z [---] followers, [--] engagements "SURFACE AREA of Cuboid Formed by Joining Two Cubes Mensuration Class [--] CBSE (Solved in [--] Steps) 🚀 INSTANT MATH LESSON Are you struggling with Mensuration Watch how we solve this classic problem involving joining two cubes and finding the new surface area Question: Two cubes each of volume [--] cm are joined end to end. Find the surface area of the resulting cuboid. Concept: When two identical cubes (side 'a') are joined only the length changes (becomes 2a) while the breadth and height remain 'a'. The resulting shape is a cuboid. We then apply the cuboid surface area formula: TSA = 2(LB + BH +" [YouTube Link](https://youtube.com/watch?v=Jl7JEeX_t9I) 2025-12-30T04:29Z [---] followers, [---] engagements "VOLUME OF WOOD Cuboid with Conical & Cubical Depressions Surface Areas and Volumes Class [--] Welcome to ABHI GARG CLASSES Master the tricky questions from Class [--] Mathematics. This video focuses on a crucial question from the Surface Areas and Volumes chapter often featured in CBSE and ICSE board exams. 🎯 The Question: A wooden pen stand is shaped like a cuboid (length = [--] cm width = [--] cm height = [--] cm). It has four identical conical depressions (radius r = [---] cm depth h = [---] cm) and one cubical depression (edge a = [--] cm) for holding pens and pins. Find the volume of the wood used in the" [YouTube Link](https://youtube.com/watch?v=LIIrh_JFA5c) 2025-12-05T05:45Z [---] followers, [--] engagements "🤯 [--] Minute Water Level Rise Challenge (Cylinder Flow) #trigonometricalidentities #surfacearea #edu [--]. Catchy Hook: Can you solve this classic Surface Area and Volume flow rate problem in under [--] minutes Let's check your speed and accuracy [--]. The Question Text: Water flows through a cylindrical pipe whose inner radius is [--] cm at the rate of [--] cm/sec into an empty cylindrical tank the radius of whose base is [--] cm. What is the rise of water level (H) in the tank in half an hour [--]. Brief Concept Explanation: The key to solving flow rate problems is equating the volume flowing out of the pipe" [YouTube Link](https://youtube.com/watch?v=MiYdYt_8r6A) 2025-12-07T05:03Z [---] followers, [---] engagements "CSA of Cone = CSA of Hemisphere Find the Height (h) in terms of Radius (r) Class [--] Mensuration 🔥 Don't let solid geometry formulas confuse you This is a classic CBSE/ICSE board exam question dealing with the relationship between a cone and a hemisphere. Question: A solid consists of a hemisphere at the bottom and a cone above it both having the same base radius r. If the curved surface areas (CSA) of the hemisphere and cone are equal then find the height (h) of the conical part. Concept Explained: We set the fundamental formulas for Curved Surface Area (CSA) of a hemisphere (2r) and a cone" [YouTube Link](https://youtube.com/watch?v=MwVD47NgM9I) 2026-01-07T04:33Z [---] followers, [--] engagements "Surface Area TRICK: When Cylinder Height is Halved Combined Solids Geometry Problem (Class 10/12) Don't let combined solids confuse you This is a classic surface area problem often seen in board exams testing your understanding of Curved Surface Area (CSA). THE QUESTION: A solid is made by placing a hemisphere on top of a cylinder. Full question text from content. CONCEPT EXPLAINED: We calculate the Total Surface Area (TSA) by summing the Curved Surface Areas (CSA) of the cylinder and the hemisphere plus the base area of the cylinder. Crucially the circular area where the two solids join is" [YouTube Link](https://youtube.com/watch?v=NKaznZTdNO8) 2026-01-06T05:40Z [---] followers, [--] engagements "Surface Area of Composite Solids Cone and Hemisphere TSA TRICK Assertion Reason Class [--] Maths Stop losing marks on tricky composite solid questions 🛑 Today we solve a fundamental Assertion-Reason problem related to the Total Surface Area (TSA) of a cone mounted on a hemisphere. Question: Assertion (A): TSA = CSA (Hemisphere) + CSA (Cone). Reason (R): The flat faces are joined internally and not exposed. Concept Explained: When two solids are joined the surface area exposed is only the sum of their external curved areas. The joined planar faces are hidden internally making this a common trap" [YouTube Link](https://youtube.com/watch?v=OpB9y1uH6v4) 2026-01-09T14:34Z [---] followers, [--] engagements "Cylinder & Cone Volume Ratio TRICK If Volume_cyl = Volume_cone What is h1:h2 Class [--] Maths Ready for a quick geometry challenge This question tests your fundamental understanding of 3D shapes and volumes (Cylinder and Cone). The Question: A cap is cylindrical in shape surmounted by a conical top. If the volume of the cylindrical part is equal to that of the conical part then find the ratio of the height of the cylindrical part to the height of the conical part. Concept: The key lies in understanding the volume formulas V_cyl = rh and V_cone = (1/3)rh. Setting them equal allows us to find the" [YouTube Link](https://youtube.com/watch?v=P5IzbT2hjAQ) 2026-01-16T05:10Z [---] followers, [--] engagements "Geometry FAIL Assertion-Reason on Sphere & Cylinder Solved (A is True R is False)Class [--] Maths [--]. Stop the confusion This tricky Assertion-Reason question tests if you know the exact formulas and constraints in 3D geometry. Watch how we analyze the 'just encloses' condition and identify the critical error in the Reason. [--]. Question: Assertion (A): A circular cylinder of radius r and height h (h Greater than 2r) just encloses a sphere then the diameter of the sphere is 2r. Reason (R): The surface area of the sphere is 2r(h + r). [--]. We confirm the sphere's maximum diameter is 2r based on the" [YouTube Link](https://youtube.com/watch?v=QCOfpqj8tCI) 2026-01-04T05:10Z [---] followers, [---] engagements "Area of Shaded Region between Two Squares Geometry Class 9/10 CBSE Solved Problem 💡 Can you solve this geometry puzzle We're finding the shaded area quickly and accurately using simple area subtraction **Question:** Find the area of the shaded region. The figure consists of a large square (side [--] cm) containing a smaller concentric unshaded square. The margin is [--] cm uniformly. **Concept:** This problem utilizes the fundamental principle of area subtraction: Area_Shaded = Area_Outer - Area_Inner. Its essential for Class [--] and [--] geometry topics. Ready to ace your Maths exams Join Abhi Garg" [YouTube Link](https://youtube.com/watch?v=QTXuGuLF1lI) 2026-01-26T08:02Z [---] followers, [--] engagements "Cloud & Its Image Problem Angles [--] & [--] Height of Cloud = [---] m #Trigonometry QUESTION: A cloud is observed from a point [---] m above a lake. Angle of elevation = [--] angle of depression of its image = [--]. Find the height of the cloud. SOLUTION: Let cloud height above lake = H. Image lies H below lake observer to image = H + [---]. Horizontal distance = x. tan30 = (H100)/x = 1/3 tan60 = (H+100)/x = [--] Divide equations (H+100)/(H100) = [--] Solve H = [---] m. Final Answer: Height of cloud = **200 m**. #Trigonometry #HeightAndDistance #Class10Maths #NCERT #MathsWithAbhi #CloudProblem #MathsShorts" [YouTube Link](https://youtube.com/watch?v=Sq4u1WRIQeY) 2025-11-14T06:17Z [---] followers, [---] engagements "Ladder slides from [--] to [--] Find foot distance (Answer: [--] m) #Trigonometry Problem: A ladder reaches [--] m on a wall at [--]. After pulling its foot out it makes [--] with the ground. Find the distance of the foot from the wall. Solution summary: Let ladder length = L. From sin60 = 5/L L = 10/3. At [--] horizontal distance = Lcos30 = (10/3)(3/2) = [--] m. Final answer: [--] m. #Trigonometry #HeightAndDistance #LadderProblem #Class10Maths #MathsShorts #AbhiGargClasses" [YouTube Link](https://youtube.com/watch?v=TR_VwuL097w) 2025-11-16T05:47Z [---] followers, [---] engagements "Surface Area TRICK: When Cylinder Height is Halved Combined Solids Geometry Problem (Class 10/12) Don't let combined solids confuse you This is a classic surface area problem often seen in board exams testing your understanding of Curved Surface Area (CSA). THE QUESTION: A solid is made by placing a hemisphere on top of a cylinder. Full question text from content. CONCEPT EXPLAINED: We calculate the Total Surface Area (TSA) by summing the Curved Surface Areas (CSA) of the cylinder and the hemisphere plus the base area of the cylinder. Crucially the circular area where the two solids join is" [YouTube Link](https://youtube.com/watch?v=U96Z2K_VJuk) 2026-01-06T05:36Z [---] followers, [--] engagements "Juice Seller Problem Apparent vs. Actual Capacity Volume of Cylinder & Hemisphere (Class 10) Don't fall for the juice seller's trick Learn the crucial difference between apparent and actual capacity in this detailed volume calculation. ❓ The Question: A cylindrical glass has an inner diameter of [--] cm and a height of [--] cm. The bottom has a raised hemispherical portion which reduces the capacity. Find the apparent capacity and the actual capacity. ( = 3.14). 💡 Concept Explained: This problem combines the volume formulas for a cylinder (V = rh) and a hemisphere (V = (2/3)r). Actual capacity is" [YouTube Link](https://youtube.com/watch?v=UiQznzfM1Qs) 2025-12-13T06:01Z [---] followers, [---] engagements "SURFACE AREA of Cuboid Formed by Joining Two Cubes Mensuration Class [--] CBSE (Solved in [--] Steps) 🚀 INSTANT MATH LESSON Are you struggling with Mensuration Watch how we solve this classic problem involving joining two cubes and finding the new surface area Question: Two cubes each of volume [--] cm are joined end to end. Find the surface area of the resulting cuboid. Concept: When two identical cubes (side 'a') are joined only the length changes (becomes 2a) while the breadth and height remain 'a'. The resulting shape is a cuboid. We then apply the cuboid surface area formula: TSA = 2(LB + BH +" [YouTube Link](https://youtube.com/watch?v=VLtVX7Kk2ww) 2025-12-30T04:28Z [---] followers, [--] engagements "Sphere vs. [--] Hemispheres: Surface Area Ratio TRICK (4r vs 6r Explained) Class [--] Math 🚨 Stop guessing the surface area ratio When a solid sphere is cut into two hemispheres the total surface area changes drastically. This is a crucial concept for CBSE Class [--] and [--] board exams. ❓ The Question: A solid sphere is cut exactly into two hemispheres. What is the ratio of the surface area of the original sphere to the total combined surface area of the two resulting hemispheres 💡 Concept Insight: Remember that the total surface area of a hemisphere includes the curved area (2r) plus the new flat" [YouTube Link](https://youtube.com/watch?v=VMBW9NLH3kw) 2026-01-13T04:30Z [---] followers, [---] engagements "Aeroplane Depression Angles [--] & [--] Height of Plane = [---] m #Trigonometry QUESTION: From an aeroplane angles of depression to two consecutive kilometre stones (1 km apart) are [--] and [--]. Find the height of the aeroplane. SOLUTION: Let height = h. tan60 = h / AS AS = h/3 tan30 = h / AS AS = 3h AS AS = [----] 3h h/3 = [----] 2h/3 = [----] h = [----] = [---] m (approx) Final answer: Height = **865 m** #Trigonometry #HeightAndDistance #Class10Maths #NCERT #MathsShorts #AbhiGargClasses" [YouTube Link](https://youtube.com/watch?v=WLprLCV5At4) 2025-11-15T05:43Z [---] followers, [--] engagements "Cylinder + Hemisphere Volume Problem Building Height = [--] m #Mensuration SEO keywords: cylinder hemisphere volume building height problem Question: A building is a cylinder surmounted by a hemispherical dome and contains [--] 19/21 m of air. If the internal diameter of the dome equals the total height above the floor find the height of the building. Solution summary: Let dome radius = r and cylinder height = r (from diameter = total height). Total volume = (5/3)r = 880/21. Using = 22/7 gives r = [--] m. Total height = 2r = [--] m. Final Answer: [--] m. #Mensuration #VolumeProblems #Class10Maths" [YouTube Link](https://youtube.com/watch?v=WQEG0unoLFg) 2025-11-24T05:04Z [---] followers, [--] engagements "Cylinder & Cone Volume Ratio TRICK If Volume_cyl = Volume_cone What is h1:h2 Class [--] Maths Ready for a quick geometry challenge This question tests your fundamental understanding of 3D shapes and volumes (Cylinder and Cone). The Question: A cap is cylindrical in shape surmounted by a conical top. If the volume of the cylindrical part is equal to that of the conical part then find the ratio of the height of the cylindrical part to the height of the conical part. Concept: The key lies in understanding the volume formulas V_cyl = rh and V_cone = (1/3)rh. Setting them equal allows us to find the" [YouTube Link](https://youtube.com/watch?v=WpZYT8d30_k) 2026-01-16T05:09Z [---] followers, [--] engagements "💊 Surface Area of a Medicine Capsule Combined Solids Class [--] Maths NCERT Ex [----] Q3 Solution Stop scrolling Can you calculate how much material is needed to coat this standard medicine capsule Question: A medicine capsule is in the shape of a cylinder with two hemispheres stuck to each of its ends. The length of the entire capsule is [--] mm and the diameter of the capsule is [--] mm. Find its surface area. This problem involves finding the total surface area of a composite figure: a cylinder capped by two hemispheres. Remember you only calculate the curved surface area (CSA) of the individual" [YouTube Link](https://youtube.com/watch?v=XCvyvM8ZGAk) 2025-12-28T04:53Z [---] followers, [--] engagements "Flow Rate vs Volume of Cone Maths Mensuration Problem Solving (Class 10) 🚨 How long does it take for a pipe to fill a conical vessel It's a classic 3D geometry question Question: Water flows at the rate of [--] m/minute through a cylindrical pipe [--] mm in diameter. How long would it take to fill a conical vessel whose diameter at the base is [--] cm and depth is [--] cm This video breaks down the concept of relating the volume flow rate (area velocity) of a cylinder to the total volume of a cone. Ensure all units are consistent (cm or m) before calculating. 📍 Find the best coaching in Sector 20" [YouTube Link](https://youtube.com/watch?v=Y39WD1Z2_Do) 2025-12-11T04:49Z [---] followers, [--] engagements "FIND THE HEIGHT Volume of Cylinder and Hemispherical Dome Problem Class [--] Mensuration CBSE 🔥 Geometry Alert Don't miss this classic volume problem crucial for your board exams Question: A building is in the form of a cylinder surmounted by a hemispherical dome. The base diameter (D) of the dome is equal to 2/3 of the total height (H) of the building. Find the height of the building if it contains [--] 1/21 m of air. Concept Explained: We simplify the complex relationship by expressing both the cylinder's height (h) and the radius (R) in terms of the Total Height (H). This reduces the entire" [YouTube Link](https://youtube.com/watch?v=YeATJmThrTA) 2025-12-14T05:03Z [---] followers, [--] engagements "SILO CASE STUDY 😱 Class [--] Maths Surface Area & Volume Guaranteed Question Slant Height & Cap Welcome to ABHI GARG CLASSES 🏆 Today we tackle a high-probability Case Study question on Surface Area and Volume crucial for your Class [--] CBSE Board Exams. This problem involves calculating the dimensions curved surface area and total capacity of a composite solida silo shaped like a cylinder surmounted by a cone. **The Full Question:** Farmer Girdhar is building a metallic silo (cylinder mounted by a cone). Conical Part: Radius (r) = [---] m Height ($h_c$) = [--] m. Cylindrical Part: Radius (r) = 1.5" [YouTube Link](https://youtube.com/watch?v=Z51cfafmci8) 2025-11-30T06:04Z [---] followers, [---] engagements "GULAB JAMUN MATH TRICK: How to Find Syrup Volume in Combined Solids Mensuration Class [--] CBSE Welcome to Abhi Garg Classes Today we are tackling a delicious yet complex mensuration problem: calculating the volume of syrup in [--] gulab jamuns. Question: A gulab jamun contains sugar syrup up to about 30% of its volume. Find approximately how much syrup would be found in [--] gulab jamuns each shaped like a cylinder with two hemispherical ends with length [--] cm and diameter [---] cm. This video demonstrates the critical concept of finding the volume of combined solids (Cylinder + Hemispheres) and" [YouTube Link](https://youtube.com/watch?v=ZYoQGqA_Yhs) 2025-12-23T05:00Z [---] followers, [---] engagements "Prove V = (131 / 96) R Volume of Combined Solids Sphere & Cylinder Math Proof (Class 10) Stop struggling with complicated Mensuration proofs This question beautifully combines the volumes of a sphere and a cylinder requiring careful algebraic substitution. We break down the steps to prove that the total volume is (131 / 96) R. Question: A spherical glass vessel has a cylindrical neck whose radius (r) is R/8 and height (h) is 2R. Prove V = (131 / 96) R. This concept is crucial for scoring high marks in surface area and volume chapters. Mastering substitution and fractions is key 📍 Find expert" [YouTube Link](https://youtube.com/watch?v=_VS-nmxUgm4) 2026-01-11T05:10Z [---] followers, [--] engagements "THE HARDEST Mensuration Question 🤯 Calculating Surface Area of Hollowed Cone & Cylinder [--] [--] Board Welcome to ABHI GARG CLASSES Today we are tackling a complex but crucial problem from the Surface Area and Volume chapter (Mensuration) for Class [--] Mathematics. This type of question frequently appears in CBSE and ICSE Board Examinations testing your visualization skills. 🎯 The Question: From a solid right circular cone whose height is [--] cm and radius of base is [--] cm a right circular cylindrical cavity of height [--] cm and radius [--] cm is hollowed out such that bases of cone and cylinder form" [YouTube Link](https://youtube.com/watch?v=_W71AaDZ8oo) 2025-12-01T05:49Z [---] followers, [--] engagements "Hour Hand Problem SOLVED Area Swept by Clock Hand in [--] Minutes Class [--] Maths 🔥 Catchy Hook: Stop guessing the angle Learn the precise formula for clock problems and master the application of the Area of a Sector formula (A = (/360) R). Question: The hour hand of a clock is [--] cm long. The area swept by it between 11:20 am and 11:55 am is calculated step-by-step. Concept: We utilize the fundamental angular speed of the hour hand (0.5 per minute) to find the angle () and then apply the sector area formula. This is an essential concept for Class [--] Board exams 📌 Location: Abhi Garg Classes" [YouTube Link](https://youtube.com/watch?v=_c7r91Ovv4g) 2026-01-20T01:48Z [---] followers, [--] engagements "TSA of Composite Solids: Cube and Hemisphere Class [--] Surface Area and Volume (Mensuration NCERT) Welcome to the world of 3D geometry Many students get confused when two solids are joined. We tackle a standard board exam question involving a cube topped with a hemisphere. Q: The decorative block is made of a cube (edge [--] cm) and a hemisphere (diameter [---] cm) on top. Find the total surface area of the block. Concept Explanation: When calculating the TSA of a composite solid where a smaller shape rests on a larger base we use the formula: TSA = (TSA of base solid) - (Area of common base) +" [YouTube Link](https://youtube.com/watch?v=adMd2igaokQ) 2025-12-25T05:14Z [---] followers, [---] engagements "Juice Seller Problem Apparent vs. Actual Capacity Volume of Cylinder & Hemisphere (Class 10) Don't fall for the juice seller's trick Learn the crucial difference between apparent and actual capacity in this detailed volume calculation. ❓ The Question: A cylindrical glass has an inner diameter of [--] cm and a height of [--] cm. The bottom has a raised hemispherical portion which reduces the capacity. Find the apparent capacity and the actual capacity. ( = 3.14). 💡 Concept Explained: This problem combines the volume formulas for a cylinder (V = rh) and a hemisphere (V = (2/3)r). Actual capacity is" [YouTube Link](https://youtube.com/watch?v=bD3shrUGEUk) 2025-12-13T06:00Z [---] followers, [--] engagements "The ICE-CREAM CONE PROBLEM that EVERY Class [--] Student Finds Tricky Volume of Composite Solids Welcome back to ABHI GARG CLASSES Master the challenging chapter on Surface Areas and Volumes with this expert breakdown of a complex problem often seen in Class [--] Mathematics (CBSE/ICSE syllabus). In this video we meticulously calculate the total volume of ice-cream when it is filled in a cone and overflows into a hemispherical shape while also handling the tricky condition about the internal unfilled volume. ***THE QUESTION:*** An empty cone of radius [--] cm and height [--] cm is filled with" [YouTube Link](https://youtube.com/watch?v=botYt0cKuhE) 2025-11-28T05:20Z [---] followers, [---] engagements "Volume to Area Ratio of Cubes The 3-2-1 Rule Shortcut Class [--] Mensuration Unlock the secret relationship between Volume and Surface Area in 3D shapes Question: If the volumes of two cubes are in the ratio 8:125 then the ratio of their surface areas is: Concept Explained: When dealing with similar 3D shapes the ratio of volumes (s) is the cube of the ratio of sides (s) and the ratio of surface areas (s) is the square of the ratio of sides. We quickly use this principle to derive the solution 4:25. Join Abhi Garg Classes for focused learning and guaranteed results We are located in Sector 20" [YouTube Link](https://youtube.com/watch?v=cXJnXNOGBik) 2026-01-12T04:17Z [---] followers, [--] engagements "Flow Rate vs Volume of Cone Maths Mensuration Problem Solving (Class 10) 🚨 How long does it take for a pipe to fill a conical vessel It's a classic 3D geometry question Question: Water flows at the rate of [--] m/minute through a cylindrical pipe [--] mm in diameter. How long would it take to fill a conical vessel whose diameter at the base is [--] cm and depth is [--] cm This video breaks down the concept of relating the volume flow rate (area velocity) of a cylinder to the total volume of a cone. Ensure all units are consistent (cm or m) before calculating. 📍 Find the best coaching in Sector 20" [YouTube Link](https://youtube.com/watch?v=d1Rh_NmmO_w) 2025-12-11T04:56Z [---] followers, [---] engagements "Cone Volume vs Sphere Volume Trick Find Cone Height Instantly CBSE Class [--] Maths SA & V 🔥 Don't let Volume questions confuse you We are solving a tricky problem where a right circular cone and a sphere share the same radius and the same volume. This conceptual shortcut will save you massive time in exams The Question: If the radius of the base of a right circular cone and the radius of a sphere are each [--] cm in length and their volumes are equal then the height of the cone is: Concept: The key lies in equating V_cone = V_sphere and observing that h = 4r when radii are equal. This" [YouTube Link](https://youtube.com/watch?v=dTM3QznmlnQ) 2026-01-17T05:08Z [---] followers, [--] engagements "Industrial Shed Volume Calculation Cuboid & Half Cylinder Volume Class [--] Maths Application 🎯 Can you solve this real-world volume problem We calculate the total air capacity of an industrial shed shaped like a cuboid surmounted by a half cylinder and then subtract the space occupied by machinery and workers. QUESTION: Shanta runs an industry in a shed which is in the shape of a cuboid surmounted by a half cylinder. If the base of the shed is of dimension [--] m x [--] m and the height of the cuboidal portion is [--] m find the volume of air that the shed can hold. Further suppose the machinery in" [YouTube Link](https://youtube.com/watch?v=dkPCmq0GMU4) 2025-12-15T05:36Z [---] followers, [--] engagements "VOLUME TRICK 🤯 How Many Lead Shots Cone & Sphere Problem (Surface Area and Volume Class 10) 🛑 Stop scrolling Can tiny spheres displace huge volumes Let's solve this viral problem Question: A vessel is in the form of an inverted cone. Its height (H) is [--] cm and the radius of its top (R) is [--] cm. It is filled with water up to the brim. When spherical lead shots of radius (r) [---] cm are dropped into the vessel one-fourth (1/4) of the water flows out. Find the number of lead shots dropped in the vessel. Concept Explanation: This problem tests the fundamental concept of volume displacement" [YouTube Link](https://youtube.com/watch?v=eGXIfAOamfE) 2025-12-17T05:49Z [---] followers, [---] engagements "Area of Sector Problem: Find the Central Angle if Sector Area is 7/20 of the Circle Class [--] 🎯 Quick Maths Hack Are you stuck on sector area problems Question: If the area of a sector of a circle is (7 / 20) of the area of the circle then the angle () at the centre is equal to: CONCEPT: The ratio of the sector area to the total circle area is exactly equal to the ratio of the central angle () to [---]. This allows us to easily isolate and solve for the unknown angle. Learn proven strategies for Classes 8th to 12th Maths and Science. 📍 Visit Abhi Garg Classes in Sector [--] Chandigarh for" [YouTube Link](https://youtube.com/watch?v=eH4muoUfwxQ) 2026-01-25T05:36Z [---] followers, [--] engagements "Ink Capacity Challenge: How Many Words Can A Bottle Write Volume of Cylinder (rh) Class [--] 🚨 Viral Math Problem Alert Can you solve this real-world application of geometry and capacity Question: A cylindrical fountain pen barrel is [--] cm long and has a [--] mm diameter. A full barrel of ink is used up when writing [----] words on average. How many words can be written using a bottle of ink containing 1/5 of a litre Concept Explained: We use the formula for the Volume of a Cylinder (V = rh) and the concept of converting units (mm to cm litres to cm). This helps us apply the unitary method to find" [YouTube Link](https://youtube.com/watch?v=esw6GlWmsag) 2025-12-10T04:59Z [---] followers, [---] engagements "DOUBLE CONE Surface Area TRICK (r=8 h=15) Class [--] Maths CBSE Surface Area and Volume Question 🔥 Welcome to ABHI GARG CLASSES In this essential Class [--] Mathematics tutorial we tackle a critical problem from the Surface Area and Volume chapter involving composite solids. This is a common high-scoring question in CBSE/ICSE board exams. 📚 Question Covered: Two cones with the same base radius (r = [--] cm) and height (h = [--] cm) are joined together along their bases. Find the total surface area of the shape so formed. Key Concepts You Will Learn: [--]. Identifying the correct formula for the TSA of" [YouTube Link](https://youtube.com/watch?v=fXn3CaqVPS4) 2025-11-29T05:41Z [---] followers, [---] engagements "Surface Area of Composite Solids Cone and Hemisphere TSA TRICK Assertion Reason Class [--] Maths Stop losing marks on tricky composite solid questions 🛑 Today we solve a fundamental Assertion-Reason problem related to the Total Surface Area (TSA) of a cone mounted on a hemisphere. Question: Assertion (A): TSA = CSA (Hemisphere) + CSA (Cone). Reason (R): The flat faces are joined internally and not exposed. Concept Explained: When two solids are joined the surface area exposed is only the sum of their external curved areas. The joined planar faces are hidden internally making this a common trap" [YouTube Link](https://youtube.com/watch?v=fueT6AttT2c) 2026-01-09T14:36Z [---] followers, [--] engagements "SILO CASE STUDY 😱 Class [--] Maths Surface Area & Volume Guaranteed Question Slant Height & Cap Welcome to ABHI GARG CLASSES 🏆 Today we tackle a high-probability Case Study question on Surface Area and Volume crucial for your Class [--] CBSE Board Exams. This problem involves calculating the dimensions curved surface area and total capacity of a composite solida silo shaped like a cylinder surmounted by a cone. **The Full Question:** Farmer Girdhar is building a metallic silo (cylinder mounted by a cone). Conical Part: Radius (r) = [---] m Height ($h_c$) = [--] m. Cylindrical Part: Radius (r) = 1.5" [YouTube Link](https://youtube.com/watch?v=gRIv87kX1XY) 2025-11-30T06:03Z [---] followers, [--] engagements "Clock Problem Mastery: How to Find Area Swept by Minute Hand (Class [--] Maths Circles) STOP wasting time and START calculating This geometry application involving clock hands is a critical and recurring board exam favorite from the chapter Area Related to Circles. QUESTION: The length of the minute hand of a clock is [--] cm. Find the area swept by the minute hand during the time period 6:05 am and 6:40 am. CONCEPT: We treat the clock hand as the radius (R) and the path it traces as a Sector. The fundamental concept is knowing the speed: the minute hand moves [--] per minute. We use the time elapsed" [YouTube Link](https://youtube.com/watch?v=gbZ-wbOxEq8) 2026-01-24T05:40Z [---] followers, [--] engagements "Cylinder and Cone Combined Total Area to be Painted Vertical Angle [--] Trick Class [--] Maths 🔥 Mensuration Mastery: Surface Area of Combined Solids Question: A building is in the form of a right circular cylinder of diameter [--] m and height [--] m surmounted by a right circular cone whose vertical angle is [--]. Find the total area to be painted. (Take = 3.14) This video breaks down a tricky Class [--] surface area problem. The crucial step is understanding how the [--] vertical angle helps you determine the cone's height and slant height (l). We calculate the Curved Surface Area of the cylinder and" [YouTube Link](https://youtube.com/watch?v=h1VEA7Ruits) 2026-01-10T04:58Z [---] followers, [--] engagements "TSA of Remaining Solid: Cone Cut from Cylinder Crucial Class [--] Mensuration Question (48 cm) Don't lose marks on complex surface area problems This standard Mensuration question involves calculating the Total Surface Area (TSA) of a composite solid after hollowing. Question: A right circular cone of height [--] cm and diameter [--] cm is hollowed out from the top of a solid right cylinder having the same height and diameter. Find the total surface area of the remaining solid. Concept: Remember when a solid is hollowed the top area of the cylinder is REMOVED and the newly created inner surface (CSA" [YouTube Link](https://youtube.com/watch?v=hSq_VRJEwHk) 2026-01-08T04:56Z [---] followers, [---] engagements "Rocket Maths Solved 🚀 Find Surface Area & Volume of Cylinder and Cone Composite Solids (Class 10) Welcome to ABHI GARG CLASSES In this detailed session for Class [--] Mathematics students we tackle a crucial problem from the chapter on Surface Area and Volume of Composite Solids. This question is frequently asked in CBSE and ICSE board exams. ***The Question:*** A rocket is in the form of a right circular cylinder closed at the lower end and surmounted by a cone with the same radius as that of the cylinder. The diameter and height of the cylinder are [--] cm and [--] cm respectively. If the slant" [YouTube Link](https://youtube.com/watch?v=hUYtqkVGTpI) 2025-12-03T06:20Z [---] followers, [--] engagements "Viral Maths Hack: How Many 539ml Cans Fit in a Cube Class [--] Surface Area & Volume Question 🔥 Geometry Alert This seemingly complex packing problem from Surface Area and Volume (Class 10) is a quick solve if you know the LCM trick. Question: A cylindrical can is placed in a cubical container. i) How many cans fit ii) If the capacity is [---] ml find the cube volume. . Conceptual Clarity is Key. Learn advanced techniques with Abhi Garg Classes. 📍 Location: Sector [--] Chandigarh. 👍 Subscribe for daily Maths and Science concepts #maths #class10 #surfaceareaandvolume #volume #abhigargclasses #cbse" [YouTube Link](https://youtube.com/watch?v=hVYUJbXlw5k) 2025-12-22T05:05Z [---] followers, [--] engagements "Cube Surmounted by a Hemisphere CLASS [--] Surface Area Solution Mensuration Masterclass 🚨 CUBE + HEMISPHERE TRICK REVEALED 🚨 Question: A cubical block of side [--] cm is surmounted by a hemisphere. What is the greatest diameter the hemisphere can have Find the surface area of the solid. This video breaks down a crucial Surface Area and Volume concept from Class [--] Mathematics. We derive the simple effective formula: SA = 6s + r. We find the final answer is [-----] cm. 📍 Visit Abhi Garg Classes in Sector [--] Chandigarh for comprehensive Maths and Science coaching. 👍 Subscribe for daily Maths tips" [YouTube Link](https://youtube.com/watch?v=kKAKpwKMPvE) 2025-12-29T04:38Z [---] followers, [--] engagements "Cuboid to Cylinder Volume Transfer Problem Find the Height Mensuration Class [--] Maths 🔥 Master Volume Conservation instantly 🔥 Question: A rectangular water tank of base [--] m [--] m contains water upto a height of [--] m. If the water in the tank is transferred to a cylindrical tank of radius [---] m find the height of the water level in the tank. Concept Explained: This problem requires equating the volume of the cuboid (V = LBH) to the volume of the cylinder (V = rh). The key principle is that the volume of the substance being transferred is conserved. Perfect for Class [--] CBSE preparation. 📍" [YouTube Link](https://youtube.com/watch?v=l1p2OnQU3PE) 2025-12-08T06:01Z [---] followers, [--] engagements "Cone Inside a Cube: Find the Volume when Cube Volume is [---] Class [--] Mensuration Solid Shapes Are you ready for a quick challenging geometry problem This question tests your visualization skills by connecting the volume of a cube directly to the dimensions of an inscribed cone. The Question: A cone is inscribed in a cube whose volume is [---] cu. units. The cone has its base on one face of the cube and its vertex at the centre of the opposite face. find the volume of the cone. Concept: The key insight is that the cube's side length (a) defines both the cone's height (h) and the cone's diameter" [YouTube Link](https://youtube.com/watch?v=l3ivb3eDtF0) 2026-01-05T06:27Z [---] followers, [--] engagements "Revolutions of Wheels Problem Diameter [--] cm vs [--] m Area Related to Circles Class [--] Maths 🎯 Unlock the secrets of circular motion This classic problem helps you master the relationship between circumference distance and revolutions. Question: The diameters of front and rear wheels of a tractor are [--] cm and [--] m respectively. Find the number of revolutions that the rear wheel will make in covering a distance in which the front wheel makes [----] revolutions. Concept: The key is recognizing that the total distance covered must be the same for both wheels. Distance = Circumference Number of" [YouTube Link](https://youtube.com/watch?v=lV1xaByKnzY) 2026-01-23T06:00Z [---] followers, [--] engagements "Spherical shell (D_ext=8 D_int=4) recast as cone (D=8) Find cone height. #Mensuration SEO: spherical shell cone problem mensuration class [--] Question: A metallic spherical shell with external diameter [--] cm and internal diameter [--] cm is melted and recast into a cone whose base diameter is [--] cm. Find the height of the cone. Short video plan: Restate the problem and show volumes: V_shell = (4/3)(R3 r3) where R=4 cm and r=2 cm. Equate shell volume to cone volume (1/3)(4)h and solve. Calculation gives h = [--] cm Option (b). Quick tip: always equate volumes when recasting solids. Final Answer: **14" [YouTube Link](https://youtube.com/watch?v=lX2VIm54JdM) 2025-11-27T05:15Z [---] followers, [---] engagements "Open Box Volume & Weight Problem Solved Critical Class 10/12 Mensuration Question 🎯 STOP losing marks on Mensuration The 'Open Box' problem has one subtle trick you MUST know regarding internal height. We solve this complete volume and weight question step-by-step. ❓ Question: How many cubic centimetres of iron is required to construct an open box whose external dimensions are [--] cm [--] cm and [----] cm provided the thickness of the iron is [---] cm. If one cubic cm of iron weighs [---] g find the weight of the box. 💡 Concept Focus: When calculating the internal dimensions of an open box with" [YouTube Link](https://youtube.com/watch?v=n7tq-aBdUDw) 2025-12-09T08:32Z [---] followers, [--] engagements "THE HARDEST Mensuration Question 🤯 Calculating Surface Area of Hollowed Cone & Cylinder [--] [--] Board Welcome to ABHI GARG CLASSES Today we are tackling a complex but crucial problem from the Surface Area and Volume chapter (Mensuration) for Class [--] Mathematics. This type of question frequently appears in CBSE and ICSE Board Examinations testing your visualization skills. 🎯 The Question: From a solid right circular cone whose height is [--] cm and radius of base is [--] cm a right circular cylindrical cavity of height [--] cm and radius [--] cm is hollowed out such that bases of cone and cylinder form" [YouTube Link](https://youtube.com/watch?v=nI6lvdajw-4) 2025-12-01T05:50Z [---] followers, [---] engagements "Water Displacement Problem Pond Water Level Rises by [---] cm #Mensuration SEO keywords: water displacement cuboidal pond volume problems class [--] maths mensuration Question: [---] persons take a dip into a cuboidal pond (80 m [--] m). Each displaces [----] m water. Find the rise in water level. Solution: Total water displaced = [---] [----] = [--] m Area of base = [--] [--] = [----] m Rise in level = [--] / [----] = [-----] m = [---] cm Final Answer: [---] cm #Mensuration #Volume #NCERT #Class10Maths #AbhiGargClasses #RiseInWaterLevel" [YouTube Link](https://youtube.com/watch?v=nomjmlsKLEA) 2025-11-25T04:50Z [---] followers, [--] engagements "500 people jump into a pond 🌊 How much does the water level rise #Mensuration #Volume SEO keywords: water displacement cuboidal pond volume problems class [--] maths mensuration Question: [---] persons take a dip into a cuboidal pond (80 m [--] m). Each displaces [----] m water. Find the rise in water level. Solution: Total water displaced = [---] [----] = [--] m Area of base = [--] [--] = [----] m Rise in level = [--] / [----] = [-----] m = [---] cm Final Answer: [---] cm #Mensuration #Volume #NCERT #Class10Maths #AbhiGargClasses #RiseInWaterLevel" [YouTube Link](https://youtube.com/watch?v=p2gstWJgYCg) 2025-11-25T04:54Z [---] followers, [---] engagements "TSA of Remaining Solid: Cone Cut from Cylinder Crucial Class [--] Mensuration Question (48 cm) Don't lose marks on complex surface area problems This standard Mensuration question involves calculating the Total Surface Area (TSA) of a composite solid after hollowing. Question: A right circular cone of height [--] cm and diameter [--] cm is hollowed out from the top of a solid right cylinder having the same height and diameter. Find the total surface area of the remaining solid. Concept: Remember when a solid is hollowed the top area of the cylinder is REMOVED and the newly created inner surface (CSA" [YouTube Link](https://youtube.com/watch?v=piJmjtireRo) 2026-01-08T04:52Z [---] followers, [--] engagements "Hemisphere TSA Ratio Secret Surface Area & Volume Class [--] Maths Quick Trick Are you often confused about the difference between Curved Surface Area and Total Surface Area of a hemisphere This quick problem will cement the concept for you ❓ QUESTION: The ratio of total surface area of a solid hemisphere to the square of its radius is: CONCEPT EXPLAINED: The total surface area of a SOLID hemisphere is 3r because it includes both the curved part and the flat circular base. Setting up the ratio (3r / r) simplifies beautifully to [--] : [--]. Master Mathematics and Science from Class 8th to 12th. Join" [YouTube Link](https://youtube.com/watch?v=rV2cwx_TnyA) 2026-01-15T04:45Z [---] followers, [--] engagements "Spherical shell (D_ext=8 D_int=4) recast as cone (D=8) Find cone height. #Mensuration SEO: spherical shell cone problem mensuration class [--] Question: A metallic spherical shell with external diameter [--] cm and internal diameter [--] cm is melted and recast into a cone whose base diameter is [--] cm. Find the height of the cone. Short video plan: Restate the problem and show volumes: V_shell = (4/3)(R3 r3) where R=4 cm and r=2 cm. Equate shell volume to cone volume (1/3)(4)h and solve. Calculation gives h = [--] cm Option (b). Quick tip: always equate volumes when recasting solids. Final Answer: **14" [YouTube Link](https://youtube.com/watch?v=roFT1tjdZlM) 2025-11-27T05:14Z [---] followers, [--] engagements "GULAB JAMUN MATH TRICK: How to Find Syrup Volume in Combined Solids Mensuration Class [--] CBSE Welcome to Abhi Garg Classes Today we are tackling a delicious yet complex mensuration problem: calculating the volume of syrup in [--] gulab jamuns. Question: A gulab jamun contains sugar syrup up to about 30% of its volume. Find approximately how much syrup would be found in [--] gulab jamuns each shaped like a cylinder with two hemispherical ends with length [--] cm and diameter [---] cm. This video demonstrates the critical concept of finding the volume of combined solids (Cylinder + Hemispheres) and" [YouTube Link](https://youtube.com/watch?v=syBhSZaKnLo) 2025-12-23T04:58Z [---] followers, [--] engagements "Geometry FAIL Assertion-Reason on Sphere & Cylinder Solved (A is True R is False)Class [--] Maths [--]. Stop the confusion This tricky Assertion-Reason question tests if you know the exact formulas and constraints in 3D geometry. Watch how we analyze the 'just encloses' condition and identify the critical error in the Reason. [--]. Question: Assertion (A): A circular cylinder of radius r and height h (h Greater than 2r) just encloses a sphere then the diameter of the sphere is 2r. Reason (R): The surface area of the sphere is 2r(h + r). [--]. We confirm the sphere's maximum diameter is 2r based on the" [YouTube Link](https://youtube.com/watch?v=t5FI0MdueB0) 2026-01-04T05:07Z [---] followers, [--] engagements "🤯 How to calculate TSA of a toy (Cone + Hemisphere) FAST Don't lose marks on composite solids Learn the simplest method to find the Total Surface Area (TSA) of a toy combining a cone and a hemisphere. Question: A toy is in the form of a cone of radius [---] cm mounted on a hemisphere of the same radius. The total height of the toy is [----] cm. Find the total surface area of the toy. Concept Explained: Remember for the total surface area of a composite solid you only add the exposed Curvature Surface Areas (CSA). Finding the slant height (l) using the Pythagorean theorem (l = (r + h)) is the" [YouTube Link](https://youtube.com/watch?v=uM_RwlT89y8) 2026-01-01T05:14Z [---] followers, [--] engagements "🔥 Pipe Flow Rate Problem: Calculate the Rise in Water Level in [--] Min Class [--] Surface Area & Vol [--]. Catchy Hook: Can you solve this classic Surface Area and Volume flow rate problem in under [--] minutes Let's check your speed and accuracy [--]. The Question Text: Water flows through a cylindrical pipe whose inner radius is [--] cm at the rate of [--] cm/sec into an empty cylindrical tank the radius of whose base is [--] cm. What is the rise of water level (H) in the tank in half an hour [--]. Brief Concept Explanation: The key to solving flow rate problems is equating the volume flowing out of the pipe" [YouTube Link](https://youtube.com/watch?v=uYv_oF7d3CI) 2025-12-07T04:59Z [---] followers, [--] engagements "Angle [--] [--] after [--] m Find tree height & river width (Answer: [-----] m [--] m) #Trigonometry Question: From the bank angle of elevation to a tree on opposite bank = [--]. After moving [--] m away angle becomes [--]. Find the tree's height and the river width. Solution summary: Let river width = d. From tan60 = h/d h = d3. From tan30 = h/(d+40) h = (d+40)/3. Solving gives d = [--] m and h = [---] [-----] m. Final: Height = [-----] m Width = [-----] m. #Trigonometry #HeightAndDistance #Class10Maths #NCERT #MathsWithAbhi #QuickSolution" [YouTube Link](https://youtube.com/watch?v=w3qFCWfgQ1g) 2025-11-21T05:29Z [---] followers, [---] engagements "Cloud & Reflection: Prove H = h(tan+tan)/(tantan) #Trigonometry Problem: From a point h metres above a lake the angle of elevation of a cloud is and the angle of depression of its reflection in the lake is . Prove that the clouds height above the lake is H = h (tan + tan ) / (tan tan ). Solution idea: Let horizontal distance to the point under the cloud be x. Use tan = (H h)/x and tan = (H + h)/x. Add and subtract the two equations to eliminate x and solve for H in terms of h tan and tan. Final formula: H = h(tan + tan)/(tan tan). #Trigonometry #HeightAndDistance #ReflectionProblem" [YouTube Link](https://youtube.com/watch?v=wFb7QNaV4p0) 2025-11-04T04:50Z [---] followers, [--] engagements "Volume of Solid (Cone on Hemisphere) Class [--] Maths Board Exam Question Quick Geometry Solution Can you solve this Class [--] geometry problem in [--] seconds Its simpler than you think Question: A solid is in the shape of a cone standing on a hemisphere with both their radii being equal to [--] cm and the height of the cone is equal to its radius. Find the volume of the solid in terms of pi. Concept: Mastering the volume of composite solids involves breaking down the structure into standard shapes (like cones and hemispheres) and applying their respective formulas. The key here is realizing that" [YouTube Link](https://youtube.com/watch?v=wLEiJxD7xI4) 2025-12-26T05:00Z [---] followers, [----] engagements "Cone Inside a Cube: Find the Volume when Cube Volume is [---] Class [--] Mensuration Solid Shapes Are you ready for a quick challenging geometry problem This question tests your visualization skills by connecting the volume of a cube directly to the dimensions of an inscribed cone. The Question: A cone is inscribed in a cube whose volume is [---] cu. units. The cone has its base on one face of the cube and its vertex at the centre of the opposite face. find the volume of the cone. Concept: The key insight is that the cube's side length (a) defines both the cone's height (h) and the cone's diameter" [YouTube Link](https://youtube.com/watch?v=yRRlNpqe_RY) 2026-01-05T06:26Z [---] followers, [--] engagements "Quiz: How Many Multiples of [--] Between [--] & [---] Class [--] CBSE Q: How many multiples of [--] lie between [--] and [---] Watch the video guess before the timer ends and see if you're faster than 99% of students ✅ Solved using AP formula 📌 Perfect for CBSE [----] preparation. 🎥 Subscribe for daily shorts on tricky board concepts #MathsQuiz #CBSEMaths2025 #ArithmeticProgression #FindMultiples #Class10BoardPrep #MathsWithAbhiSir #FastMaths #ConceptReels" [YouTube Link](https://youtube.com/watch?v=yqEGMHfz8QI) 2025-07-19T05:36Z [---] followers, [---] engagements "Volume to Area Ratio of Cubes The 3-2-1 Rule Shortcut Class [--] Mensuration Unlock the secret relationship between Volume and Surface Area in 3D shapes Question: If the volumes of two cubes are in the ratio 8:125 then the ratio of their surface areas is: Concept Explained: When dealing with similar 3D shapes the ratio of volumes (s) is the cube of the ratio of sides (s) and the ratio of surface areas (s) is the square of the ratio of sides. We quickly use this principle to derive the solution 4:25. Join Abhi Garg Classes for focused learning and guaranteed results We are located in Sector 20" [YouTube Link](https://youtube.com/watch?v=z6AH9tRx6gQ) 2026-01-12T04:18Z [---] followers, [---] engagements "TSA of Composite Solids: Cube and Hemisphere Class [--] Surface Area and Volume (Mensuration NCERT) Welcome to the world of 3D geometry Many students get confused when two solids are joined. We tackle a standard board exam question involving a cube topped with a hemisphere. Q: The decorative block is made of a cube (edge [--] cm) and a hemisphere (diameter [---] cm) on top. Find the total surface area of the block. Concept Explanation: When calculating the TSA of a composite solid where a smaller shape rests on a larger base we use the formula: TSA = (TSA of base solid) - (Area of common base) +" [YouTube Link](https://youtube.com/watch?v=zD2Hb8HQus4) 2025-12-25T05:13Z [---] followers, [--] engagements "🔥 TRIGONOMETRY MASTERCLASS Proving (1/(sin+cos)) = sec/2 Identity Proofs Class 10/11 🎯 Catchy Hook: Can you prove this seemingly impossible trigonometric identity Its easier than you think if you know the right shortcut 📝 The Question: If [--] / (sin - cos) = cosec / [--] prove that (1 / (sin + cos)) = sec / [--]. 💡 Concept Explanation: This proof hinges on manipulating the fundamental identity (a+b) + (a-b) = 2(a + b) and strategically substituting the given condition. We convert the difference of sine and cosine squared into a multiple of cos leading directly to the secant function. 📍 Location:" [YouTube Link](https://youtube.com/watch?v=O6sC7U3woNM) 2026-02-16T12:12Z [---] followers, [--] engagements "🔥 TRIGONOMETRY MASTERCLASS Proving (1/(sin+cos)) = sec/2 Identity Proofs Class 10/11 🎯 Catchy Hook: Can you prove this seemingly impossible trigonometric identity Its easier than you think if you know the right shortcut 📝 The Question: If [--] / (sin - cos) = cosec / [--] prove that (1 / (sin + cos)) = sec / [--]. 💡 Concept Explanation: This proof hinges on manipulating the fundamental identity (a+b) + (a-b) = 2(a + b) and strategically substituting the given condition. We convert the difference of sine and cosine squared into a multiple of cos leading directly to the secant function. 📍 Location:" [YouTube Link](https://youtube.com/watch?v=pcc9kVQ3JB4) 2026-02-16T12:12Z [---] followers, [--] engagements "TRIGONOMETRY SHORT TRICK: If sin + cos = [--] Find sin cos in [--] Steps CBSE Class [--] [--]. Catchy Hook: Welcome back champions Today we're tackling a classic trigonometry identity problem that looks tough but melts away in just two steps [--]. The Question Text: If sin + cos = [--] find the value of sin cos. [--]. Brief Concept Explanation: This problem is designed to test your understanding of the squaring method combined with the core trigonometric identity sin + cos = [--]. A must-know concept for Class [--] and [--] board exams and competitive test preparation. [--]. Location: For personalized and high-quality" [YouTube Link](https://youtube.com/watch?v=-9OMf8GtDFY) 2026-02-16T07:58Z [---] followers, [---] engagements "TRIGONOMETRY SHORT TRICK: If sin + cos = [--] Find sin cos in [--] Steps CBSE Class [--] [--]. Catchy Hook: Welcome back champions Today we're tackling a classic trigonometry identity problem that looks tough but melts away in just two steps [--]. The Question Text: If sin + cos = [--] find the value of sin cos. [--]. Brief Concept Explanation: This problem is designed to test your understanding of the squaring method combined with the core trigonometric identity sin + cos = [--]. A must-know concept for Class [--] and [--] board exams and competitive test preparation. [--]. Location: For personalized and high-quality" [YouTube Link](https://youtube.com/watch?v=NTn3m576zA0) 2026-02-16T07:58Z [---] followers, [--] engagements "🤯 TRIGONOMETRY PROOF: If cos + sin = [--] Prove cos - sin = [--] Class [--] CBSE [----] Stop fearing Trigo proofs This identity problem is a frequently asked question (SQP 2024-25) and must be mastered for scoring full marks. 📝 The Question: If cos + sin = [--] then prove that cos - sin = [--]. 💡 Concept Explanation: We solve this by cleverly combining the fundamental trigonometric identity (sin + cos = 1) with an essential algebraic identity allowing us to find the required relationship in just a few lines. This is a crucial concept for Chapter [--]. 📍 For specialized coaching in Maths and Science" [YouTube Link](https://youtube.com/watch?v=v8BIjubPMVg) 2026-02-16T07:54Z [---] followers, [----] engagements "🤯 TRIGONOMETRY PROOF: If cos + sin = [--] Prove cos - sin = [--] Class [--] CBSE [----] Stop fearing Trigo proofs This identity problem is a frequently asked question (SQP 2024-25) and must be mastered for scoring full marks. 📝 The Question: If cos + sin = [--] then prove that cos - sin = [--]. 💡 Concept Explanation: We solve this by cleverly combining the fundamental trigonometric identity (sin + cos = 1) with an essential algebraic identity allowing us to find the required relationship in just a few lines. This is a crucial concept for Chapter [--]. 📍 For specialized coaching in Maths and Science" [YouTube Link](https://youtube.com/watch?v=JCV71vbBq4c) 2026-02-16T07:53Z [---] followers, [--] engagements "TRIGONOMETRY PROOF TRICK: Prove (cosec - sec) / (cosec + sec) = 3/4 Class [--] Maths 🔥 Don't let complex trigonometric proofs scare you This is one of the most frequently asked proof questions in CBSE Class [--] Boards. Question: Prove that (cosec - sec) / (cosec + sec) = 3/4 if tan = [--] / [--]. Concept: The key to solving this proof quickly is recognizing the relationship between cosec sec and tan. By dividing the numerator and denominator by cosec we reduce the entire expression to a simple function of tan making substitution straightforward and fast. 📍 Join Abhi Garg Classes for comprehensive" [YouTube Link](https://youtube.com/watch?v=zayriuOYX-4) 2026-02-16T07:50Z [---] followers, [----] engagements "TRIGONOMETRY PROOF TRICK: Prove (cosec - sec) / (cosec + sec) = 3/4 Class [--] Maths 🔥 Don't let complex trigonometric proofs scare you This is one of the most frequently asked proof questions in CBSE Class [--] Boards. Question: Prove that (cosec - sec) / (cosec + sec) = 3/4 if tan = [--] / [--]. Concept: The key to solving this proof quickly is recognizing the relationship between cosec sec and tan. By dividing the numerator and denominator by cosec we reduce the entire expression to a simple function of tan making substitution straightforward and fast. 📍 Join Abhi Garg Classes for comprehensive" [YouTube Link](https://youtube.com/watch?v=ObmSAP5s950) 2026-02-16T07:50Z [---] followers, [---] engagements "Trigonometry Trick: If sin = cos find the value of tan + cot - [--] Class [--] Maths Stop scrolling Can you solve this trigonometric identity challenge in [--] seconds Question: If is an acute angle and sin = cos find the value of tan + cot - [--]. This problem beautifully links the definition of tangent (sin/cos) with finding specific angle values (like 45). Understanding when sin and cos are equal is the key to simplifying the entire expression quickly. Learn this simple trick to score full marks Join Abhi Garg Classes for comprehensive Mathematics and Science coaching in Sector [--] Chandigarh. Don't" [YouTube Link](https://youtube.com/watch?v=dsCrlpWrzjI) 2026-02-16T07:43Z [---] followers, [---] engagements "Trigonometry Trick: If sin = cos find the value of tan + cot - [--] Class [--] Maths Stop scrolling Can you solve this trigonometric identity challenge in [--] seconds Question: If is an acute angle and sin = cos find the value of tan + cot - [--]. This problem beautifully links the definition of tangent (sin/cos) with finding specific angle values (like 45). Understanding when sin and cos are equal is the key to simplifying the entire expression quickly. Learn this simple trick to score full marks Join Abhi Garg Classes for comprehensive Mathematics and Science coaching in Sector [--] Chandigarh. Don't" [YouTube Link](https://youtube.com/watch?v=hi6HLlADEy0) 2026-02-16T07:42Z [---] followers, [--] engagements "TRIGONOMETRY HACK: If sin x + cosec x = [--] find sinx + cosecx Solved in [--] Seconds Stop solving start observing This famous trigonometry problem can be solved in seconds if you spot the underlying algebraic trick. Question: Find the value of sinx + cosecx if sin x + cosec x = [--]. Concept: We show that when the sum of a term and its reciprocal equals [--] (x + 1/x = 2) that term (x) must be equal to [--]. This applies perfectly to trigonometric functions like sine and cosecant. Mastering advanced concepts starts here Enroll now at Abhi Garg Classes Sector [--] Chandigarh to transform your Math scores." [YouTube Link](https://youtube.com/watch?v=HkQONZ4FIq8) 2026-02-16T07:11Z [---] followers, [---] engagements "TRIGONOMETRY HACK: If sin x + cosec x = [--] find sinx + cosecx Solved in [--] Seconds Stop solving start observing This famous trigonometry problem can be solved in seconds if you spot the underlying algebraic trick. Question: Find the value of sinx + cosecx if sin x + cosec x = [--]. Concept: We show that when the sum of a term and its reciprocal equals [--] (x + 1/x = 2) that term (x) must be equal to [--]. This applies perfectly to trigonometric functions like sine and cosecant. Mastering advanced concepts starts here Enroll now at Abhi Garg Classes Sector [--] Chandigarh to transform your Math scores." [YouTube Link](https://youtube.com/watch?v=THPQc7SdVVI) 2026-02-16T07:09Z [---] followers, [--] engagements "🔥 How to Find the Area of the Remaining Portion Square & Circle Cutouts Class [--] Geometry NCERT Stop losing marks on geometry questions involving combined shapes This solution simplifies everything. **The Question:** From each corner of a square of side [--] cm a quadrant of a circle of radius [--] cm is cut and also a circle of diameter [--] cm is cut from the center. Find the area of the remaining portion. **Concept Explained:** We use the simple principle: Area Remaining = Area of Square - Total Area Removed. Note that four quadrants always combine to form one full circle Join the best coaching" [YouTube Link](https://youtube.com/watch?v=9L9gE0r9TvM) 2026-02-16T05:43Z [---] followers, [---] engagements "🔥 How to Find the Area of the Remaining Portion Square & Circle Cutouts Class [--] Geometry NCERT Stop losing marks on geometry questions involving combined shapes This solution simplifies everything. **The Question:** From each corner of a square of side [--] cm a quadrant of a circle of radius [--] cm is cut and also a circle of diameter [--] cm is cut from the center. Find the area of the remaining portion. **Concept Explained:** We use the simple principle: Area Remaining = Area of Square - Total Area Removed. Note that four quadrants always combine to form one full circle Join the best coaching" [YouTube Link](https://youtube.com/watch?v=74fUFnciZGU) 2026-02-16T05:43Z [---] followers, [--] engagements "Viral Geometry Trick: Find Difference in Areas of Overlapping Sectors (R=6 R=8) Cancellation Meth 🔥 Geometry Hack Alert This seemingly complex problem involving overlapping sectors has a surprising simplification trick. Question: Find the difference in the areas of regions I and III given two overlapping sectors with radii [--] cm and [--] cm (assuming they are quadrants). Concept Explanation: We demonstrate the powerful cancellation technique. By setting up simultaneous equations for the areas we show that the common overlapping area (Region II) completely cancels out allowing us to find the" [YouTube Link](https://youtube.com/watch?v=MOvBDYfP0ps) 2026-02-16T05:09Z [---] followers, [---] engagements "Viral Geometry Trick: Find Difference in Areas of Overlapping Sectors (R=6 R=8) Cancellation Meth 🔥 Geometry Hack Alert This seemingly complex problem involving overlapping sectors has a surprising simplification trick. Question: Find the difference in the areas of regions I and III given two overlapping sectors with radii [--] cm and [--] cm (assuming they are quadrants). Concept Explanation: We demonstrate the powerful cancellation technique. By setting up simultaneous equations for the areas we show that the common overlapping area (Region II) completely cancels out allowing us to find the" [YouTube Link](https://youtube.com/watch?v=3Y51BYsRxK0) 2026-02-16T05:08Z [---] followers, [--] engagements "Area of Shaded Region: Square and Two Semicircles NCERT Class [--] Geometry Abhi Garg Classes Stop confusing composite shapes This is one of the most frequently asked questions on Area of Shaded Regions in Class [--] boards. ❓ The Question: Find the area of the shaded region if ABCD is a square of side [--] cm and APD and BPC are semicircles. 💡 Concept Explained: We use the fundamental principle: Area of Shaded Region = Area of Square - Area of Two Semicircles. Pay close attention to calculating the radius from the side length This is perfect practice for Class [--] Boards geometry. 📍 For focused" [YouTube Link](https://youtube.com/watch?v=Ain16XK3lEk) 2026-02-15T15:25Z [---] followers, [---] engagements "Area of Shaded Region: Square and Two Semicircles NCERT Class [--] Geometry Abhi Garg Classes Stop confusing composite shapes This is one of the most frequently asked questions on Area of Shaded Regions in Class [--] boards. ❓ The Question: Find the area of the shaded region if ABCD is a square of side [--] cm and APD and BPC are semicircles. 💡 Concept Explained: We use the fundamental principle: Area of Shaded Region = Area of Square - Area of Two Semicircles. Pay close attention to calculating the radius from the side length This is perfect practice for Class [--] Boards geometry. 📍 For focused" [YouTube Link](https://youtube.com/watch?v=et1ul3d5om8) 2026-02-15T15:22Z [---] followers, [--] engagements Limited data mode. 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@abhigargclasses Abhi Garg Classes
Abhi Garg Classes posts on YouTube about sector, math, solve, how to the most. They currently have [---] followers and [---] posts still getting attention that total [-----] engagements in the last [--] hours.
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Social topic influence sector #1543, math, solve, how to, hook, complex #1430, this is, tutorial, the most, can you
Top Social Posts
Top posts by engagements in the last [--] hours
"Master AP Sum Trick: Sum of Integers Between [---] and [---] Divisible by [--] Class [--] Maths 🤯 Don't let Arithmetic Progression sums confuse you This classic problem requires two simple steps and we show you exactly how to tackle it. Question: Find the sum of the integers between [---] and [---] that are (i) divisible by [--]. (ii) not divisible by [--]. Concept Explained: We use the AP sum formula S = (n/2)(a + l) and the concept of exclusion (Total Sum - Sum Divisible = Sum Not Divisible) to solve this problem efficiently. Join the best coaching institute Abhi Garg Classes is located in Sector 20"
YouTube Link 2026-02-15T07:05Z [---] followers, [--] engagements
"Viral Geometry Trick: Find Difference in Areas of Overlapping Sectors (R=6 R=8) Cancellation Meth 🔥 Geometry Hack Alert This seemingly complex problem involving overlapping sectors has a surprising simplification trick. Question: Find the difference in the areas of regions I and III given two overlapping sectors with radii [--] cm and [--] cm (assuming they are quadrants). Concept Explanation: We demonstrate the powerful cancellation technique. By setting up simultaneous equations for the areas we show that the common overlapping area (Region II) completely cancels out allowing us to find the"
YouTube Link 2026-02-16T05:08Z [---] followers, [--] engagements
"Area Related to Circles: Finding Perimeter of Shaded Region with Four Semi-Circles Class [--] Maths 🔥 Don't let complex figures fool you This seemingly tricky geometry problem is a straightforward application of circle perimeter. Question: In the given figure APB and CQD are semi-circles with a diameter of [--] cm each. ARC and BSD are semi-circles with a diameter of [--] cm each. Find the perimeter of the shaded region. Concept Focus: The perimeter of a composite region formed by arcs is the sum of the lengths of the bounding arcs. Remember arc length for a semi-circle is r. Join Abhi Garg Classes"
YouTube Link 2026-02-14T02:52Z [---] followers, [--] engagements
"TRIGONOMETRY PROOF TRICK: Prove (cosec - sec) / (cosec + sec) = 3/4 Class [--] Maths 🔥 Don't let complex trigonometric proofs scare you This is one of the most frequently asked proof questions in CBSE Class [--] Boards. Question: Prove that (cosec - sec) / (cosec + sec) = 3/4 if tan = [--] / [--]. Concept: The key to solving this proof quickly is recognizing the relationship between cosec sec and tan. By dividing the numerator and denominator by cosec we reduce the entire expression to a simple function of tan making substitution straightforward and fast. 📍 Join Abhi Garg Classes for comprehensive"
YouTube Link 2026-02-16T07:50Z [---] followers, [---] engagements
"Area of Shaded Region: Square and Two Semicircles NCERT Class [--] Geometry Abhi Garg Classes Stop confusing composite shapes This is one of the most frequently asked questions on Area of Shaded Regions in Class [--] boards. ❓ The Question: Find the area of the shaded region if ABCD is a square of side [--] cm and APD and BPC are semicircles. 💡 Concept Explained: We use the fundamental principle: Area of Shaded Region = Area of Square - Area of Two Semicircles. Pay close attention to calculating the radius from the side length This is perfect practice for Class [--] Boards geometry. 📍 For focused"
YouTube Link 2026-02-15T15:22Z [---] followers, [--] engagements
"Area of Shaded Region Class [--] Equilateral Triangle & Major Sector Combo Explained Simply CBSE Hook: Stop confusing composite figures Learn the fastest method to solve this challenging Class [--] Area of Shaded Region problem. Question: Find the area of the shaded region where a circular arc of radius [--] cm has been drawn with vertex O of an equilateral triangle OAB of side [--] cm as the centre. Concept: We break down the figure into two parts: the Area of the Equilateral Triangle (363) and the Area of the Major Sector (30). The key is accurately identifying the [--] angle of the triangle and"
YouTube Link 2026-02-15T06:08Z [---] followers, [--] engagements
"NCERT Class [--] Area of Shaded Region Problem (7 cm [--] cm) Geometry Simplified 🔥 Geometry Hack Alert This is a super important question from Area Related to Circles that frequently appears in CBSE Class [--] Board Exams. ❓ The Question: Find the area of the shaded region if PQ = [--] cm PR = [--] cm and O is the centre of the circle. 💡 Concept: The key is recognizing that the angle subtended by the diameter (QR) at the circumference is [--]. This immediately allows us to use the Pythagorean theorem to find the diameter and then calculate the required area by subtracting the area of the triangle from"
YouTube Link 2026-02-15T05:17Z [---] followers, [--] engagements
"Area of Shaded Region Concentric Circles (R=14 r=7 =40) Class [--] Maths Chapter [--] 🔥 Quickest way to solve Area Related to Circles problems We tackle the challenge of finding the area of the shaded region between two concentric circles. Question: Find the area of the shaded region if the radii of the two concentric circles are [--] cm and [--] cm and the central angle is [--]. Concept: The solution relies on finding the difference between the areas of the two large and small sectors. A simple factorisation of the sector formula makes the calculation lightning fast: Area = (/360) (R - r). Need"
YouTube Link 2026-02-15T05:30Z [---] followers, [--] engagements
"Area to Distance HACK How Many Revolutions Does a Wheel Make Class [--] Circles Problem Tired of confusing word problems in Circles This short tutorial breaks down the classic 'Number of Revolutions' calculation easily We show you how to link Area Circumference and Total Distance. Question: Find the number of revolutions made by a circular wheel of area [----] m rolling a distance of [---] m. Concept Explanation: This problem requires two steps: first finding the radius (r) from the given Area (A = r) and second using the Circumference (C = 2r) to find the number of revolutions (N = Distance / C)."
YouTube Link 2026-01-27T04:53Z [---] followers, [--] engagements
"Area of Three Sectors Shortcut Class [--] Maths Chapter [--] The Central Angle Trick Explained Don't waste time calculating the area of three sectors separately Watch this shortcut where we solve this common CBSE Class [--] geometry problem in a single step. Question: Three sectors of a circle of radius [--] cm making angles [--] [--] and [--] at the center are shaded. Find the area of the shaded region. Use = 22/7 Concept Explained: Learn how combining the central angles simplifies complex area calculations in circles. By recognizing that the total shaded angle creates a single larger sector we"
YouTube Link 2026-02-11T07:17Z [---] followers, [--] engagements
"Area of Segment Class [--] Maths Circles FULL SOLUTION in [--] Minutes (NCERT Example) Don't skip this Geometry essential Finding the Area of a Segment is one of the most tested topics in the Class [--] syllabus. QUESTION: A circle has a radius (r) of [--] cm and a central angle () of [--]. Find the area of the minor segment. (Use = 22/7). CONCEPT: The area of the minor segment is calculated by subtracting the area of the corresponding triangle from the area of the sector. The key formulas used are: Area of Sector = ( / 360) * * r and Area of Triangle = (1/2) * r * sin(). Mastery of this ensures full"
YouTube Link 2026-02-06T05:07Z [---] followers, [--] engagements
"Area of Segment TRICK Chord Subtending [--] Class [--] Circles Most Important Question 🔥 Don't let area of segments problems confuse you This concept is crucial for your board exams. 🔥 Question: Find the difference of the areas of two segments of a circle formed by a chord of length [--] cm subtending an angle of [--] at the centre. We tackle a crucial application of the area of sectors and triangles within a circle. When the angle is [--] we use Pythagoras theorem to find the radius and then proceed step-by-step to calculate the area difference. Mastering these formulas is key to securing top marks."
YouTube Link 2026-01-28T03:30Z [---] followers, [--] engagements
"Area of Three Sectors in a Triangle Explained Class [--] Math Circles Abhi Garg Classes Don't let side lengths trick you This classic geometry problem relies on a fundamental concept you already know: the Angle Sum Property of a triangle. 🔥 Question: Given a triangle ABC arcs are drawn from vertices A B and C as centers each with a radius of r = [--] cm. If the side lengths are AB = [--] cm BC = [--] cm and CA = [--] cm find the total area of the three sectors. (Use = 3.14). Concept Explanation: This problem beautifully combines the area of a sector formula with the fact that the sum of angles in any"
YouTube Link 2026-01-29T04:41Z [---] followers, [--] engagements
"Area Ratio: Circle vs Square when Perimeter is Equal Class [--] CBSE Geometry Problem Explained 🔥 Catchy Hook: Can two shapes with the same perimeter have drastically different areas Find out the crucial ratio for this classic exam question 📚 Question: If the perimeter of a circle is equal to that of a square then the ratio of their areas is what 💡 Concept Explanation: We equate the perimeter formulas (2r = 4a) to find the relationship between radius (r) and side (a). By substituting this relationship into the area ratio (A_c / A_s) we derive the simple fraction 4/ which simplifies to 14:11."
YouTube Link 2026-02-05T05:11Z [---] followers, [--] engagements
"Viral Geometry Trick: Find the Area of a Square Inscribed in a Circle (R = [---] cm) [--]. Hook: Stop confusing diameter and diagonal This simple concept is key to cracking high-level geometry questions quickly. [--]. The Question: The area of the square inscribed in a circle of radius [---] cm is calculated by equating the diameter of the circle to the diagonal of the square. [--]. Concept Explanation: The most efficient way to solve this is using the formula Area = (1/2) (Diagonal) where Diagonal = [--] Radius. This saves time and avoids finding the side length first. Result is [----] cm. [--]. Location: Join"
YouTube Link 2026-02-03T04:53Z [---] followers, [--] engagements
"Area of Shaded Region: Trapezium and Sector Cutout CBSE Class [--] Maths Geometry Problem 🔥 Don't let composite figures confuse you This problem tests your knowledge of two fundamental geometry formulas: Area of a Trapezium and Area of a Sector. Question: A trapezium ABCD with AB parallel to DC has parallel sides AB = [--] cm and DC = [--] cm and the height is [--] cm. A sector of a circle with radius r = [--] cm and central angle [--] is cut out from corner D. Find the area of the shaded region in terms of . 🎯 Concept Explained: The key is to break down the complex figure into simpler parts. Area of"
YouTube Link 2026-02-12T05:21Z [---] followers, [--] engagements
"Perimeter of a Sector SOLVED Class [--] Maths Area Related to Circles Full Explanation (CBSE) 🔥 HOOK: Don't lose marks on this easy Perimeter of Sector question It comes up almost every year in the Class [--] CBSE Board Exams. ❓ QUESTION: The shape of the top of a table is that of a sector of a circle with centre O and angle AOB = [--]. If AO = OB = [--] cm find the perimeter of the top of the table. 💡 CONCEPT: Remember that the perimeter of a sector includes not just the curved arc length but also the two straight radii. We use the formula: Perimeter = (/360) * 2r + 2r. Mastering this formula is"
YouTube Link 2026-02-12T05:13Z [---] followers, [--] engagements
"Areas Related to Circles: ALL Formulas Explained in [--] Minutes Class [--] Maths Formula Sheet Are you tired of mixing up circumference and area This video gives you a crystal-clear breakdown of the [--] essential formulas needed for 'Areas Related to Circles' (Class 10/9 Maths). Formulas Covered: [--]. Area of Circle (r) [--]. Circumference (2r) [--]. Area of Sector [--]. Length of Arc [--]. Area of Segment Mastering these concepts is non-negotiable for scoring high in your CBSE Board Exams. We explain what each variable (r and ) represents and how to apply the formula correctly. Ready to achieve guaranteed"
YouTube Link 2026-02-10T04:59Z [---] followers, [--] engagements
"Area of Uncovered Floor with Circular Tiles Tiling Problem Mensuration Class [--] & [--] 🎯 Quick Math Challenge: Area of Uncovered Floor Question: Floor of a room has dimensions [--] m [--] m. It is covered with circular tiles of diameter [--] cm each. Find the area of the floor that remains uncovered by the tiles. (Use = 3.14) This problem requires careful unit conversion (cm to m) and understanding how the area of a circle (r) relates to a rectangular floor space. We calculate the total area the area covered by all the tiles and subtract to find the remaining area. A crucial concept for Class [--] and"
YouTube Link 2026-01-30T05:12Z [---] followers, [--] engagements
"Bicycle Wheel Problem [----] Revolutions in [--] km Find the Diameter (Circles Class 10/9) Is your geometry strong enough to measure a bicycle wheel 🚴♂ Let's tackle this classic problem involving Distance Revolutions and Circumference Question: A bicycle wheel makes [----] revolutions in moving [--] km. Find the diameter of the wheel. This concept is vital for understanding the relationship between linear distance traveled and angular rotation (Distance = N Circumference) a key topic in the 'Areas Related to Circles' chapter for CBSE/ICSE Class [--] and [--]. Join Abhi Garg Classes for top-tier coaching"
YouTube Link 2026-02-07T06:20Z [---] followers, [--] engagements
"Area of Sector Class [--] Clock Hand Problem (5 a.m. to [--] a.m.) Geometry and Circles Concept 🎯 Hook: Stop panicking when you see clock problems in circles Today we solve one of the most frequently asked Class [--] Sector questions in less than [--] seconds. Question: The length of the hour hand of a clock is [--] cm. Find the area of the minor sector swept by the hour hand of the clock between [--] a.m. to [--] a.m. Also find the area of the major sector. Concept Explained: The key is understanding that the hour hand moves [--] every hour (360 / [--] hours). Once the angle ( = 90) is found we use the formula"
YouTube Link 2026-02-11T05:36Z [---] followers, [--] engagements
"Major Segment Area Calculation Class [--] Circles Full Solution [--] Chord Problem 🔥 Don't let Major Segment problems scare you This is a frequently asked question (FAQ) for CBSE Class [--] Boards. Question: A chord of a circle of radius [--] cm subtends an angle of [--] at the centre. Find the area of the corresponding major segment of the circle. (Use = 3.14). Concept Explained: Finding the major segment involves calculating the total circle area and subtracting the minor segment (sector area - triangle area). Pay close attention to the right angle simplification Join Abhi Garg Classes for"
YouTube Link 2026-02-12T10:07Z [---] followers, [--] engagements
"OLYMPIC RINGS MATH CHALLENGE Radius Sector & Segment Area in [--] Minutes Class [--] Circles 🔥 Geometry Hot Question 🔥 Unlock the secrets hidden within the Olympic Rings symbol This video breaks down a crucial application-based problem involving Circumference Area of Sectors and Area of Segments (Class [--] Maths). The Question: Students used 44m of rope per ring. If AOB is equilateral find the Radius (r) and the Area of the shaded Rangoli region (R). We show you exactly how to use the Circumference formula to find the radius and then calculate the segment area using = 22/7. Conceptual Clarity"
YouTube Link 2026-02-08T12:23Z [---] followers, [--] engagements
"Area Related to Circles: Semi-Circle Farm House Case Study CBSE Class [--] Maths Abhi Garg Classes 🔥 Ultimate Geometry Challenge Can you solve this complex semi-circle case study involving perimeter and area Question: A farm house is shaped like a semi-circle (D=70 m). Point P is on the circumference such that PAB = [--]. Find (i) POA (ii) Total perimeter and (iii) Area of Sector AOP. This video breaks down how to use radius properties (Isosceles Triangles) and area formulas (Area of Sector) efficiently. Perfect revision for your Class [--] Board Exams 📍 Learn with the best at Abhi Garg Classes"
YouTube Link 2026-02-09T05:15Z [---] followers, [--] engagements
"Perimeter of a Sector of a Circle Class [--] Maths Chapter [--] Areas Related to Circles Solved Prob 🔥 Learn the easiest way to calculate the perimeter of a sector in seconds Question: The perimeter of the sector of a circle of radius [--] cm which subtends an angle of [--] at the centre of circle is: Concept Simplified: The perimeter of a sector combines the arc length (calculated using the central angle) and the length of the two radii. This concept is fundamental to the 'Areas Related to Circles' chapter for CBSE Class [--]. For personalized tutoring in Mathematics and Science (8th to 12th) visit"
YouTube Link 2026-02-04T06:05Z [---] followers, [--] engagements
"Arc Length Ratio Solved in Seconds [--] Central Angle Circles Class [--] Maths CBSE/ICSE Unlock the secrets of circles This ratio problem involving arc length and circumference is a guaranteed question type for your board exams. Question: If an arc subtends an angle of [--] at the center of a circle what is the ratio of its length to the circumference of the circle Concept Explained: The ratio of the arc length to the total circumference is directly proportional to the ratio of the central angle subtended by the arc () to the total angle (360). It's simpler than you think Master this and many more"
YouTube Link 2026-02-01T05:02Z [---] followers, [--] engagements
"Equilateral Triangle & Inscribed Circle: Find the Shaded Area Class [--] Math Geometry Solution 🎯 Master the relationship between heights and radii in geometry This video solves a critical Class [--] problem involving an inscribed circle within an equilateral triangle. Question: A circle is inscribed in an equilateral triangle ABC of side [--] cm. Find the radius of the inscribed circle and the area of the shaded region. (Use = [----] and [--] = 1.73) We break down how to calculate the height of the triangle using the altitude formula and how that height determines the inradius (r=h/3). Then we"
YouTube Link 2026-02-13T06:34Z [---] followers, [--] engagements
"Area of Sectors: Finding the Difference (120 Angle) Class [--] CBSE Chapter [--] Full Solution Get ready to ace your Class [--] Geometry chapter This video breaks down a highly requested board exam question: finding the difference between the areas of the Major and Minor sectors of a circle. Question: Find the difference of the areas of a sector of angle [---] and its corresponding major sector of a circle of radius [--] cm. We utilize the fundamental formula A = ( / 360) * * r and show a clean effective method to calculate the difference. Understanding the relationship between the minor and major"
YouTube Link 2026-01-31T05:40Z [---] followers, [--] engagements
"🔥 Perimeter of Shaded Region Explained Circles Class [--] Maths Area Related to Circles CBSE Sol 🎯 Catchy Hook: Stop struggling with complex geometry figures This seemingly difficult shaded region problem is actually a simple application of the semi-circle perimeter formula. 🧠 The Question: PQRS is a diameter of a circle of radius [--] cm. PQ = QR = RS. Find the perimeter of the shaded region formed by semi-circles on diameters PQ QS and PS. 💡 Concept Explanation: The key is recognizing that the perimeter calculation requires only adding the lengths of the bounding arcs ( radius). Since the"
YouTube Link 2026-02-12T15:13Z [---] followers, [---] engagements
"Area of Remaining Cardboard Two Maximum Circles Cut from Rectangle Class [--] Maths Geometry Prob 🔥 How much cardboard area is left after cutting two big circles This is a classic geometry question that requires you to identify the maximum constraints Question: Two circular pieces of equal radii and maximum area touching each other are cut out from a rectangular card board of dimensions [--] cm x [--] cm. Find the area of the remaining card board. Use = 22/7 Concept Explanation: The key to solving this lies in recognizing that the diameter of the maximum possible equal circles must be equal to the"
YouTube Link 2026-02-13T10:28Z [---] followers, [--] engagements
"Perimeter of Shaded Region involving Semicircles Class [--] Mensuration Solved Abhi Garg Classes Unlock the secrets of Mensuration 🔓 Can you calculate the perimeter of this complex shaded region involving multiple semi-circles This is a guaranteed high-score question for CBSE/ICSE Class [--] Board Exams. The Question: In the figure a semi-circle is drawn with O as the center and AB as the diameter. Two smaller semi-circles are drawn using AO and OB as diameters. If AB = [--] m find the perimeter of the shaded region. (Use = 22/7). Concept Explained: The key here is recognizing that the perimeter"
YouTube Link 2026-02-14T07:27Z [---] followers, [--] engagements
"SUM OF AREAS of Two Circular Parks Radius of the New Circle Class [--] Areas Related to Circles Stop guessing the answer This Class [--] Areas Related to Circles problem is crucial for your board exams preparation. We solve it step-by-step. 🤔 THE QUESTION: It is proposed to build a new circular park equal in area to the sum of areas of two circular parks of diameters [--] m and [--] m in a locality. Find the radius of the new park. 💡 CONCEPT EXPLAINED: We use the fundamental area formula A = r and the crucial relationship that the radius (r) is half the diameter (d). The entire problem hinges on"
YouTube Link 2026-02-02T05:10Z [---] followers, [--] engagements
"Olympic Rings Area Calculation (Advanced Geometry) CBSE Class 10/12 Abhi Garg Classes 🤯 How the Olympic Rings are a hidden geometry puzzle Question: Given the Olympic rings of radius [--] cm where the common chord length is [--] cm. Find the total area of the four intersecting (dotted) regions. This video breaks down a tricky area calculation question. We use the property that equal radius and equal chord length create a [--] (Equilateral Triangle) sector. Mastering segment area calculation is key to solving CBSE and competitive exam problems. 📍 Visit us: Abhi Garg Classes Sector [--] Chandigarh. 🔔"
YouTube Link 2026-02-07T14:12Z [---] followers, [--] engagements
"CBSE Class [--] Solve the Viral Square & Circles Shaded Area Problem in [--] Steps Areas Related to C 🔥 Master the trickiest geometry problems effortlessly 🔥 Question: ABCD is a square of side [--] cm. Four circles are drawn with centres A B C and D such that each circle touches two adjacent circles externally. Find the area of the shaded region. Concept: This is a classic problem involving Areas Related to Circles. We calculate the area of the large square and subtract the area of the four identical quarter-circle sectors. A must-know concept for Class [--] CBSE boards (Area of Square - Area of 1"
YouTube Link 2026-02-13T05:02Z [---] followers, [--] engagements
"NCERT MASTER: Area of Square Lawn & Circular Flower Beds Class [--] Maths Chapter [--] [----] m 🎯 Master the tricky concepts of Areas Related to Circles with Abhi Garg Classes Question: In the given figure two circular flower beds have been shown on two sides of a square lawn ABCD of side [--] m. If the center of each circular flower bed is the point of intersection O of the diagonals of the square lawn find the sum of the areas of the lawn and the flower beds. 💡 Concept Explanation: This problem requires combining the area of a square with the area of two circular segments. We must first find the"
YouTube Link 2026-02-10T05:12Z [---] followers, [--] engagements
"Bus Wheel Revolutions: How to Calculate RPM from Speed Class [--] Circles Application Problem Catchy Hook: Stop guessing Learn the precise mathematical relationship between linear speed and the rotation of a wheel in just a few steps. Question: The diameter of the wheels of a bus is [---] cm. How many revolutions per minute must a wheel make in order to move at a speed of [--] km per hour Concept Explanation: This concept requires using the circumference (2r) to find the distance covered in one rotation. Crucially you must perform accurate unit conversions moving from kilometers per hour to"
YouTube Link 2026-02-08T05:55Z [---] followers, [--] engagements
"Quick Proof: (cot cosec ) = (1 cos )/(1 + cos ) #Maths Problem: Prove (cot cosec ) = (1 cos )/(1 + cos ). Solution summary: [--]. cot cosec = (cos 1)/sin = (1 cos )/sin . [--]. Square and use sin = [--] cos = (1 cos )(1 + cos ). [--]. Cancel (1 cos ) to get (1 cos )/(1 + cos ). Domain: sin [--] so cot and cosec are defined. #Trigonometry #Class10Maths #MathsProof #AbhiGargClasses"
YouTube Link 2025-10-07T05:33Z [---] followers, [--] engagements
"Trig Proof: (1+sec)/sec = sin/(1cos) Problem: Prove (1 + sec A)/sec A = sinA/(1 cos A). Short solution: LHS = (1+secA)/secA = 1/secA + [--] = cosA + [--]. RHS = sinA/(1cosA) = (1cosA)/(1cosA) = 1+cosA (after cancellation). Thus both sides equal [--] + cosA where defined. Domain: require cosA [--] and [--] cosA [--] for direct cancellation; equality's simplified form 1+cosA holds when expressions are defined. (Abhi Garg Classes)"
YouTube Link 2025-10-10T04:54Z [---] followers, [---] engagements
"Sum of 11-term AP when middle term = [--] #AP #MathsTrick Arithmetic Progression quick method: sum of odd-numbered AP = n (middle term). Learn why S = n middle term and apply it fast for exams. #WhatIsTheSum #HowToFind Question (rewritten): Find the sum of all the [--] terms of an AP whose middle most term is [--]. Short Explanation: For any AP with odd number of terms n the middle term equals the average of the sequence and the sum of all terms = n (middle term). Here n = [--] and middle term = [--] so total sum S = [--] [--] = [---]. Perfect quick trick for Class [--] / CBSE / NCERT exam prep saves time in"
YouTube Link 2025-09-05T05:54Z [---] followers, [---] engagements
"Find the 3-digit AP number Sum=15 Reverse is [---] less #AP #Maths Class [--] Maths Arithmetic Progression Important AP Word Problem 👉 Question: The digits of a three-digit positive integer are in AP. Their sum is [--]. The number obtained by reversing the digits is [---] less than the original number. Find the number. 🔎 Key Concepts: - Digits in AP middle digit = average of first and last. - Sum of digits = [--]. - Reversed number = Original number [---]. - Equation solving with AP logic. 📘 Solution Highlights: Let digits be (a d) a (a + d). Sum = (a d) + a + (a + d) = 3a = [--] a = [--]. Digits: (5 d) 5"
YouTube Link 2025-09-07T13:28Z [---] followers, [---] engagements
"#FindNumberOfTerms in AP: [----] [--]. ➤ Sum = [---] #HowManyTerms #WhatIsN Solved In this video we solve this Arithmetic Progression problem: "How many terms of the AP [----] [--]. must be taken so that their sum is 636" Perfect for CBSE Class [--] students and those preparing for competitive exams. #FindNumberOfTerms #HowManyTerms #WhatIsN #APSolved #ArithmeticProgression #NCERTQuestion #CBSEMaths #Class10Maths #MathHelp #APFormula #MathShorts"
YouTube Link 2025-07-31T05:53Z [---] followers, [--] engagements
"When Are Two A.P. Terms Equal Class [--] CBSE AP Trick 🎯 Two arithmetic progressions. One question: 👉 When will their nth terms become equal AP 1: [--] [--] [--]. AP 2: [--] [--] [--]. Learn how to equate AP terms step-by-step. Great revision for CBSE Class [--] students 🧮 Perfect question for board preparation. 📌 Like Comment your answer and Subscribe for more class [--] math tricks. #MathChallenge #ArithmeticProgression #CBSEClass10 #BoardExam2025 #StudyShorts #FastMaths #nthterm #MathsWithAbhiSir"
YouTube Link 2025-07-20T08:13Z [---] followers, [--] engagements
"🤯 Number Riddle with Digits Class [--] Quadratic Equation Statement Ques. #mathematics #quadratic 🎓 Quadratic Equation Word Problem Number Based Puzzle Class [--] Maths 📌 Question Covered: A two-digit number is four times the sum of its digits. It is also equal to three times the product of its digits. 👉 Find the number. 📘 In this video: Step-by-step explanation Building and solving the quadratic equation Tips to identify number-based word problems in Class [--] Board Exams 🧑🏫 Presented by Abhi Sir Mathematics and Science 🎯 Ideal for: ✔ Class [--] CBSE students ✔ Quadratic equation word"
YouTube Link 2025-06-18T10:37Z [---] followers, [--] engagements
"Find the Missing Terms in APs Class [--] Arithmetic Progression #AP #question3 📘 Topic: Fill in the missing terms in the given Arithmetic Progressions (APs) using the formula: 👉 an = a + (n 1)d In this video we solve [--] different APs where some terms are missing. Learn how to find them step-by-step 🔥 Must-watch for Class [--] CBSE students preparing for board exams 📌 Like comment and subscribe for more concept-wise short videos #ArithmeticProgression #MissingTermsInAP #Class10Maths #CBSEBoard2025 #MathsWithAbhiSir #FillTheBlanksAP #APChapterClass10 #MathConcepts #BoardExamPrep"
YouTube Link 2025-07-08T11:21Z [---] followers, [--] engagements
"#AP Sum Formula Proof Show that S = (a+c)(b+c-2a)/2(b-a) #Class10Maths #NCERT 📘 In this video we solve an important NCERT/CBSE Class [--] Maths question on Arithmetic Progressions (AP). We are asked to show that the sum of an AP with first term a second term b and last term c is equal to (a+c)(b+c-2a) / 2(b-a). 👉 This proof is a frequently asked question in exams and is very important for Class [--] board preparation. 👉 We carefully break it down step by step for better understanding. ✨ Keywords: Arithmetic Progression sum proof Class [--] Maths AP proof NCERT AP sum formula CBSE AP"
YouTube Link 2025-09-03T06:49Z [---] followers, [--] engagements
"#AP #Class10 If n-2 4n-1 5n+2 are in AP Find n Answer = [--] Arithmetic Progression Class [--] question: Solve for n if n-2 4n-1 5n+2 are in AP. SEO: AP condition how to check numbers in AP find n in AP NCERT CBSE maths solutions. Question (rewritten): If the numbers n - [--] 4n - [--] and 5n + [--] are in AP find the value of n. Fast solution: For AP: 2nd 1st = 3rd 2nd (4n - 1) - (n - 2) = (5n + 2) - (4n - 1) 3n + [--] = n + [--] 3n - n = [--] - [--] 2n = [--] n = [--] ✅ Answer: n = [--] #ArithmeticProgression #Class10Maths #NCERT #CBSE #APFormula #ExamPrep #WhatIsTheAnswer #MathTrick"
YouTube Link 2025-08-30T05:13Z [---] followers, [--] engagements
"When Are Two A.P. Terms Equal Class [--] CBSE AP Trick 🎯 Two arithmetic progressions. One question: 👉 When will their nth terms become equal AP 1: [--] [--] [--]. AP 2: [--] [--] [--]. Learn how to equate AP terms step-by-step. Great revision for CBSE Class [--] students 🧮 Perfect question for board preparation. 📌 Like Comment your answer and Subscribe for more class [--] math tricks. #MathChallenge #ArithmeticProgression #CBSEClass10 #BoardExam2025 #StudyShorts #FastMaths #nthterm #MathsWithAbhiSir"
YouTube Link 2025-07-20T08:13Z [---] followers, [---] engagements
"AP Tricks: Find 'a' and 'd' in Seconds Class [--] Maths #maths #AP 📘 Topic: Find the first term and common difference of given Arithmetic Progressions (APs). We solve the following APs: [--] [--] [--] [--] [--] [--] [--] [--] [--] [--] [--] [--] [---] [---] [---] [---] 🧠 Concept: First term = first number in the AP Common difference = second term first term Perfect for Class [--] CBSE students learning AP basics #Class10Maths #ArithmeticProgression #FindCommonDifference #CBSE2025 #APFirstTerm #MathsWithAbhiSir #BoardMathsPrep #MathBasics #NumberPatterns #StudyShorts"
YouTube Link 2025-06-30T14:14Z [---] followers, [---] engagements
"AM = tanB=3/4 tanC=5/12 BC=56 AM = [--] cm #TrigTrick Geometry + Trigonometry: Find the altitude AM when BC = [--] cm and tan B = 3/4 tan C = 5/12. Short exam-ready solution below. SEO: altitude of triangle tanB and tanC given find AM Class [--] trig NCERT geometry problem. Question (rewritten): In ABC AM is perpendicular to BC. If tan B = 3/4 tan C = 5/12 and BC = [--] cm find the length of AM. Solution (step-by-step): 1) Drop altitude AM to BC at M. In right triangles ABM and ACM: tan B = AM / BM BM = AM / tan B tan C = AM / CM CM = AM / tan C 2) BC = BM + CM = AM(1/tan B + 1/tan C). 3) Therefore"
YouTube Link 2025-09-15T05:36Z [---] followers, [--] engagements
"AP [--] [--] [--] [--] : First negative term #ArithmeticProgression Class [--] AP Decreasing AP to first negative term using nth term formula. SEO: AP first negative term AP decreasing series Class [--] NCERT AP questions. Rewritten Question: Which term of the AP [--] [--] [--] [--] is the first negative term Quick Solution: a=65 d=4. a = [--] + (n1)(4) = [--] 4n For first negative: [--] 4n [--] n [-----] n = [--]. Check: a = [--] [--] = [--] (negative) a = [--] (positive). ✅ Answer: 18th term. #ArithmeticProgression #WhichTerm #APQuestion #NCERT #CBSE #BoardExamPrep #APFormula #MathsShorts"
YouTube Link 2025-08-23T05:01Z [---] followers, [--] engagements
"Class [--] Maths [--] Number System Explained Real Rational Irrational Integers & More 📚 Class [--] Maths Number System Full Concept Explained In this video we cover all types of numbers in detail: Natural Numbers Whole Numbers Integers Rational & Irrational Numbers Real Numbers With simple examples and clear explanation. 🎯 Perfect for CBSE ICSE and State Boards. 🔔 Dont forget to Subscribe for more Maths & Science lessons 📥 Share with friends and support the channel #class9maths #numbersystem #mathslecture #cbsemaths #rationalnumbers #irrationalnumbers #abhigargclasses"
YouTube Link 2025-05-22T15:11Z [---] followers, [--] engagements
"Sum of LAST [--] terms: AP [--] [--] [--] [---] Answer = [----] #AP #Class10 #NCERT AP last ten terms sum sum of last [--] terms AP Class [--] Arithmetic Progression NCERT solution. SEO: how to find sum of last [--] terms AP sum formula NCERT Class [--] AP CBSE maths tricks. Rewritten Question: Find the sum of the last ten terms of the AP: [--] [--] [--] [---]. Fast Solution (one glance): a = [--] d = [--] last term l = [---] Find total terms: [---] = [--] + (n1)2 n = [--] Last [--] terms are T51 to T60: first of this block = T51 = [--] + [---] = [---] Sum of last [--] = (10/2) (first_of_block + last_term) = [--] (108 + 126) = [--] [---] = [----] ✅ Final"
YouTube Link 2025-09-02T14:37Z [---] followers, [--] engagements
"Quick Proof: (cosecsin)(seccos)=1/(tan+cot) Problem: Show that (cosec A sin A)(sec A cos A) = [--] / (tan A + cot A). Short solution summary: [--]. Convert to sines and cosines: cosecsin = cos/sin and seccos = sin/cos. [--]. Multiply to get sinAcosA. [--]. RHS simplifies to 1/( (sin+cos)/(sincos) ) = sinAcosA. Thus both sides equal sinAcosA; identity proved. Domain: require sinA [--] and cosA [--] so expressions are defined. #Trigonometry #Class10Maths #MathsProof #AbhiGargClasses"
YouTube Link 2025-09-30T06:15Z [---] followers, [--] engagements
"Find altitude AM when tan B=3/4 tan C=5/12 and BC=56 cm Quick Trig Trick #Geometry #Trigonometry Geometry + Trigonometry: Find the altitude AM when BC = [--] cm and tan B = 3/4 tan C = 5/12. Short exam-ready solution below. SEO: altitude of triangle tanB and tanC given find AM Class [--] trig NCERT geometry problem. Question (rewritten): In ABC AM is perpendicular to BC. If tan B = 3/4 tan C = 5/12 and BC = [--] cm find the length of AM. Solution (step-by-step): 1) Drop altitude AM to BC at M. In right triangles ABM and ACM: tan B = AM / BM BM = AM / tan B tan C = AM / CM CM = AM / tan C 2) BC = BM"
YouTube Link 2025-09-15T05:33Z [---] followers, [--] engagements
"AP Trick: Sum of last [--] terms in [--------] = [----] ✅ AP last ten terms sum sum of last [--] terms AP Class [--] Arithmetic Progression NCERT solution. SEO: how to find sum of last [--] terms AP sum formula NCERT Class [--] AP CBSE maths tricks. Rewritten Question: Find the sum of the last ten terms of the AP: [--] [--] [--] [---]. Fast Solution (one glance): a = [--] d = [--] last term l = [---] Find total terms: [---] = [--] + (n1)2 n = [--] Last [--] terms are T51 to T60: first of this block = T51 = [--] + [---] = [---] Sum of last [--] = (10/2) (first_of_block + last_term) = [--] (108 + 126) = [--] [---] = [----] ✅ Final Answer: 1170"
YouTube Link 2025-09-02T14:35Z [---] followers, [--] engagements
"AP Trick: If a:a=2:3 find S:S (Answer 6:17) #ArithmeticProgression #Class10 AP ratio problem nth term to sum conversion Class [--] NCERTquick proof + final answer (6:17). SEO: Arithmetic Progression ratio a11:a18=2:3 find S5:S10 AP nth term AP sum formula Class [--] CBSE NCERT solutions. Question (rewritten): If the ratio of the 11th term of an AP to its 18th term is 2:3 find the ratio of the sum of the first five terms to the sum of its first ten terms. Fast solution: Let a be the first term and d the common difference. a = a + (n1)d Given a : a = (a+10d) : (a+17d) = [--] : [--] 3(a+10d) = 2(a+17d) 3a"
YouTube Link 2025-08-28T05:11Z [---] followers, [--] engagements
"Prove [--] + (cot)/(1 + cosec ) = cosec #Maths Problem: Prove that [--] + (cot) / (1 + cosec ) = cosec . Solution (step-by-step): [--]. Start with the LHS: [--] + (cot) / (1 + cosec ) = (1 + cosec ) + cot / (1 + cosec ) (write [--] as (1 + cosec )/(1 + cosec )) [--]. Use identity: [--] + cot = cosec Numerator = cosec + cosec = cosec (cosec + 1) [--]. So LHS = cosec (cosec + 1) / (1 + cosec ) = cosec . Hence proved: [--] + (cot) / (1 + cosec ) = cosec . #Trigonometry #MathsProof #Class10Maths #TrigIdentities (For more such proofs follow Abhi Garg Classes.)"
YouTube Link 2025-09-24T05:47Z [---] followers, [--] engagements
"Trig Identity:Q8 part V) (cossin+1)/(cos+sin1) = cosec + cot #Maths Problem: Prove (cos A sin A + 1)/(cos A + sin A 1) = cosec A + cot A. Solution summary: RHS = (1 + cos A)/sin A. Cross-multiply and expand both sides. Use sinA + cosA = [--] to show both sides match. Domain: sin A [--] and cos A + sin A [--] [--]. For more quick trig proofs follow Abhi Garg Classes"
YouTube Link 2025-10-01T05:44Z [---] followers, [--] engagements
"Trig Identity:Q8 part V) (cossin+1)/(cos+sin1) = cosec + cot #Maths Problem: Prove (cos A sin A + 1)/(cos A + sin A 1) = cosec A + cot A. Solution summary: RHS = (1 + cos A)/sin A. Cross-multiply and expand both sides. Use sinA + cosA = [--] to show both sides match. Domain: sin A [--] and cos A + sin A [--] [--]. For more quick trig proofs follow Abhi Garg Classes"
YouTube Link 2025-10-01T05:45Z [---] followers, [--] engagements
"🤔 Can you solve this in [--] secondsMath isnt tough you just need the right strategy Question: If two positive integers a and b are as a = x3y2 and b = xy3 where x y are prime numbers then the result obtained by dividing the product of the positive integers by the LCM (a b) is 🤔 Can you solve this in [--] seconds Math isnt tough you just need the right strategy Try this smart LCM trick from exponents 💡 🎓 Topic: Real Number Class [--] 🔔 Follow for more CBSE math tricks #class10maths #mathtricks #numberSystem #cbse2025 #abhigargclasses #shorts #reels"
YouTube Link 2025-06-01T07:57Z [---] followers, [---] engagements
"How to Find First Term and Common Difference of APs Class [--] Arithmetic Progression 📘 Topic: Find the first term and common difference of given Arithmetic Progressions (APs). We solve the following APs: [--] [--] [--] [--] [--] [--] [--] [--] [--] [--] [--] [--] [---] [---] [---] [---] 🧠 Concept: First term = first number in the AP Common difference = second term first term Perfect for Class [--] CBSE students learning AP basics #Class10Maths #ArithmeticProgression #FindCommonDifference #CBSE2025 #APFirstTerm #MathsWithAbhiSir #BoardMathsPrep #MathBasics #NumberPatterns #StudyShorts"
YouTube Link 2025-06-30T14:16Z [---] followers, [--] engagements
"#SumOfAP Find the Sum of These Tricky APs #WhatIsTheSum #Class10Maths #CBSE2025 📘 Lets solve [--] interesting AP sums These questions test your understanding of AP Sum Formula (Sn). Watch this step-by-step breakdown for: (i) [--] + [----] + [--] +. + [--] (ii) [--] + [--] + [--] +. + [--] (iii) [--] + (8) + (11) +. + (230) Perfect for Class [--] CBSE [----] prep 📚 👇 Comment your answers below #WhatIsTheSum #SumOfAP #Class10Maths #CBSE2025 #MathsQuiz #ArithmeticProgression #SnFormula #LearnWithAbhiSir #MathsReel #NTHTerm #FormulaBasedQuestion #BoardExamPrep"
YouTube Link 2025-07-27T07:06Z [---] followers, [--] engagements
"Trig Proof: tan/(1cot) + cot/(1tan) = [--] + seccsc #Maths Problem: Prove fractantheta1-cottheta + fraccottheta1-tantheta = [--] + secthetacsctheta. Solution summary: Convert tan and cot to sin/cos and simplify. Combine terms factor sin3cos3 and cancel (sincos). Use sin2+cos2 = [--] to reach [--] + 1/(sincos) = [--] + seccsc. Perfect for Class [--] practice and quick exam revision. (Abhi Garg Classes)"
YouTube Link 2025-10-06T05:21Z [---] followers, [--] engagements
"AP Sum Proof 🔥 (a+c)(b+c-2a)/2(b-a) #Maths #Class10 📘 In this video we solve an important NCERT/CBSE Class [--] Maths question on Arithmetic Progressions (AP). We are asked to show that the sum of an AP with first term a second term b and last term c is equal to (a+c)(b+c-2a) / 2(b-a). 👉 This proof is a frequently asked question in exams and is very important for Class [--] board preparation. 👉 We carefully break it down step by step for better understanding. ✨ Keywords: Arithmetic Progression sum proof Class [--] Maths AP proof NCERT AP sum formula CBSE AP questions. #Maths"
YouTube Link 2025-09-03T06:51Z [---] followers, [--] engagements
"3-digit number in AP Digits sum [--] & reverse is [---] less Important Class [--] AP Question #Maths Class [--] Maths Arithmetic Progression Important AP Word Problem 👉 Question: The digits of a three-digit positive integer are in AP. Their sum is [--]. The number obtained by reversing the digits is [---] less than the original number. Find the number. 🔎 Key Concepts: - Digits in AP middle digit = average of first and last. - Sum of digits = [--]. - Reversed number = Original number [---]. - Equation solving with AP logic. 📘 Solution Highlights: Let digits be (a d) a (a + d). Sum = (a d) + a + (a + d) ="
YouTube Link 2025-09-07T13:23Z [---] followers, [--] engagements
"Can You Fill the Missing AP Terms Class [--] CBSE #Ap #exercise5.2 #question3 📘 Topic: Fill in the missing terms in the given Arithmetic Progressions (APs) using the formula: 👉 an = a + (n 1)d In this video we solve [--] different APs where some terms are missing. Learn how to find them step-by-step 🔥 Must-watch for Class [--] CBSE students preparing for board exams 📌 Like comment and subscribe for more concept-wise short videos #ArithmeticProgression #MissingTermsInAP #Class10Maths #CBSEBoard2025 #MathsWithAbhiSir #FillTheBlanksAP #APChapterClass10 #MathConcepts #BoardExamPrep"
YouTube Link 2025-07-08T11:23Z [---] followers, [--] engagements
"Find [--] AP numbers: Sum [--] & product ratio 7:15 Quick Solve #AP #WhatIs AP problem: find four consecutive AP terms when their sum is [--] and (firstlast) : (2nd3rd) = [--] : [--] Answer: [--] [--] [--] [--]. SEO keywords: Arithmetic Progression find numbers in AP AP product ratio sum of AP Class [--] NCERT problem. Question (rewritten): The sum of four consecutive numbers in an AP is [--] and the ratio of the product of the first and the last terms to the product of the two middle terms is [--] : [--]. Find the numbers. Short solution: Let the four consecutive AP terms be a a+d a+2d a+3d. Sum 4a + 6d = [--] 2a + 3d = 16"
YouTube Link 2025-09-01T05:09Z [---] followers, [---] engagements
"🟰 Find Dimensions of Triangle Quadratic Equation Word Problem Class [--] Maths 📘 Quadratic Equation Word Problem Class [--] CBSE Maths 🔹 Question: The area of a right-angled triangle is [---] cm. If the base exceeds the height by [--] cm find the dimensions of the triangle. 🧠 In this short video: Learn to form and solve a quadratic equation from a geometry word problem Use the area formula ( base height) with smart substitution Solve it step-by-step in an easy way 🎓 Best for: ✔ CBSE Class [--] Students ✔ Word problem practice ✔ Concept strengthening & exam readiness 👨🏫 Explained by Abhi Sir"
YouTube Link 2025-06-15T13:27Z [---] followers, [---] engagements
"#AP Question Sum of Two Middle Terms in AP: -4/3 [---] -2/3. [--] #Class10 #NCERT 📘 In this video we solve an NCERT Class [--] Arithmetic Progression problem: Find the sum of the two middle most terms of the AP: -4/3 [---] -2/3 [--]. 👉 We calculate the total number of terms identify the two middle terms and then find their sum step by step. 👉 This is an important CBSE exam-style question from the Arithmetic Progressions chapter. ✨ Keywords: Arithmetic Progression middle terms Class [--] Maths AP NCERT AP questions CBSE AP sums sum of middle terms in AP. #Maths #ArithmeticProgression #NCERT #CBSE"
YouTube Link 2025-09-04T06:03Z [---] followers, [--] engagements
"Trig Proof: tan/(1cot) + cot/(1tan) = [--] + seccsc #Maths Problem: Prove fractantheta1-cottheta + fraccottheta1-tantheta = [--] + secthetacsctheta. Solution summary: Convert tan and cot to sin/cos and simplify. Combine terms factor sin3cos3 and cancel (sincos). Use sin2+cos2 = [--] to reach [--] + 1/(sincos) = [--] + seccsc. Perfect for Class [--] practice and quick exam revision. (Abhi Garg Classes)"
YouTube Link 2025-10-06T05:21Z [---] followers, [--] engagements
"Quick Proof: (cot cosec ) = (1 cos )/(1 + cos ) #Maths Problem: Prove (cot cosec ) = (1 cos )/(1 + cos ). Solution summary: [--]. cot cosec = (cos 1)/sin = (1 cos )/sin . [--]. Square and use sin = [--] cos = (1 cos )(1 + cos ). [--]. Cancel (1 cos ) to get (1 cos )/(1 + cos ). Domain: sin [--] so cot and cosec are defined. #Trigonometry #Class10Maths #MathsProof #AbhiGargClasses"
YouTube Link 2025-10-07T05:34Z [---] followers, [--] engagements
"Different way: If tan + cot = [--] ( acute) Find tan + cot Trig Quick Trick #Trigonometry Trigonometry trick: If tan + cot = [--] ( acute) find tan7 + cot7. Quick proof and result perfect for exam prep and short-form maths videos. Question (rewritten): If is an acute angle and tan + cot = [--] find tan7 + cot7 . Solution (short): Let t = tan. Then t + 1/t = [--] (t2 + 1)/t = [--] t2 2t + [--] = [--] (t 1)2 = [--] t = [--] (since is acute). So tan = [--] and cot = [--]. Hence tan7 + cot7 = [--] + [--] = [--]. ✅ Final Answer: [--] #Trigonometry #TrigTrick #tanpluscot #WhatIsTheAnswer #HowToSolve #MathsShorts #Class10Maths #NCERT #CBSE"
YouTube Link 2025-09-14T13:41Z [---] followers, [--] engagements
"Quick Proof: [--] + (cot)/(1 + cosec ) = cosec Problem: Prove that [--] + (cot) / (1 + cosec ) = cosec . Solution (step-by-step): [--]. Start with the LHS: [--] + (cot) / (1 + cosec ) = (1 + cosec ) + cot / (1 + cosec ) (write [--] as (1 + cosec )/(1 + cosec )) [--]. Use identity: [--] + cot = cosec Numerator = cosec + cosec = cosec (cosec + 1) [--]. So LHS = cosec (cosec + 1) / (1 + cosec ) = cosec . Hence proved: [--] + (cot) / (1 + cosec ) = cosec . #Trigonometry #MathsProof #Class10Maths #TrigIdentities (For more such proofs follow Abhi Garg Classes.)"
YouTube Link 2025-09-24T05:48Z [---] followers, [--] engagements
"tan + cot = [--] tan + cot = Trig Trick #Maths Trigonometry trick: If tan + cot = [--] ( acute) find tan7 + cot7. Quick proof and result perfect for exam prep and short-form maths videos. Question (rewritten): If is an acute angle and tan + cot = [--] find tan7 + cot7 . Solution (short): Let t = tan. Then t + 1/t = [--] (t2 + 1)/t = [--] t2 2t + [--] = [--] (t 1)2 = [--] t = [--] (since is acute). So tan = [--] and cot = [--]. Hence tan7 + cot7 = [--] + [--] = [--]. ✅ Final Answer: [--] #Trigonometry #TrigTrick #tanpluscot #WhatIsTheAnswer #HowToSolve #MathsShorts #Class10Maths #NCERT #CBSE #ExamPrep"
YouTube Link 2025-09-13T05:50Z [---] followers, [---] engagements
"#FindSn When S = [--] and S = [---] AP Sum Formula #ArithmeticProgression #Class10Maths In this video we solve: "If the sum of first [--] terms of an AP is [--] and that of [--] terms is [---] find the sum of first n terms." We use the formula: S = n/2 (2a + (n - 1)d) and simplify using given values to find a general expression for S. A perfect AP Sum problem from CBSE Class [--] Arithmetic Progression chapter. #FindSn #APSum #ArithmeticProgression #APFormula #CBSEMaths #NCERTSolution #Class10Maths #MathsQuestion #WhatIsSn #HowToFindSum"
YouTube Link 2025-08-01T05:05Z [---] followers, [--] engagements
"First negative term in [------] #AP Class [--] AP Decreasing AP to first negative term using nth term formula. SEO: AP first negative term AP decreasing series Class [--] NCERT AP questions. Rewritten Question: Which term of the AP [--] [--] [--] [--] is the first negative term #ArithmeticProgression #WhichTerm #APQuestion #NCERT #CBSE #BoardExamPrep #APFormula #MathsShorts"
YouTube Link 2025-08-23T05:02Z [---] followers, [--] engagements
"AP Problem: Sum = [--] & (1st4th):(2nd3rd)=7:15 Find the [--] numbers #What #How AP problem: find four consecutive AP terms when their sum is [--] and (firstlast) : (2nd3rd) = [--] : [--] Answer: [--] [--] [--] [--]. SEO keywords: Arithmetic Progression find numbers in AP AP product ratio sum of AP Class [--] NCERT problem. Question (rewritten): The sum of four consecutive numbers in an AP is [--] and the ratio of the product of the first and the last terms to the product of the two middle terms is [--] : [--]. Find the numbers. Short solution: Let the four consecutive AP terms be a a+d a+2d a+3d. Sum 4a + 6d = [--] 2a + 3d"
YouTube Link 2025-09-01T05:07Z [---] followers, [--] engagements
"14 Trigonometry tan7 a + cot7 a Trigonometry trick: If tan + cot = [--] ( acute) find tan7 + cot7. Quick proof and result perfect for exam prep and short-form maths videos. Question (rewritten): If is an acute angle and tan + cot = [--] find tan7 + cot7 . Solution (short): Let t = tan. Then t + 1/t = [--] (t2 + 1)/t = [--] t2 2t + [--] = [--] (t 1)2 = [--] t = [--] (since is acute). So tan = [--] and cot = [--]. Hence tan7 + cot7 = [--] + [--] = [--]. ✅ Final Answer: [--] #Trigonometry #TrigTrick #tanpluscot #WhatIsTheAnswer #HowToSolve #MathsShorts #Class10Maths #NCERT #CBSE #ExamPrep"
YouTube Link 2025-09-13T05:49Z [---] followers, [--] engagements
"Diiferent Way: tan + cot = [--] tan + cot = Trig Trick #Maths Trigonometry trick: If tan + cot = [--] ( acute) find tan7 + cot7. Quick proof and result perfect for exam prep and short-form maths videos. Question (rewritten): If is an acute angle and tan + cot = [--] find tan7 + cot7 . Solution (short): Let t = tan. Then t + 1/t = [--] (t2 + 1)/t = [--] t2 2t + [--] = [--] (t 1)2 = [--] t = [--] (since is acute). So tan = [--] and cot = [--]. Hence tan7 + cot7 = [--] + [--] = [--]. ✅ Final Answer: [--] #Trigonometry #TrigTrick #tanpluscot #WhatIsTheAnswer #HowToSolve #MathsShorts #Class10Maths #NCERT #CBSE #ExamPrep"
YouTube Link 2025-09-14T13:43Z [---] followers, [--] engagements
"Trig Proof: (1+sec)/sec = sin/(1cos) Problem: Prove (1 + sec A)/sec A = sinA/(1 cos A). Short solution: LHS = (1+secA)/secA = 1/secA + [--] = cosA + [--]. RHS = sinA/(1cosA) = (1cosA)/(1cosA) = 1+cosA (after cancellation). Thus both sides equal [--] + cosA where defined. Domain: require cosA [--] and [--] cosA [--] for direct cancellation; equality's simplified form 1+cosA holds when expressions are defined. (Abhi Garg Classes)"
YouTube Link 2025-10-10T04:54Z [---] followers, [--] engagements
"Sum of integers divisible by [--] between [---] and [---] Class [--] Maths #AP In this video we solve an important Arithmetic Progression (AP) problem: ❓ Find the sum of integers between [---] and [---] that are (i) divisible by [--] (ii) not divisible by [--] This type of question is frequently asked in Class [--] Maths exams (AP Chapter NCERT/Exemplar) and is super useful for board exam preparation. Watch till the end to understand the step-by-step solution ✨ #Maths #AP #ArithmeticProgression #Class10 #NCERT #ExamPrep #MathsTricks #Algebra"
YouTube Link 2025-09-02T04:41Z [---] followers, [--] engagements
"How many terms needed to get [---] from AP [----] [--]. #WhatIsN #FindTerms #APSolved In this video we solve this Arithmetic Progression problem: "How many terms of the AP [----] [--]. must be taken so that their sum is 636" We use the AP sum formula: S = n/2 2a + (n - 1)d to find the number of terms (n). Perfect for CBSE Class [--] students and those preparing for competitive exams. #FindNumberOfTerms #HowManyTerms #WhatIsN #APSolved #ArithmeticProgression #NCERTQuestion #CBSEMaths #Class10Maths #MathHelp #APFormula #MathShorts"
YouTube Link 2025-07-31T05:56Z [---] followers, [---] engagements
"NCERT Volume Check Spherical Vessel + Cylindrical Neck Class [--] Maths Chapter [--] Solution 🎯 Can you calculate the precise volume of this tricky spherical vessel Question: A spherical glass vessel has a cylindrical neck [--] cm long [--] cm in diameter; the diameter of the spherical part is [---] cm. By measuring the amount of water it holds a child finds its volume to be [---] cm. Check whether she is correct taking the above as the inside measurements and = [----]. Concept: This question requires calculating the volume of a composite solid by adding the volume of a cylinder (rH) and the volume of a"
YouTube Link 2025-12-12T05:02Z [---] followers, [--] engagements
"Cylinder with Conical Cavity Total Surface Area (Answer: [--] cm) Class [--] Mensuration Problem: From a solid cylinder (height [---] cm diameter [---] cm) a cone of same height and diameter is removed. Find the total surface area of the remaining solid. Solution summary: r = [---] cm h = [---] cm cone slant l = [---] cm. Cylinder lateral = 2rh = [----]. Bottom face = r = [----]. Inner cone lateral = rl = [----]. Total = [---] [-----] cm 18 cm (nearest cm). #Mensuration #SurfaceArea #Class10Maths #Cylinder #Cone #Geometry #AbhiGargClasses"
YouTube Link 2025-11-23T05:28Z [---] followers, [---] engagements
"Find sum of first n terms when S = [--] & S = [---] #FindSn #APSum #Class10Maths In this video we solve: "If the sum of first [--] terms of an AP is [--] and that of [--] terms is [---] find the sum of first n terms." We use the formula: S = n/2 (2a + (n - 1)d) and simplify using given values to find a general expression for S. A perfect AP Sum problem from CBSE Class [--] Arithmetic Progression chapter. #FindSn #APSum #ArithmeticProgression #APFormula #CBSEMaths #NCERTSolution #Class10Maths #MathsQuestion #WhatIsSn #HowToFindSum"
YouTube Link 2025-08-01T05:06Z [---] followers, [---] engagements
"CSA of Cone = CSA of Hemisphere Find the Height (h) in terms of Radius (r) Class [--] Mensuration 🔥 Don't let solid geometry formulas confuse you This is a classic CBSE/ICSE board exam question dealing with the relationship between a cone and a hemisphere. Question: A solid consists of a hemisphere at the bottom and a cone above it both having the same base radius r. If the curved surface areas (CSA) of the hemisphere and cone are equal then find the height (h) of the conical part. Concept Explained: We set the fundamental formulas for Curved Surface Area (CSA) of a hemisphere (2r) and a cone"
YouTube Link 2026-01-07T04:34Z [---] followers, [---] engagements
"Area of Shaded Path TRICK Mensuration Geometry Problem Solved Step-by-Step (Class [--] & 10) 🔥 Quick and easy way to solve complex area problems This video breaks down a common Mensuration question often seen in Class [--] and Class [--] exams. ❓ The Question: Find the area of the shaded region in Fig. [----]. Outer rectangle: [--] m x [--] m. Inner gaps: [--] m (sides) [--] m (top/bottom). ✍ Concept Explained: To find the area of a uniform path or shaded border surrounding an inner figure simply find the difference between the area of the outer figure and the area of the inner figure. This 'area subtraction'"
YouTube Link 2026-01-22T04:52Z [---] followers, [--] engagements
"Rocket Maths Solved 🚀 Find Surface Area & Volume of Cylinder and Cone Composite Solids (Class 10) Welcome to ABHI GARG CLASSES In this detailed session for Class [--] Mathematics students we tackle a crucial problem from the chapter on Surface Area and Volume of Composite Solids. This question is frequently asked in CBSE and ICSE board exams. The Question: A rocket is in the form of a right circular cylinder closed at the lower end and surmounted by a cone with the same radius as that of the cylinder. The diameter and height of the cylinder are [--] cm and [--] cm respectively. If the slant"
YouTube Link 2025-12-03T06:26Z [---] followers, [---] engagements
"Hour Hand Problem SOLVED Area Swept by Clock Hand in [--] Minutes Class [--] Maths 🔥 Catchy Hook: Stop guessing the angle Learn the precise formula for clock problems and master the application of the Area of a Sector formula (A = (/360) R). Question: The hour hand of a clock is [--] cm long. The area swept by it between 11:20 am and 11:55 am is calculated step-by-step. Concept: We utilize the fundamental angular speed of the hour hand (0.5 per minute) to find the angle () and then apply the sector area formula. This is an essential concept for Class [--] Board exams 📌 Location: Abhi Garg Classes"
YouTube Link 2026-01-20T01:48Z [---] followers, [---] engagements
"🔥 Cube Carving Problem Surface Area of Remaining Solid (Cube + Hemispherical Depression) Class [--] Welcome to Abhi Garg Classes 🔥 Are you struggling with surface area problems involving combined solids Question: A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter 'l' of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid. In this video we break down this tricky carving problem step-by-step. The key concept is understanding that the external surface area changes: we lose the area of the circular"
YouTube Link 2025-12-27T05:06Z [---] followers, [--] engagements
"DOUBLE CONE Surface Area TRICK (r=8 h=15) Class [--] Maths CBSE Surface Area and Volume Question 🔥 Welcome to ABHI GARG CLASSES In this essential Class [--] Mathematics tutorial we tackle a critical problem from the Surface Area and Volume chapter involving composite solids. This is a common high-scoring question in CBSE/ICSE board exams. 📚 Question Covered: Two cones with the same base radius (r = [--] cm) and height (h = [--] cm) are joined together along their bases. Find the total surface area of the shape so formed. Key Concepts You Will Learn: [--]. Identifying the correct formula for the TSA of"
YouTube Link 2025-11-29T05:40Z [---] followers, [--] engagements
"CLASS [--] MATHS: Surface Area of Hemisphere Mounted by Cylinder Mensuration Full Solution CBSE 🔥 Mastering Mensuration: Solve the toughest Surface Area problems effortlessly This video breaks down a crucial Class [--] question involving a vessel formed by a hollow hemisphere and a hollow cylinder. Question: A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. The diameter of the hemisphere is [--] cm and the total height of the vessel is [--] cm. Find the inner surface area of the vessel. Concept Explained: Learn why we calculate the Curved Surface Area (CSA) and how to"
YouTube Link 2025-12-31T05:14Z [---] followers, [--] engagements
"How to Find the Volume of the LARGEST Cone Carved from a Cube (Side [--] cm) Class 9/10 Geometry 🔥 Geometry Visualisation Challenge 🔥 Question: The volume of the largest right circular cone that can be carved out from a solid cube of side length [--] cm is: This video explains the crucial relationship between the dimensions of the base object (the cube) and the derived object (the cone). For the largest possible fit the cone's height and diameter must equal the cube's side length. Perfect for quick revision of Surface Areas and Volumes Join us at Abhi Garg Classes Sector [--] Chandigarh for"
YouTube Link 2026-01-14T05:17Z [---] followers, [--] engagements
"Hemispherical Bowl Volume Trick Find Volume of Steel Used Surface Area & Volume Class [--] 🎯 Quick Math Challenge Can you calculate the exact volume of steel used in this hemispherical bowl Question: A hemispherical bowl is made of steel of thickness [----] cm. The inner radius of the bowl is [--] cm. The volume of steel used (in cu cm) is: In this detailed video Abhi Garg explains the key concept for hollow solids: finding the volume of material by calculating V_outer - V_inner. This is an essential high-scoring topic for CBSE Class [--] and Class [--] geometry exams. Need expert guidance to ace your"
YouTube Link 2026-01-11T14:37Z [---] followers, [--] engagements
"TSA of Cone Mounted on Hemisphere Class [--] Maths Surface Area and Volume (NCERT ) Don't lose marks on composite solids Learn the simplest method to find the Total Surface Area (TSA) of a toy combining a cone and a hemisphere. Question: A toy is in the form of a cone of radius [---] cm mounted on a hemisphere of the same radius. The total height of the toy is [----] cm. Find the total surface area of the toy. Concept Explained: Remember for the total surface area of a composite solid you only add the exposed Curvature Surface Areas (CSA). Finding the slant height (l) using the Pythagorean theorem"
YouTube Link 2026-01-01T05:13Z [---] followers, [--] engagements
"Angle [--] [--] after [--] m Find tree height & river width (Answer: [-----] m [--] m) #Trigonometry Question: From the bank angle of elevation to a tree on opposite bank = [--]. After moving [--] m away angle becomes [--]. Find the tree's height and the river width. Solution summary: Let river width = d. From tan60 = h/d h = d3. From tan30 = h/(d+40) h = (d+40)/3. Solving gives d = [--] m and h = [---] [-----] m. Final: Height = [-----] m Width = [-----] m. #Trigonometry #HeightAndDistance #Class10Maths #NCERT #MathsWithAbhi #QuickSolution"
YouTube Link 2025-11-21T05:29Z [---] followers, [--] engagements
"NCERT Volume Check Spherical Vessel + Cylindrical Neck Class [--] Maths Chapter [--] Solution 🎯 Can you calculate the precise volume of this tricky spherical vessel Question: A spherical glass vessel has a cylindrical neck [--] cm long [--] cm in diameter; the diameter of the spherical part is [---] cm. By measuring the amount of water it holds a child finds its volume to be [---] cm. Check whether she is correct taking the above as the inside measurements and = [----]. Concept: This question requires calculating the volume of a composite solid by adding the volume of a cylinder (rH) and the volume of a"
YouTube Link 2025-12-12T05:03Z [---] followers, [--] engagements
"FIND THE HEIGHT Volume of Cylinder and Hemispherical Dome Problem Class [--] Mensuration CBSE 🔥 Geometry Alert Don't miss this classic volume problem crucial for your board exams Question: A building is in the form of a cylinder surmounted by a hemispherical dome. The base diameter (D) of the dome is equal to 2/3 of the total height (H) of the building. Find the height of the building if it contains [--] 1/21 m of air. Concept Explained: We simplify the complex relationship by expressing both the cylinder's height (h) and the radius (R) in terms of the Total Height (H). This reduces the entire"
YouTube Link 2025-12-14T05:04Z [---] followers, [---] engagements
"🔥 Cube Carving Problem Surface Area of Remaining Solid (Cube + Hemispherical Depression) Class [--] Welcome to Abhi Garg Classes 🔥 Are you struggling with surface area problems involving combined solids Question: A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter 'l' of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid. In this video we break down this tricky carving problem step-by-step. The key concept is understanding that the external surface area changes: we lose the area of the circular"
YouTube Link 2025-12-27T05:08Z [---] followers, [---] engagements
"Area of Shaded Region: Square Inscribed in a Quadrant Class [--] CBSE Geometry Mastery 🔥 Quick Geometry Challenge Can you find the area of the shaded region when a square is inscribed in a quarter circle Question: A square OABC is inscribed in a quadrant OPBQ. If the side OA = [--] cm find the area of the shaded region. (Use = 3.14). This video walks you through the crucial concept: realizing that the diagonal of the inscribed square serves as the radius of the quadrant. We use the Pythagorean theorem to find R easily simplifying the calculation of the quadrant's area. 📍 Visit Abhi Garg Classes"
YouTube Link 2026-01-21T07:15Z [---] followers, [--] engagements
"💊 Surface Area of a Medicine Capsule Combined Solids Class [--] Maths NCERT Ex [----] Q3 Solution Stop scrolling Can you calculate how much material is needed to coat this standard medicine capsule Question: A medicine capsule is in the shape of a cylinder with two hemispheres stuck to each of its ends. The length of the entire capsule is [--] mm and the diameter of the capsule is [--] mm. Find its surface area. This problem involves finding the total surface area of a composite figure: a cylinder capped by two hemispheres. Remember you only calculate the curved surface area (CSA) of the individual"
YouTube Link 2025-12-28T04:54Z [---] followers, [---] engagements
"VOLUME OF WOOD Cuboid with Conical & Cubical Depressions Surface Areas and Volumes Class [--] Welcome to ABHI GARG CLASSES Master the tricky questions from Class [--] Mathematics. This video focuses on a crucial question from the Surface Areas and Volumes chapter often featured in CBSE and ICSE board exams. 🎯 The Question: A wooden pen stand is shaped like a cuboid (length = [--] cm width = [--] cm height = [--] cm). It has four identical conical depressions (radius r = [---] cm depth h = [---] cm) and one cubical depression (edge a = [--] cm) for holding pens and pins. Find the volume of the wood used in the"
YouTube Link 2025-12-05T05:45Z [---] followers, [---] engagements
"Hemisphere TSA Ratio Secret Surface Area & Volume Class [--] Maths Quick Trick Are you often confused about the difference between Curved Surface Area and Total Surface Area of a hemisphere This quick problem will cement the concept for you ❓ QUESTION: The ratio of total surface area of a solid hemisphere to the square of its radius is: CONCEPT EXPLAINED: The total surface area of a SOLID hemisphere is 3r because it includes both the curved part and the flat circular base. Setting up the ratio (3r / r) simplifies beautifully to [--] : [--]. Master Mathematics and Science from Class 8th to 12th. Join"
YouTube Link 2026-01-15T04:50Z [---] followers, [---] engagements
"Industrial Shed Volume Calculation Cuboid & Half Cylinder Volume Class [--] Maths Application 🎯 Can you solve this real-world volume problem We calculate the total air capacity of an industrial shed shaped like a cuboid surmounted by a half cylinder and then subtract the space occupied by machinery and workers. QUESTION: Shanta runs an industry in a shed which is in the shape of a cuboid surmounted by a half cylinder. If the base of the shed is of dimension [--] m x [--] m and the height of the cuboidal portion is [--] m find the volume of air that the shed can hold. Further suppose the machinery in"
YouTube Link 2025-12-15T05:37Z [---] followers, [---] engagements
"Sphere vs. [--] Hemispheres: Surface Area Ratio TRICK (4r vs 6r Explained) Class [--] Math 🚨 Stop guessing the surface area ratio When a solid sphere is cut into two hemispheres the total surface area changes drastically. This is a crucial concept for CBSE Class [--] and [--] board exams. ❓ The Question: A solid sphere is cut exactly into two hemispheres. What is the ratio of the surface area of the original sphere to the total combined surface area of the two resulting hemispheres 💡 Concept Insight: Remember that the total surface area of a hemisphere includes the curved area (2r) plus the new flat"
YouTube Link 2026-01-13T04:29Z [---] followers, [--] engagements
"Volume of Solid (Cone on Hemisphere) Class [--] Maths Board Exam Question Quick Geometry Solution Can you solve this Class [--] geometry problem in [--] seconds Its simpler than you think Question: A solid is in the shape of a cone standing on a hemisphere with both their radii being equal to [--] cm and the height of the cone is equal to its radius. Find the volume of the solid in terms of pi. Concept: Mastering the volume of composite solids involves breaking down the structure into standard shapes (like cones and hemispheres) and applying their respective formulas. The key here is realizing that"
YouTube Link 2025-12-26T04:59Z [---] followers, [--] engagements
"Prove V = (131 / 96) R Volume of Combined Solids Sphere & Cylinder Math Proof (Class 10) Stop struggling with complicated Mensuration proofs This question beautifully combines the volumes of a sphere and a cylinder requiring careful algebraic substitution. We break down the steps to prove that the total volume is (131 / 96) R. Question: A spherical glass vessel has a cylindrical neck whose radius (r) is R/8 and height (h) is 2R. Prove V = (131 / 96) R. This concept is crucial for scoring high marks in surface area and volume chapters. Mastering substitution and fractions is key 📍 Find expert"
YouTube Link 2026-01-11T05:10Z [---] followers, [--] engagements
"Ladder slides from [--] to [--] Find foot distance (Answer: [--] m) #Trigonometry Problem: A ladder reaches [--] m on a wall at [--]. After pulling its foot out it makes [--] with the ground. Find the distance of the foot from the wall. Solution summary: Let ladder length = L. From sin60 = 5/L L = 10/3. At [--] horizontal distance = Lcos30 = (10/3)(3/2) = [--] m. Final answer: [--] m. #Trigonometry #HeightAndDistance #LadderProblem #Class10Maths #MathsShorts #AbhiGargClasses"
YouTube Link 2025-11-16T05:47Z [---] followers, [--] engagements
"CLASS [--] MATHS: Surface Area of Hemisphere Mounted by Cylinder Mensuration Full Solution CBSE 🔥 Mastering Mensuration: Solve the toughest Surface Area problems effortlessly This video breaks down a crucial Class [--] question involving a vessel formed by a hollow hemisphere and a hollow cylinder. Question: A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. The diameter of the hemisphere is [--] cm and the total height of the vessel is [--] cm. Find the inner surface area of the vessel. Concept Explained: Learn why we calculate the Curved Surface Area (CSA) and how to"
YouTube Link 2025-12-31T05:14Z [---] followers, [---] engagements
"MASSIVE IRON POLE WEIGHT CALCULATION (892 kg) Class [--] Maths Surface Area & Volume Hook: Ready to calculate the weight of this massive industrial iron pole just using geometry Let's find out Question: A solid iron pole consists of a cylinder of height [---] cm and base diameter [--] cm which is surmounted by another cylinder of height [--] cm and radius [--] cm. Find the mass of the pole given that [--] cm of iron has approximately [--] g mass. (Use = 3.14). Concept: This problem requires finding the volume of two cylinders and adding them up (Volume of Combined Solids). We then use the given density (mass"
YouTube Link 2025-12-20T07:32Z [---] followers, [--] engagements
"Open Box Volume & Weight Problem Solved Critical Class 10/12 Mensuration Question 🎯 STOP losing marks on Mensuration The 'Open Box' problem has one subtle trick you MUST know regarding internal height. We solve this complete volume and weight question step-by-step. ❓ Question: How many cubic centimetres of iron is required to construct an open box whose external dimensions are [--] cm [--] cm and [----] cm provided the thickness of the iron is [---] cm. If one cubic cm of iron weighs [---] g find the weight of the box. 💡 Concept Focus: When calculating the internal dimensions of an open box with"
YouTube Link 2025-12-09T08:31Z [---] followers, [--] engagements
"MELTED IRON BLOCK to [---] METER PIPE 🤯 Class [--] Maths Board Exam Question Volume & Recasting Welcome to ABHI GARG CLASSES In this essential Class [--] Mathematics video we solve a challenging Mensuration problem involving the concept of 'Recasting Solids'. When a solid is melted and recast the total volume remains constant. This question tests your ability to handle complex unit conversions and the formula for the volume of a hollow cylinder. FULL QUESTION: A solid iron cuboidal block of dimensions [---] m x [---] m x [--] m is recast into a hollow cylindrical pipe of internal radius [--] cm and"
YouTube Link 2025-12-02T05:08Z [---] followers, [--] engagements
"Stool Design: Find Leg Length & Step Lengths Practical Trigonometry #Maths Problem: A stool has a square top of side [---] m at height [---] m. Each leg is inclined at [--] to the ground. Find (1) the length of each leg and (2) lengths of two steps fixed at equal vertical intervals (heights [---] m and [---] m). Solution summary: [--]. Leg length L: vertical component = Lsin60 = [---] L = [---] / sin60 = [---] / (3/2) = [--] [-----] m. [--]. At a level y above ground horizontal distance between opposite legs = [---] + 2(1.5 y)/3. - For y = [---] m: step length = [---] + 2(1.0)/3 = [---] + 2/3 [------] m. - For y = [---] m: step"
YouTube Link 2025-11-02T05:04Z [---] followers, [--] engagements
"MELTED IRON BLOCK to [---] METER PIPE 🤯 Class [--] Maths Board Exam Question Volume & Recasting Welcome to ABHI GARG CLASSES In this essential Class [--] Mathematics video we solve a challenging Mensuration problem involving the concept of 'Recasting Solids'. When a solid is melted and recast the total volume remains constant. This question tests your ability to handle complex unit conversions and the formula for the volume of a hollow cylinder. FULL QUESTION: A solid iron cuboidal block of dimensions [---] m x [---] m x [--] m is recast into a hollow cylindrical pipe of internal radius [--] cm and"
YouTube Link 2025-12-02T05:09Z [---] followers, [--] engagements
"Sphere Dropped in Cylinder: How to Calculate Water Level Rise (Surface area and Volume Class 10) 🎯 Catchy Hook: Can the size of the container really determine how much water rises Yes and the math behind it is simple geometry Question: A sphere of diameter [--] cm is dropped into a cylindrical vessel of diameter [--] cm partly filled with water. If the sphere is completely submerged what is the rise in the water level Concept: We use the fundamental principle of volume displacement: the volume of the sphere is equal to the volume of the cylindrical column of water that rises. This is a must-know"
YouTube Link 2026-01-18T06:01Z [---] followers, [--] engagements
"SURFACE AREA of Cuboid Formed by Joining Two Cubes Mensuration Class [--] CBSE (Solved in [--] Steps) 🚀 INSTANT MATH LESSON Are you struggling with Mensuration Watch how we solve this classic problem involving joining two cubes and finding the new surface area Question: Two cubes each of volume [--] cm are joined end to end. Find the surface area of the resulting cuboid. Concept: When two identical cubes (side 'a') are joined only the length changes (becomes 2a) while the breadth and height remain 'a'. The resulting shape is a cuboid. We then apply the cuboid surface area formula: TSA = 2(LB + BH +"
YouTube Link 2025-12-30T04:29Z [---] followers, [---] engagements
"VOLUME OF WOOD Cuboid with Conical & Cubical Depressions Surface Areas and Volumes Class [--] Welcome to ABHI GARG CLASSES Master the tricky questions from Class [--] Mathematics. This video focuses on a crucial question from the Surface Areas and Volumes chapter often featured in CBSE and ICSE board exams. 🎯 The Question: A wooden pen stand is shaped like a cuboid (length = [--] cm width = [--] cm height = [--] cm). It has four identical conical depressions (radius r = [---] cm depth h = [---] cm) and one cubical depression (edge a = [--] cm) for holding pens and pins. Find the volume of the wood used in the"
YouTube Link 2025-12-05T05:45Z [---] followers, [--] engagements
"🤯 [--] Minute Water Level Rise Challenge (Cylinder Flow) #trigonometricalidentities #surfacearea #edu [--]. Catchy Hook: Can you solve this classic Surface Area and Volume flow rate problem in under [--] minutes Let's check your speed and accuracy [--]. The Question Text: Water flows through a cylindrical pipe whose inner radius is [--] cm at the rate of [--] cm/sec into an empty cylindrical tank the radius of whose base is [--] cm. What is the rise of water level (H) in the tank in half an hour [--]. Brief Concept Explanation: The key to solving flow rate problems is equating the volume flowing out of the pipe"
YouTube Link 2025-12-07T05:03Z [---] followers, [---] engagements
"CSA of Cone = CSA of Hemisphere Find the Height (h) in terms of Radius (r) Class [--] Mensuration 🔥 Don't let solid geometry formulas confuse you This is a classic CBSE/ICSE board exam question dealing with the relationship between a cone and a hemisphere. Question: A solid consists of a hemisphere at the bottom and a cone above it both having the same base radius r. If the curved surface areas (CSA) of the hemisphere and cone are equal then find the height (h) of the conical part. Concept Explained: We set the fundamental formulas for Curved Surface Area (CSA) of a hemisphere (2r) and a cone"
YouTube Link 2026-01-07T04:33Z [---] followers, [--] engagements
"Surface Area TRICK: When Cylinder Height is Halved Combined Solids Geometry Problem (Class 10/12) Don't let combined solids confuse you This is a classic surface area problem often seen in board exams testing your understanding of Curved Surface Area (CSA). THE QUESTION: A solid is made by placing a hemisphere on top of a cylinder. Full question text from content. CONCEPT EXPLAINED: We calculate the Total Surface Area (TSA) by summing the Curved Surface Areas (CSA) of the cylinder and the hemisphere plus the base area of the cylinder. Crucially the circular area where the two solids join is"
YouTube Link 2026-01-06T05:40Z [---] followers, [--] engagements
"Surface Area of Composite Solids Cone and Hemisphere TSA TRICK Assertion Reason Class [--] Maths Stop losing marks on tricky composite solid questions 🛑 Today we solve a fundamental Assertion-Reason problem related to the Total Surface Area (TSA) of a cone mounted on a hemisphere. Question: Assertion (A): TSA = CSA (Hemisphere) + CSA (Cone). Reason (R): The flat faces are joined internally and not exposed. Concept Explained: When two solids are joined the surface area exposed is only the sum of their external curved areas. The joined planar faces are hidden internally making this a common trap"
YouTube Link 2026-01-09T14:34Z [---] followers, [--] engagements
"Cylinder & Cone Volume Ratio TRICK If Volume_cyl = Volume_cone What is h1:h2 Class [--] Maths Ready for a quick geometry challenge This question tests your fundamental understanding of 3D shapes and volumes (Cylinder and Cone). The Question: A cap is cylindrical in shape surmounted by a conical top. If the volume of the cylindrical part is equal to that of the conical part then find the ratio of the height of the cylindrical part to the height of the conical part. Concept: The key lies in understanding the volume formulas V_cyl = rh and V_cone = (1/3)rh. Setting them equal allows us to find the"
YouTube Link 2026-01-16T05:10Z [---] followers, [--] engagements
"Geometry FAIL Assertion-Reason on Sphere & Cylinder Solved (A is True R is False)Class [--] Maths [--]. Stop the confusion This tricky Assertion-Reason question tests if you know the exact formulas and constraints in 3D geometry. Watch how we analyze the 'just encloses' condition and identify the critical error in the Reason. [--]. Question: Assertion (A): A circular cylinder of radius r and height h (h Greater than 2r) just encloses a sphere then the diameter of the sphere is 2r. Reason (R): The surface area of the sphere is 2r(h + r). [--]. We confirm the sphere's maximum diameter is 2r based on the"
YouTube Link 2026-01-04T05:10Z [---] followers, [---] engagements
"Area of Shaded Region between Two Squares Geometry Class 9/10 CBSE Solved Problem 💡 Can you solve this geometry puzzle We're finding the shaded area quickly and accurately using simple area subtraction Question: Find the area of the shaded region. The figure consists of a large square (side [--] cm) containing a smaller concentric unshaded square. The margin is [--] cm uniformly. Concept: This problem utilizes the fundamental principle of area subtraction: Area_Shaded = Area_Outer - Area_Inner. Its essential for Class [--] and [--] geometry topics. Ready to ace your Maths exams Join Abhi Garg"
YouTube Link 2026-01-26T08:02Z [---] followers, [--] engagements
"Cloud & Its Image Problem Angles [--] & [--] Height of Cloud = [---] m #Trigonometry QUESTION: A cloud is observed from a point [---] m above a lake. Angle of elevation = [--] angle of depression of its image = [--]. Find the height of the cloud. SOLUTION: Let cloud height above lake = H. Image lies H below lake observer to image = H + [---]. Horizontal distance = x. tan30 = (H100)/x = 1/3 tan60 = (H+100)/x = [--] Divide equations (H+100)/(H100) = [--] Solve H = [---] m. Final Answer: Height of cloud = 200 m. #Trigonometry #HeightAndDistance #Class10Maths #NCERT #MathsWithAbhi #CloudProblem #MathsShorts"
YouTube Link 2025-11-14T06:17Z [---] followers, [---] engagements
"Ladder slides from [--] to [--] Find foot distance (Answer: [--] m) #Trigonometry Problem: A ladder reaches [--] m on a wall at [--]. After pulling its foot out it makes [--] with the ground. Find the distance of the foot from the wall. Solution summary: Let ladder length = L. From sin60 = 5/L L = 10/3. At [--] horizontal distance = Lcos30 = (10/3)(3/2) = [--] m. Final answer: [--] m. #Trigonometry #HeightAndDistance #LadderProblem #Class10Maths #MathsShorts #AbhiGargClasses"
YouTube Link 2025-11-16T05:47Z [---] followers, [---] engagements
"Surface Area TRICK: When Cylinder Height is Halved Combined Solids Geometry Problem (Class 10/12) Don't let combined solids confuse you This is a classic surface area problem often seen in board exams testing your understanding of Curved Surface Area (CSA). THE QUESTION: A solid is made by placing a hemisphere on top of a cylinder. Full question text from content. CONCEPT EXPLAINED: We calculate the Total Surface Area (TSA) by summing the Curved Surface Areas (CSA) of the cylinder and the hemisphere plus the base area of the cylinder. Crucially the circular area where the two solids join is"
YouTube Link 2026-01-06T05:36Z [---] followers, [--] engagements
"Juice Seller Problem Apparent vs. Actual Capacity Volume of Cylinder & Hemisphere (Class 10) Don't fall for the juice seller's trick Learn the crucial difference between apparent and actual capacity in this detailed volume calculation. ❓ The Question: A cylindrical glass has an inner diameter of [--] cm and a height of [--] cm. The bottom has a raised hemispherical portion which reduces the capacity. Find the apparent capacity and the actual capacity. ( = 3.14). 💡 Concept Explained: This problem combines the volume formulas for a cylinder (V = rh) and a hemisphere (V = (2/3)r). Actual capacity is"
YouTube Link 2025-12-13T06:01Z [---] followers, [---] engagements
"SURFACE AREA of Cuboid Formed by Joining Two Cubes Mensuration Class [--] CBSE (Solved in [--] Steps) 🚀 INSTANT MATH LESSON Are you struggling with Mensuration Watch how we solve this classic problem involving joining two cubes and finding the new surface area Question: Two cubes each of volume [--] cm are joined end to end. Find the surface area of the resulting cuboid. Concept: When two identical cubes (side 'a') are joined only the length changes (becomes 2a) while the breadth and height remain 'a'. The resulting shape is a cuboid. We then apply the cuboid surface area formula: TSA = 2(LB + BH +"
YouTube Link 2025-12-30T04:28Z [---] followers, [--] engagements
"Sphere vs. [--] Hemispheres: Surface Area Ratio TRICK (4r vs 6r Explained) Class [--] Math 🚨 Stop guessing the surface area ratio When a solid sphere is cut into two hemispheres the total surface area changes drastically. This is a crucial concept for CBSE Class [--] and [--] board exams. ❓ The Question: A solid sphere is cut exactly into two hemispheres. What is the ratio of the surface area of the original sphere to the total combined surface area of the two resulting hemispheres 💡 Concept Insight: Remember that the total surface area of a hemisphere includes the curved area (2r) plus the new flat"
YouTube Link 2026-01-13T04:30Z [---] followers, [---] engagements
"Aeroplane Depression Angles [--] & [--] Height of Plane = [---] m #Trigonometry QUESTION: From an aeroplane angles of depression to two consecutive kilometre stones (1 km apart) are [--] and [--]. Find the height of the aeroplane. SOLUTION: Let height = h. tan60 = h / AS AS = h/3 tan30 = h / AS AS = 3h AS AS = [----] 3h h/3 = [----] 2h/3 = [----] h = [----] = [---] m (approx) Final answer: Height = 865 m #Trigonometry #HeightAndDistance #Class10Maths #NCERT #MathsShorts #AbhiGargClasses"
YouTube Link 2025-11-15T05:43Z [---] followers, [--] engagements
"Cylinder + Hemisphere Volume Problem Building Height = [--] m #Mensuration SEO keywords: cylinder hemisphere volume building height problem Question: A building is a cylinder surmounted by a hemispherical dome and contains [--] 19/21 m of air. If the internal diameter of the dome equals the total height above the floor find the height of the building. Solution summary: Let dome radius = r and cylinder height = r (from diameter = total height). Total volume = (5/3)r = 880/21. Using = 22/7 gives r = [--] m. Total height = 2r = [--] m. Final Answer: [--] m. #Mensuration #VolumeProblems #Class10Maths"
YouTube Link 2025-11-24T05:04Z [---] followers, [--] engagements
"Cylinder & Cone Volume Ratio TRICK If Volume_cyl = Volume_cone What is h1:h2 Class [--] Maths Ready for a quick geometry challenge This question tests your fundamental understanding of 3D shapes and volumes (Cylinder and Cone). The Question: A cap is cylindrical in shape surmounted by a conical top. If the volume of the cylindrical part is equal to that of the conical part then find the ratio of the height of the cylindrical part to the height of the conical part. Concept: The key lies in understanding the volume formulas V_cyl = rh and V_cone = (1/3)rh. Setting them equal allows us to find the"
YouTube Link 2026-01-16T05:09Z [---] followers, [--] engagements
"💊 Surface Area of a Medicine Capsule Combined Solids Class [--] Maths NCERT Ex [----] Q3 Solution Stop scrolling Can you calculate how much material is needed to coat this standard medicine capsule Question: A medicine capsule is in the shape of a cylinder with two hemispheres stuck to each of its ends. The length of the entire capsule is [--] mm and the diameter of the capsule is [--] mm. Find its surface area. This problem involves finding the total surface area of a composite figure: a cylinder capped by two hemispheres. Remember you only calculate the curved surface area (CSA) of the individual"
YouTube Link 2025-12-28T04:53Z [---] followers, [--] engagements
"Flow Rate vs Volume of Cone Maths Mensuration Problem Solving (Class 10) 🚨 How long does it take for a pipe to fill a conical vessel It's a classic 3D geometry question Question: Water flows at the rate of [--] m/minute through a cylindrical pipe [--] mm in diameter. How long would it take to fill a conical vessel whose diameter at the base is [--] cm and depth is [--] cm This video breaks down the concept of relating the volume flow rate (area velocity) of a cylinder to the total volume of a cone. Ensure all units are consistent (cm or m) before calculating. 📍 Find the best coaching in Sector 20"
YouTube Link 2025-12-11T04:49Z [---] followers, [--] engagements
"FIND THE HEIGHT Volume of Cylinder and Hemispherical Dome Problem Class [--] Mensuration CBSE 🔥 Geometry Alert Don't miss this classic volume problem crucial for your board exams Question: A building is in the form of a cylinder surmounted by a hemispherical dome. The base diameter (D) of the dome is equal to 2/3 of the total height (H) of the building. Find the height of the building if it contains [--] 1/21 m of air. Concept Explained: We simplify the complex relationship by expressing both the cylinder's height (h) and the radius (R) in terms of the Total Height (H). This reduces the entire"
YouTube Link 2025-12-14T05:03Z [---] followers, [--] engagements
"SILO CASE STUDY 😱 Class [--] Maths Surface Area & Volume Guaranteed Question Slant Height & Cap Welcome to ABHI GARG CLASSES 🏆 Today we tackle a high-probability Case Study question on Surface Area and Volume crucial for your Class [--] CBSE Board Exams. This problem involves calculating the dimensions curved surface area and total capacity of a composite solida silo shaped like a cylinder surmounted by a cone. The Full Question: Farmer Girdhar is building a metallic silo (cylinder mounted by a cone). Conical Part: Radius (r) = [---] m Height ($h_c$) = [--] m. Cylindrical Part: Radius (r) = 1.5"
YouTube Link 2025-11-30T06:04Z [---] followers, [---] engagements
"GULAB JAMUN MATH TRICK: How to Find Syrup Volume in Combined Solids Mensuration Class [--] CBSE Welcome to Abhi Garg Classes Today we are tackling a delicious yet complex mensuration problem: calculating the volume of syrup in [--] gulab jamuns. Question: A gulab jamun contains sugar syrup up to about 30% of its volume. Find approximately how much syrup would be found in [--] gulab jamuns each shaped like a cylinder with two hemispherical ends with length [--] cm and diameter [---] cm. This video demonstrates the critical concept of finding the volume of combined solids (Cylinder + Hemispheres) and"
YouTube Link 2025-12-23T05:00Z [---] followers, [---] engagements
"Prove V = (131 / 96) R Volume of Combined Solids Sphere & Cylinder Math Proof (Class 10) Stop struggling with complicated Mensuration proofs This question beautifully combines the volumes of a sphere and a cylinder requiring careful algebraic substitution. We break down the steps to prove that the total volume is (131 / 96) R. Question: A spherical glass vessel has a cylindrical neck whose radius (r) is R/8 and height (h) is 2R. Prove V = (131 / 96) R. This concept is crucial for scoring high marks in surface area and volume chapters. Mastering substitution and fractions is key 📍 Find expert"
YouTube Link 2026-01-11T05:10Z [---] followers, [--] engagements
"THE HARDEST Mensuration Question 🤯 Calculating Surface Area of Hollowed Cone & Cylinder [--] [--] Board Welcome to ABHI GARG CLASSES Today we are tackling a complex but crucial problem from the Surface Area and Volume chapter (Mensuration) for Class [--] Mathematics. This type of question frequently appears in CBSE and ICSE Board Examinations testing your visualization skills. 🎯 The Question: From a solid right circular cone whose height is [--] cm and radius of base is [--] cm a right circular cylindrical cavity of height [--] cm and radius [--] cm is hollowed out such that bases of cone and cylinder form"
YouTube Link 2025-12-01T05:49Z [---] followers, [--] engagements
"Hour Hand Problem SOLVED Area Swept by Clock Hand in [--] Minutes Class [--] Maths 🔥 Catchy Hook: Stop guessing the angle Learn the precise formula for clock problems and master the application of the Area of a Sector formula (A = (/360) R). Question: The hour hand of a clock is [--] cm long. The area swept by it between 11:20 am and 11:55 am is calculated step-by-step. Concept: We utilize the fundamental angular speed of the hour hand (0.5 per minute) to find the angle () and then apply the sector area formula. This is an essential concept for Class [--] Board exams 📌 Location: Abhi Garg Classes"
YouTube Link 2026-01-20T01:48Z [---] followers, [--] engagements
"TSA of Composite Solids: Cube and Hemisphere Class [--] Surface Area and Volume (Mensuration NCERT) Welcome to the world of 3D geometry Many students get confused when two solids are joined. We tackle a standard board exam question involving a cube topped with a hemisphere. Q: The decorative block is made of a cube (edge [--] cm) and a hemisphere (diameter [---] cm) on top. Find the total surface area of the block. Concept Explanation: When calculating the TSA of a composite solid where a smaller shape rests on a larger base we use the formula: TSA = (TSA of base solid) - (Area of common base) +"
YouTube Link 2025-12-25T05:14Z [---] followers, [---] engagements
"Juice Seller Problem Apparent vs. Actual Capacity Volume of Cylinder & Hemisphere (Class 10) Don't fall for the juice seller's trick Learn the crucial difference between apparent and actual capacity in this detailed volume calculation. ❓ The Question: A cylindrical glass has an inner diameter of [--] cm and a height of [--] cm. The bottom has a raised hemispherical portion which reduces the capacity. Find the apparent capacity and the actual capacity. ( = 3.14). 💡 Concept Explained: This problem combines the volume formulas for a cylinder (V = rh) and a hemisphere (V = (2/3)r). Actual capacity is"
YouTube Link 2025-12-13T06:00Z [---] followers, [--] engagements
"The ICE-CREAM CONE PROBLEM that EVERY Class [--] Student Finds Tricky Volume of Composite Solids Welcome back to ABHI GARG CLASSES Master the challenging chapter on Surface Areas and Volumes with this expert breakdown of a complex problem often seen in Class [--] Mathematics (CBSE/ICSE syllabus). In this video we meticulously calculate the total volume of ice-cream when it is filled in a cone and overflows into a hemispherical shape while also handling the tricky condition about the internal unfilled volume. THE QUESTION: An empty cone of radius [--] cm and height [--] cm is filled with"
YouTube Link 2025-11-28T05:20Z [---] followers, [---] engagements
"Volume to Area Ratio of Cubes The 3-2-1 Rule Shortcut Class [--] Mensuration Unlock the secret relationship between Volume and Surface Area in 3D shapes Question: If the volumes of two cubes are in the ratio 8:125 then the ratio of their surface areas is: Concept Explained: When dealing with similar 3D shapes the ratio of volumes (s) is the cube of the ratio of sides (s) and the ratio of surface areas (s) is the square of the ratio of sides. We quickly use this principle to derive the solution 4:25. Join Abhi Garg Classes for focused learning and guaranteed results We are located in Sector 20"
YouTube Link 2026-01-12T04:17Z [---] followers, [--] engagements
"Flow Rate vs Volume of Cone Maths Mensuration Problem Solving (Class 10) 🚨 How long does it take for a pipe to fill a conical vessel It's a classic 3D geometry question Question: Water flows at the rate of [--] m/minute through a cylindrical pipe [--] mm in diameter. How long would it take to fill a conical vessel whose diameter at the base is [--] cm and depth is [--] cm This video breaks down the concept of relating the volume flow rate (area velocity) of a cylinder to the total volume of a cone. Ensure all units are consistent (cm or m) before calculating. 📍 Find the best coaching in Sector 20"
YouTube Link 2025-12-11T04:56Z [---] followers, [---] engagements
"Cone Volume vs Sphere Volume Trick Find Cone Height Instantly CBSE Class [--] Maths SA & V 🔥 Don't let Volume questions confuse you We are solving a tricky problem where a right circular cone and a sphere share the same radius and the same volume. This conceptual shortcut will save you massive time in exams The Question: If the radius of the base of a right circular cone and the radius of a sphere are each [--] cm in length and their volumes are equal then the height of the cone is: Concept: The key lies in equating V_cone = V_sphere and observing that h = 4r when radii are equal. This"
YouTube Link 2026-01-17T05:08Z [---] followers, [--] engagements
"Industrial Shed Volume Calculation Cuboid & Half Cylinder Volume Class [--] Maths Application 🎯 Can you solve this real-world volume problem We calculate the total air capacity of an industrial shed shaped like a cuboid surmounted by a half cylinder and then subtract the space occupied by machinery and workers. QUESTION: Shanta runs an industry in a shed which is in the shape of a cuboid surmounted by a half cylinder. If the base of the shed is of dimension [--] m x [--] m and the height of the cuboidal portion is [--] m find the volume of air that the shed can hold. Further suppose the machinery in"
YouTube Link 2025-12-15T05:36Z [---] followers, [--] engagements
"VOLUME TRICK 🤯 How Many Lead Shots Cone & Sphere Problem (Surface Area and Volume Class 10) 🛑 Stop scrolling Can tiny spheres displace huge volumes Let's solve this viral problem Question: A vessel is in the form of an inverted cone. Its height (H) is [--] cm and the radius of its top (R) is [--] cm. It is filled with water up to the brim. When spherical lead shots of radius (r) [---] cm are dropped into the vessel one-fourth (1/4) of the water flows out. Find the number of lead shots dropped in the vessel. Concept Explanation: This problem tests the fundamental concept of volume displacement"
YouTube Link 2025-12-17T05:49Z [---] followers, [---] engagements
"Area of Sector Problem: Find the Central Angle if Sector Area is 7/20 of the Circle Class [--] 🎯 Quick Maths Hack Are you stuck on sector area problems Question: If the area of a sector of a circle is (7 / 20) of the area of the circle then the angle () at the centre is equal to: CONCEPT: The ratio of the sector area to the total circle area is exactly equal to the ratio of the central angle () to [---]. This allows us to easily isolate and solve for the unknown angle. Learn proven strategies for Classes 8th to 12th Maths and Science. 📍 Visit Abhi Garg Classes in Sector [--] Chandigarh for"
YouTube Link 2026-01-25T05:36Z [---] followers, [--] engagements
"Ink Capacity Challenge: How Many Words Can A Bottle Write Volume of Cylinder (rh) Class [--] 🚨 Viral Math Problem Alert Can you solve this real-world application of geometry and capacity Question: A cylindrical fountain pen barrel is [--] cm long and has a [--] mm diameter. A full barrel of ink is used up when writing [----] words on average. How many words can be written using a bottle of ink containing 1/5 of a litre Concept Explained: We use the formula for the Volume of a Cylinder (V = rh) and the concept of converting units (mm to cm litres to cm). This helps us apply the unitary method to find"
YouTube Link 2025-12-10T04:59Z [---] followers, [---] engagements
"DOUBLE CONE Surface Area TRICK (r=8 h=15) Class [--] Maths CBSE Surface Area and Volume Question 🔥 Welcome to ABHI GARG CLASSES In this essential Class [--] Mathematics tutorial we tackle a critical problem from the Surface Area and Volume chapter involving composite solids. This is a common high-scoring question in CBSE/ICSE board exams. 📚 Question Covered: Two cones with the same base radius (r = [--] cm) and height (h = [--] cm) are joined together along their bases. Find the total surface area of the shape so formed. Key Concepts You Will Learn: [--]. Identifying the correct formula for the TSA of"
YouTube Link 2025-11-29T05:41Z [---] followers, [---] engagements
"Surface Area of Composite Solids Cone and Hemisphere TSA TRICK Assertion Reason Class [--] Maths Stop losing marks on tricky composite solid questions 🛑 Today we solve a fundamental Assertion-Reason problem related to the Total Surface Area (TSA) of a cone mounted on a hemisphere. Question: Assertion (A): TSA = CSA (Hemisphere) + CSA (Cone). Reason (R): The flat faces are joined internally and not exposed. Concept Explained: When two solids are joined the surface area exposed is only the sum of their external curved areas. The joined planar faces are hidden internally making this a common trap"
YouTube Link 2026-01-09T14:36Z [---] followers, [--] engagements
"SILO CASE STUDY 😱 Class [--] Maths Surface Area & Volume Guaranteed Question Slant Height & Cap Welcome to ABHI GARG CLASSES 🏆 Today we tackle a high-probability Case Study question on Surface Area and Volume crucial for your Class [--] CBSE Board Exams. This problem involves calculating the dimensions curved surface area and total capacity of a composite solida silo shaped like a cylinder surmounted by a cone. The Full Question: Farmer Girdhar is building a metallic silo (cylinder mounted by a cone). Conical Part: Radius (r) = [---] m Height ($h_c$) = [--] m. Cylindrical Part: Radius (r) = 1.5"
YouTube Link 2025-11-30T06:03Z [---] followers, [--] engagements
"Clock Problem Mastery: How to Find Area Swept by Minute Hand (Class [--] Maths Circles) STOP wasting time and START calculating This geometry application involving clock hands is a critical and recurring board exam favorite from the chapter Area Related to Circles. QUESTION: The length of the minute hand of a clock is [--] cm. Find the area swept by the minute hand during the time period 6:05 am and 6:40 am. CONCEPT: We treat the clock hand as the radius (R) and the path it traces as a Sector. The fundamental concept is knowing the speed: the minute hand moves [--] per minute. We use the time elapsed"
YouTube Link 2026-01-24T05:40Z [---] followers, [--] engagements
"Cylinder and Cone Combined Total Area to be Painted Vertical Angle [--] Trick Class [--] Maths 🔥 Mensuration Mastery: Surface Area of Combined Solids Question: A building is in the form of a right circular cylinder of diameter [--] m and height [--] m surmounted by a right circular cone whose vertical angle is [--]. Find the total area to be painted. (Take = 3.14) This video breaks down a tricky Class [--] surface area problem. The crucial step is understanding how the [--] vertical angle helps you determine the cone's height and slant height (l). We calculate the Curved Surface Area of the cylinder and"
YouTube Link 2026-01-10T04:58Z [---] followers, [--] engagements
"TSA of Remaining Solid: Cone Cut from Cylinder Crucial Class [--] Mensuration Question (48 cm) Don't lose marks on complex surface area problems This standard Mensuration question involves calculating the Total Surface Area (TSA) of a composite solid after hollowing. Question: A right circular cone of height [--] cm and diameter [--] cm is hollowed out from the top of a solid right cylinder having the same height and diameter. Find the total surface area of the remaining solid. Concept: Remember when a solid is hollowed the top area of the cylinder is REMOVED and the newly created inner surface (CSA"
YouTube Link 2026-01-08T04:56Z [---] followers, [---] engagements
"Rocket Maths Solved 🚀 Find Surface Area & Volume of Cylinder and Cone Composite Solids (Class 10) Welcome to ABHI GARG CLASSES In this detailed session for Class [--] Mathematics students we tackle a crucial problem from the chapter on Surface Area and Volume of Composite Solids. This question is frequently asked in CBSE and ICSE board exams. The Question: A rocket is in the form of a right circular cylinder closed at the lower end and surmounted by a cone with the same radius as that of the cylinder. The diameter and height of the cylinder are [--] cm and [--] cm respectively. If the slant"
YouTube Link 2025-12-03T06:20Z [---] followers, [--] engagements
"Viral Maths Hack: How Many 539ml Cans Fit in a Cube Class [--] Surface Area & Volume Question 🔥 Geometry Alert This seemingly complex packing problem from Surface Area and Volume (Class 10) is a quick solve if you know the LCM trick. Question: A cylindrical can is placed in a cubical container. i) How many cans fit ii) If the capacity is [---] ml find the cube volume. . Conceptual Clarity is Key. Learn advanced techniques with Abhi Garg Classes. 📍 Location: Sector [--] Chandigarh. 👍 Subscribe for daily Maths and Science concepts #maths #class10 #surfaceareaandvolume #volume #abhigargclasses #cbse"
YouTube Link 2025-12-22T05:05Z [---] followers, [--] engagements
"Cube Surmounted by a Hemisphere CLASS [--] Surface Area Solution Mensuration Masterclass 🚨 CUBE + HEMISPHERE TRICK REVEALED 🚨 Question: A cubical block of side [--] cm is surmounted by a hemisphere. What is the greatest diameter the hemisphere can have Find the surface area of the solid. This video breaks down a crucial Surface Area and Volume concept from Class [--] Mathematics. We derive the simple effective formula: SA = 6s + r. We find the final answer is [-----] cm. 📍 Visit Abhi Garg Classes in Sector [--] Chandigarh for comprehensive Maths and Science coaching. 👍 Subscribe for daily Maths tips"
YouTube Link 2025-12-29T04:38Z [---] followers, [--] engagements
"Cuboid to Cylinder Volume Transfer Problem Find the Height Mensuration Class [--] Maths 🔥 Master Volume Conservation instantly 🔥 Question: A rectangular water tank of base [--] m [--] m contains water upto a height of [--] m. If the water in the tank is transferred to a cylindrical tank of radius [---] m find the height of the water level in the tank. Concept Explained: This problem requires equating the volume of the cuboid (V = LBH) to the volume of the cylinder (V = rh). The key principle is that the volume of the substance being transferred is conserved. Perfect for Class [--] CBSE preparation. 📍"
YouTube Link 2025-12-08T06:01Z [---] followers, [--] engagements
"Cone Inside a Cube: Find the Volume when Cube Volume is [---] Class [--] Mensuration Solid Shapes Are you ready for a quick challenging geometry problem This question tests your visualization skills by connecting the volume of a cube directly to the dimensions of an inscribed cone. The Question: A cone is inscribed in a cube whose volume is [---] cu. units. The cone has its base on one face of the cube and its vertex at the centre of the opposite face. find the volume of the cone. Concept: The key insight is that the cube's side length (a) defines both the cone's height (h) and the cone's diameter"
YouTube Link 2026-01-05T06:27Z [---] followers, [--] engagements
"Revolutions of Wheels Problem Diameter [--] cm vs [--] m Area Related to Circles Class [--] Maths 🎯 Unlock the secrets of circular motion This classic problem helps you master the relationship between circumference distance and revolutions. Question: The diameters of front and rear wheels of a tractor are [--] cm and [--] m respectively. Find the number of revolutions that the rear wheel will make in covering a distance in which the front wheel makes [----] revolutions. Concept: The key is recognizing that the total distance covered must be the same for both wheels. Distance = Circumference Number of"
YouTube Link 2026-01-23T06:00Z [---] followers, [--] engagements
"Spherical shell (D_ext=8 D_int=4) recast as cone (D=8) Find cone height. #Mensuration SEO: spherical shell cone problem mensuration class [--] Question: A metallic spherical shell with external diameter [--] cm and internal diameter [--] cm is melted and recast into a cone whose base diameter is [--] cm. Find the height of the cone. Short video plan: Restate the problem and show volumes: V_shell = (4/3)(R3 r3) where R=4 cm and r=2 cm. Equate shell volume to cone volume (1/3)(4)h and solve. Calculation gives h = [--] cm Option (b). Quick tip: always equate volumes when recasting solids. Final Answer: **14"
YouTube Link 2025-11-27T05:15Z [---] followers, [---] engagements
"Open Box Volume & Weight Problem Solved Critical Class 10/12 Mensuration Question 🎯 STOP losing marks on Mensuration The 'Open Box' problem has one subtle trick you MUST know regarding internal height. We solve this complete volume and weight question step-by-step. ❓ Question: How many cubic centimetres of iron is required to construct an open box whose external dimensions are [--] cm [--] cm and [----] cm provided the thickness of the iron is [---] cm. If one cubic cm of iron weighs [---] g find the weight of the box. 💡 Concept Focus: When calculating the internal dimensions of an open box with"
YouTube Link 2025-12-09T08:32Z [---] followers, [--] engagements
"THE HARDEST Mensuration Question 🤯 Calculating Surface Area of Hollowed Cone & Cylinder [--] [--] Board Welcome to ABHI GARG CLASSES Today we are tackling a complex but crucial problem from the Surface Area and Volume chapter (Mensuration) for Class [--] Mathematics. This type of question frequently appears in CBSE and ICSE Board Examinations testing your visualization skills. 🎯 The Question: From a solid right circular cone whose height is [--] cm and radius of base is [--] cm a right circular cylindrical cavity of height [--] cm and radius [--] cm is hollowed out such that bases of cone and cylinder form"
YouTube Link 2025-12-01T05:50Z [---] followers, [---] engagements
"Water Displacement Problem Pond Water Level Rises by [---] cm #Mensuration SEO keywords: water displacement cuboidal pond volume problems class [--] maths mensuration Question: [---] persons take a dip into a cuboidal pond (80 m [--] m). Each displaces [----] m water. Find the rise in water level. Solution: Total water displaced = [---] [----] = [--] m Area of base = [--] [--] = [----] m Rise in level = [--] / [----] = [-----] m = [---] cm Final Answer: [---] cm #Mensuration #Volume #NCERT #Class10Maths #AbhiGargClasses #RiseInWaterLevel"
YouTube Link 2025-11-25T04:50Z [---] followers, [--] engagements
"500 people jump into a pond 🌊 How much does the water level rise #Mensuration #Volume SEO keywords: water displacement cuboidal pond volume problems class [--] maths mensuration Question: [---] persons take a dip into a cuboidal pond (80 m [--] m). Each displaces [----] m water. Find the rise in water level. Solution: Total water displaced = [---] [----] = [--] m Area of base = [--] [--] = [----] m Rise in level = [--] / [----] = [-----] m = [---] cm Final Answer: [---] cm #Mensuration #Volume #NCERT #Class10Maths #AbhiGargClasses #RiseInWaterLevel"
YouTube Link 2025-11-25T04:54Z [---] followers, [---] engagements
"TSA of Remaining Solid: Cone Cut from Cylinder Crucial Class [--] Mensuration Question (48 cm) Don't lose marks on complex surface area problems This standard Mensuration question involves calculating the Total Surface Area (TSA) of a composite solid after hollowing. Question: A right circular cone of height [--] cm and diameter [--] cm is hollowed out from the top of a solid right cylinder having the same height and diameter. Find the total surface area of the remaining solid. Concept: Remember when a solid is hollowed the top area of the cylinder is REMOVED and the newly created inner surface (CSA"
YouTube Link 2026-01-08T04:52Z [---] followers, [--] engagements
"Hemisphere TSA Ratio Secret Surface Area & Volume Class [--] Maths Quick Trick Are you often confused about the difference between Curved Surface Area and Total Surface Area of a hemisphere This quick problem will cement the concept for you ❓ QUESTION: The ratio of total surface area of a solid hemisphere to the square of its radius is: CONCEPT EXPLAINED: The total surface area of a SOLID hemisphere is 3r because it includes both the curved part and the flat circular base. Setting up the ratio (3r / r) simplifies beautifully to [--] : [--]. Master Mathematics and Science from Class 8th to 12th. Join"
YouTube Link 2026-01-15T04:45Z [---] followers, [--] engagements
"Spherical shell (D_ext=8 D_int=4) recast as cone (D=8) Find cone height. #Mensuration SEO: spherical shell cone problem mensuration class [--] Question: A metallic spherical shell with external diameter [--] cm and internal diameter [--] cm is melted and recast into a cone whose base diameter is [--] cm. Find the height of the cone. Short video plan: Restate the problem and show volumes: V_shell = (4/3)(R3 r3) where R=4 cm and r=2 cm. Equate shell volume to cone volume (1/3)(4)h and solve. Calculation gives h = [--] cm Option (b). Quick tip: always equate volumes when recasting solids. Final Answer: **14"
YouTube Link 2025-11-27T05:14Z [---] followers, [--] engagements
"GULAB JAMUN MATH TRICK: How to Find Syrup Volume in Combined Solids Mensuration Class [--] CBSE Welcome to Abhi Garg Classes Today we are tackling a delicious yet complex mensuration problem: calculating the volume of syrup in [--] gulab jamuns. Question: A gulab jamun contains sugar syrup up to about 30% of its volume. Find approximately how much syrup would be found in [--] gulab jamuns each shaped like a cylinder with two hemispherical ends with length [--] cm and diameter [---] cm. This video demonstrates the critical concept of finding the volume of combined solids (Cylinder + Hemispheres) and"
YouTube Link 2025-12-23T04:58Z [---] followers, [--] engagements
"Geometry FAIL Assertion-Reason on Sphere & Cylinder Solved (A is True R is False)Class [--] Maths [--]. Stop the confusion This tricky Assertion-Reason question tests if you know the exact formulas and constraints in 3D geometry. Watch how we analyze the 'just encloses' condition and identify the critical error in the Reason. [--]. Question: Assertion (A): A circular cylinder of radius r and height h (h Greater than 2r) just encloses a sphere then the diameter of the sphere is 2r. Reason (R): The surface area of the sphere is 2r(h + r). [--]. We confirm the sphere's maximum diameter is 2r based on the"
YouTube Link 2026-01-04T05:07Z [---] followers, [--] engagements
"🤯 How to calculate TSA of a toy (Cone + Hemisphere) FAST Don't lose marks on composite solids Learn the simplest method to find the Total Surface Area (TSA) of a toy combining a cone and a hemisphere. Question: A toy is in the form of a cone of radius [---] cm mounted on a hemisphere of the same radius. The total height of the toy is [----] cm. Find the total surface area of the toy. Concept Explained: Remember for the total surface area of a composite solid you only add the exposed Curvature Surface Areas (CSA). Finding the slant height (l) using the Pythagorean theorem (l = (r + h)) is the"
YouTube Link 2026-01-01T05:14Z [---] followers, [--] engagements
"🔥 Pipe Flow Rate Problem: Calculate the Rise in Water Level in [--] Min Class [--] Surface Area & Vol [--]. Catchy Hook: Can you solve this classic Surface Area and Volume flow rate problem in under [--] minutes Let's check your speed and accuracy [--]. The Question Text: Water flows through a cylindrical pipe whose inner radius is [--] cm at the rate of [--] cm/sec into an empty cylindrical tank the radius of whose base is [--] cm. What is the rise of water level (H) in the tank in half an hour [--]. Brief Concept Explanation: The key to solving flow rate problems is equating the volume flowing out of the pipe"
YouTube Link 2025-12-07T04:59Z [---] followers, [--] engagements
"Angle [--] [--] after [--] m Find tree height & river width (Answer: [-----] m [--] m) #Trigonometry Question: From the bank angle of elevation to a tree on opposite bank = [--]. After moving [--] m away angle becomes [--]. Find the tree's height and the river width. Solution summary: Let river width = d. From tan60 = h/d h = d3. From tan30 = h/(d+40) h = (d+40)/3. Solving gives d = [--] m and h = [---] [-----] m. Final: Height = [-----] m Width = [-----] m. #Trigonometry #HeightAndDistance #Class10Maths #NCERT #MathsWithAbhi #QuickSolution"
YouTube Link 2025-11-21T05:29Z [---] followers, [---] engagements
"Cloud & Reflection: Prove H = h(tan+tan)/(tantan) #Trigonometry Problem: From a point h metres above a lake the angle of elevation of a cloud is and the angle of depression of its reflection in the lake is . Prove that the clouds height above the lake is H = h (tan + tan ) / (tan tan ). Solution idea: Let horizontal distance to the point under the cloud be x. Use tan = (H h)/x and tan = (H + h)/x. Add and subtract the two equations to eliminate x and solve for H in terms of h tan and tan. Final formula: H = h(tan + tan)/(tan tan). #Trigonometry #HeightAndDistance #ReflectionProblem"
YouTube Link 2025-11-04T04:50Z [---] followers, [--] engagements
"Volume of Solid (Cone on Hemisphere) Class [--] Maths Board Exam Question Quick Geometry Solution Can you solve this Class [--] geometry problem in [--] seconds Its simpler than you think Question: A solid is in the shape of a cone standing on a hemisphere with both their radii being equal to [--] cm and the height of the cone is equal to its radius. Find the volume of the solid in terms of pi. Concept: Mastering the volume of composite solids involves breaking down the structure into standard shapes (like cones and hemispheres) and applying their respective formulas. The key here is realizing that"
YouTube Link 2025-12-26T05:00Z [---] followers, [----] engagements
"Cone Inside a Cube: Find the Volume when Cube Volume is [---] Class [--] Mensuration Solid Shapes Are you ready for a quick challenging geometry problem This question tests your visualization skills by connecting the volume of a cube directly to the dimensions of an inscribed cone. The Question: A cone is inscribed in a cube whose volume is [---] cu. units. The cone has its base on one face of the cube and its vertex at the centre of the opposite face. find the volume of the cone. Concept: The key insight is that the cube's side length (a) defines both the cone's height (h) and the cone's diameter"
YouTube Link 2026-01-05T06:26Z [---] followers, [--] engagements
"Quiz: How Many Multiples of [--] Between [--] & [---] Class [--] CBSE Q: How many multiples of [--] lie between [--] and [---] Watch the video guess before the timer ends and see if you're faster than 99% of students ✅ Solved using AP formula 📌 Perfect for CBSE [----] preparation. 🎥 Subscribe for daily shorts on tricky board concepts #MathsQuiz #CBSEMaths2025 #ArithmeticProgression #FindMultiples #Class10BoardPrep #MathsWithAbhiSir #FastMaths #ConceptReels"
YouTube Link 2025-07-19T05:36Z [---] followers, [---] engagements
"Volume to Area Ratio of Cubes The 3-2-1 Rule Shortcut Class [--] Mensuration Unlock the secret relationship between Volume and Surface Area in 3D shapes Question: If the volumes of two cubes are in the ratio 8:125 then the ratio of their surface areas is: Concept Explained: When dealing with similar 3D shapes the ratio of volumes (s) is the cube of the ratio of sides (s) and the ratio of surface areas (s) is the square of the ratio of sides. We quickly use this principle to derive the solution 4:25. Join Abhi Garg Classes for focused learning and guaranteed results We are located in Sector 20"
YouTube Link 2026-01-12T04:18Z [---] followers, [---] engagements
"TSA of Composite Solids: Cube and Hemisphere Class [--] Surface Area and Volume (Mensuration NCERT) Welcome to the world of 3D geometry Many students get confused when two solids are joined. We tackle a standard board exam question involving a cube topped with a hemisphere. Q: The decorative block is made of a cube (edge [--] cm) and a hemisphere (diameter [---] cm) on top. Find the total surface area of the block. Concept Explanation: When calculating the TSA of a composite solid where a smaller shape rests on a larger base we use the formula: TSA = (TSA of base solid) - (Area of common base) +"
YouTube Link 2025-12-25T05:13Z [---] followers, [--] engagements
"🔥 TRIGONOMETRY MASTERCLASS Proving (1/(sin+cos)) = sec/2 Identity Proofs Class 10/11 🎯 Catchy Hook: Can you prove this seemingly impossible trigonometric identity Its easier than you think if you know the right shortcut 📝 The Question: If [--] / (sin - cos) = cosec / [--] prove that (1 / (sin + cos)) = sec / [--]. 💡 Concept Explanation: This proof hinges on manipulating the fundamental identity (a+b) + (a-b) = 2(a + b) and strategically substituting the given condition. We convert the difference of sine and cosine squared into a multiple of cos leading directly to the secant function. 📍 Location:"
YouTube Link 2026-02-16T12:12Z [---] followers, [--] engagements
"🔥 TRIGONOMETRY MASTERCLASS Proving (1/(sin+cos)) = sec/2 Identity Proofs Class 10/11 🎯 Catchy Hook: Can you prove this seemingly impossible trigonometric identity Its easier than you think if you know the right shortcut 📝 The Question: If [--] / (sin - cos) = cosec / [--] prove that (1 / (sin + cos)) = sec / [--]. 💡 Concept Explanation: This proof hinges on manipulating the fundamental identity (a+b) + (a-b) = 2(a + b) and strategically substituting the given condition. We convert the difference of sine and cosine squared into a multiple of cos leading directly to the secant function. 📍 Location:"
YouTube Link 2026-02-16T12:12Z [---] followers, [--] engagements
"TRIGONOMETRY SHORT TRICK: If sin + cos = [--] Find sin cos in [--] Steps CBSE Class [--] [--]. Catchy Hook: Welcome back champions Today we're tackling a classic trigonometry identity problem that looks tough but melts away in just two steps [--]. The Question Text: If sin + cos = [--] find the value of sin cos. [--]. Brief Concept Explanation: This problem is designed to test your understanding of the squaring method combined with the core trigonometric identity sin + cos = [--]. A must-know concept for Class [--] and [--] board exams and competitive test preparation. [--]. Location: For personalized and high-quality"
YouTube Link 2026-02-16T07:58Z [---] followers, [---] engagements
"TRIGONOMETRY SHORT TRICK: If sin + cos = [--] Find sin cos in [--] Steps CBSE Class [--] [--]. Catchy Hook: Welcome back champions Today we're tackling a classic trigonometry identity problem that looks tough but melts away in just two steps [--]. The Question Text: If sin + cos = [--] find the value of sin cos. [--]. Brief Concept Explanation: This problem is designed to test your understanding of the squaring method combined with the core trigonometric identity sin + cos = [--]. A must-know concept for Class [--] and [--] board exams and competitive test preparation. [--]. Location: For personalized and high-quality"
YouTube Link 2026-02-16T07:58Z [---] followers, [--] engagements
"🤯 TRIGONOMETRY PROOF: If cos + sin = [--] Prove cos - sin = [--] Class [--] CBSE [----] Stop fearing Trigo proofs This identity problem is a frequently asked question (SQP 2024-25) and must be mastered for scoring full marks. 📝 The Question: If cos + sin = [--] then prove that cos - sin = [--]. 💡 Concept Explanation: We solve this by cleverly combining the fundamental trigonometric identity (sin + cos = 1) with an essential algebraic identity allowing us to find the required relationship in just a few lines. This is a crucial concept for Chapter [--]. 📍 For specialized coaching in Maths and Science"
YouTube Link 2026-02-16T07:54Z [---] followers, [----] engagements
"🤯 TRIGONOMETRY PROOF: If cos + sin = [--] Prove cos - sin = [--] Class [--] CBSE [----] Stop fearing Trigo proofs This identity problem is a frequently asked question (SQP 2024-25) and must be mastered for scoring full marks. 📝 The Question: If cos + sin = [--] then prove that cos - sin = [--]. 💡 Concept Explanation: We solve this by cleverly combining the fundamental trigonometric identity (sin + cos = 1) with an essential algebraic identity allowing us to find the required relationship in just a few lines. This is a crucial concept for Chapter [--]. 📍 For specialized coaching in Maths and Science"
YouTube Link 2026-02-16T07:53Z [---] followers, [--] engagements
"TRIGONOMETRY PROOF TRICK: Prove (cosec - sec) / (cosec + sec) = 3/4 Class [--] Maths 🔥 Don't let complex trigonometric proofs scare you This is one of the most frequently asked proof questions in CBSE Class [--] Boards. Question: Prove that (cosec - sec) / (cosec + sec) = 3/4 if tan = [--] / [--]. Concept: The key to solving this proof quickly is recognizing the relationship between cosec sec and tan. By dividing the numerator and denominator by cosec we reduce the entire expression to a simple function of tan making substitution straightforward and fast. 📍 Join Abhi Garg Classes for comprehensive"
YouTube Link 2026-02-16T07:50Z [---] followers, [----] engagements
"TRIGONOMETRY PROOF TRICK: Prove (cosec - sec) / (cosec + sec) = 3/4 Class [--] Maths 🔥 Don't let complex trigonometric proofs scare you This is one of the most frequently asked proof questions in CBSE Class [--] Boards. Question: Prove that (cosec - sec) / (cosec + sec) = 3/4 if tan = [--] / [--]. Concept: The key to solving this proof quickly is recognizing the relationship between cosec sec and tan. By dividing the numerator and denominator by cosec we reduce the entire expression to a simple function of tan making substitution straightforward and fast. 📍 Join Abhi Garg Classes for comprehensive"
YouTube Link 2026-02-16T07:50Z [---] followers, [---] engagements
"Trigonometry Trick: If sin = cos find the value of tan + cot - [--] Class [--] Maths Stop scrolling Can you solve this trigonometric identity challenge in [--] seconds Question: If is an acute angle and sin = cos find the value of tan + cot - [--]. This problem beautifully links the definition of tangent (sin/cos) with finding specific angle values (like 45). Understanding when sin and cos are equal is the key to simplifying the entire expression quickly. Learn this simple trick to score full marks Join Abhi Garg Classes for comprehensive Mathematics and Science coaching in Sector [--] Chandigarh. Don't"
YouTube Link 2026-02-16T07:43Z [---] followers, [---] engagements
"Trigonometry Trick: If sin = cos find the value of tan + cot - [--] Class [--] Maths Stop scrolling Can you solve this trigonometric identity challenge in [--] seconds Question: If is an acute angle and sin = cos find the value of tan + cot - [--]. This problem beautifully links the definition of tangent (sin/cos) with finding specific angle values (like 45). Understanding when sin and cos are equal is the key to simplifying the entire expression quickly. Learn this simple trick to score full marks Join Abhi Garg Classes for comprehensive Mathematics and Science coaching in Sector [--] Chandigarh. Don't"
YouTube Link 2026-02-16T07:42Z [---] followers, [--] engagements
"TRIGONOMETRY HACK: If sin x + cosec x = [--] find sinx + cosecx Solved in [--] Seconds Stop solving start observing This famous trigonometry problem can be solved in seconds if you spot the underlying algebraic trick. Question: Find the value of sinx + cosecx if sin x + cosec x = [--]. Concept: We show that when the sum of a term and its reciprocal equals [--] (x + 1/x = 2) that term (x) must be equal to [--]. This applies perfectly to trigonometric functions like sine and cosecant. Mastering advanced concepts starts here Enroll now at Abhi Garg Classes Sector [--] Chandigarh to transform your Math scores."
YouTube Link 2026-02-16T07:11Z [---] followers, [---] engagements
"TRIGONOMETRY HACK: If sin x + cosec x = [--] find sinx + cosecx Solved in [--] Seconds Stop solving start observing This famous trigonometry problem can be solved in seconds if you spot the underlying algebraic trick. Question: Find the value of sinx + cosecx if sin x + cosec x = [--]. Concept: We show that when the sum of a term and its reciprocal equals [--] (x + 1/x = 2) that term (x) must be equal to [--]. This applies perfectly to trigonometric functions like sine and cosecant. Mastering advanced concepts starts here Enroll now at Abhi Garg Classes Sector [--] Chandigarh to transform your Math scores."
YouTube Link 2026-02-16T07:09Z [---] followers, [--] engagements
"🔥 How to Find the Area of the Remaining Portion Square & Circle Cutouts Class [--] Geometry NCERT Stop losing marks on geometry questions involving combined shapes This solution simplifies everything. The Question: From each corner of a square of side [--] cm a quadrant of a circle of radius [--] cm is cut and also a circle of diameter [--] cm is cut from the center. Find the area of the remaining portion. Concept Explained: We use the simple principle: Area Remaining = Area of Square - Total Area Removed. Note that four quadrants always combine to form one full circle Join the best coaching"
YouTube Link 2026-02-16T05:43Z [---] followers, [---] engagements
"🔥 How to Find the Area of the Remaining Portion Square & Circle Cutouts Class [--] Geometry NCERT Stop losing marks on geometry questions involving combined shapes This solution simplifies everything. The Question: From each corner of a square of side [--] cm a quadrant of a circle of radius [--] cm is cut and also a circle of diameter [--] cm is cut from the center. Find the area of the remaining portion. Concept Explained: We use the simple principle: Area Remaining = Area of Square - Total Area Removed. Note that four quadrants always combine to form one full circle Join the best coaching"
YouTube Link 2026-02-16T05:43Z [---] followers, [--] engagements
"Viral Geometry Trick: Find Difference in Areas of Overlapping Sectors (R=6 R=8) Cancellation Meth 🔥 Geometry Hack Alert This seemingly complex problem involving overlapping sectors has a surprising simplification trick. Question: Find the difference in the areas of regions I and III given two overlapping sectors with radii [--] cm and [--] cm (assuming they are quadrants). Concept Explanation: We demonstrate the powerful cancellation technique. By setting up simultaneous equations for the areas we show that the common overlapping area (Region II) completely cancels out allowing us to find the"
YouTube Link 2026-02-16T05:09Z [---] followers, [---] engagements
"Viral Geometry Trick: Find Difference in Areas of Overlapping Sectors (R=6 R=8) Cancellation Meth 🔥 Geometry Hack Alert This seemingly complex problem involving overlapping sectors has a surprising simplification trick. Question: Find the difference in the areas of regions I and III given two overlapping sectors with radii [--] cm and [--] cm (assuming they are quadrants). Concept Explanation: We demonstrate the powerful cancellation technique. By setting up simultaneous equations for the areas we show that the common overlapping area (Region II) completely cancels out allowing us to find the"
YouTube Link 2026-02-16T05:08Z [---] followers, [--] engagements
"Area of Shaded Region: Square and Two Semicircles NCERT Class [--] Geometry Abhi Garg Classes Stop confusing composite shapes This is one of the most frequently asked questions on Area of Shaded Regions in Class [--] boards. ❓ The Question: Find the area of the shaded region if ABCD is a square of side [--] cm and APD and BPC are semicircles. 💡 Concept Explained: We use the fundamental principle: Area of Shaded Region = Area of Square - Area of Two Semicircles. Pay close attention to calculating the radius from the side length This is perfect practice for Class [--] Boards geometry. 📍 For focused"
YouTube Link 2026-02-15T15:25Z [---] followers, [---] engagements
"Area of Shaded Region: Square and Two Semicircles NCERT Class [--] Geometry Abhi Garg Classes Stop confusing composite shapes This is one of the most frequently asked questions on Area of Shaded Regions in Class [--] boards. ❓ The Question: Find the area of the shaded region if ABCD is a square of side [--] cm and APD and BPC are semicircles. 💡 Concept Explained: We use the fundamental principle: Area of Shaded Region = Area of Square - Area of Two Semicircles. Pay close attention to calculating the radius from the side length This is perfect practice for Class [--] Boards geometry. 📍 For focused"
YouTube Link 2026-02-15T15:22Z [---] followers, [--] engagements
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